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Course: LSAT > Unit 1
Lesson 5: Analytical Reasoning – Worked examples- Ordering setup | Overview | Rules and deductions
- Ordering setup | Given info–basic 1 | Worked example
- Ordering setup | Given info–basic 2 | Worked example
- Ordering setup | Given info–could be true | Worked example
- Ordering setup | Given info–cannot be true 1 | Worked example
- Ordering setup | Given info–cannot be true 2 | Worked example
- Ordering setup | Given info–must be true | Worked example
- Ordering setup | New info–could be true 1 | Worked example
- Ordering setup | New info–could be true 2 | Worked example
- Ordering setup | New info–could be true 3 | Worked example
- Ordering setup | Completely determines | Worked example
- Ordering setup | New info-must be true | Worked example
- Grouping setup | Overview | Rules and deductions
- Grouping setup | Given info–basic | Worked example
- Grouping setup | Given info–could be true | Worked example
- Grouping setup | Given info–must be false | Worked example
- Grouping setup | Given info–must be true 1 | Worked example
- Grouping setup | Given info–must be true 2 | Worked example
- Grouping setup | New info–could be true 1 | Worked example
- Grouping setup | New info–could be true 2 | Worked example
- Grouping setup | New info–must be true | Worked example
- Grouping setup | "Completely determines" | Worked example
- Mixed setup | Overview | Rules and deductions
- Mixed setup | Given info–basic | Worked example
- Mixed setup | Given info–could be true 1 | Worked example
- Mixed setup | Given info–could be true 2 | Worked example
- Mixed setup | Given info–must be true | Worked example
- Mixed setup | Given info–cannot be true | Worked example
- Mixed setup | New info–could be true | Worked example
- Mixed setup | New info–must be true 1 | Worked example
- Mixed setup | New info–must be true 2 | Worked example
- Mixed setup | Rule substitution | Worked example
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Grouping setup | New info–could be true 1 | Worked example
Watch a demonstration of one way to approach questions that ask you to identify what could be true, given new information on an LSAT analytical reasoning grouping setup. Created by Annie Hollister.
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- at 0.58 how was it determined that each of the colors must appear in one costume?(1 vote)
Video transcript
- [Narrator] This question asks
if only one of the costumes has both yellow and orange
in it, then which one of the following could be true? So we wanna add the new
information that one of the costumes has both yellow
and orange to the set-up we already have, and cross
out choices that could not be true, given this new information. Well, if one of the costumes has both yellow and orange in
it, what else do we know? Rule two and three together
tell us that yellow and indigo are together, so if a costume
has both yellow and orange in it, that costume is
yellow, indigo and orange, so we can add that here. We also figured out from rule
four and the fact that indigo and yellow are a pair,
that red can only be paired with white and orange,
so one of the costumes is red, white and orange. This means that if yellow and orange are together in a costume, two of the costumes are fully determined. Since each of the colors has to appear in at least one costume, the third costume must have green in it somewhere. It can't have red, but we don't
know anything else about it. So let's look at the choices. A, exactly one of the
costumes has yellow in it. Well we haven't learned
anything that tells us that this has to be false, for instance
if this costume that has green in it is green, white
and orange, then exactly one of the costumes
could have yellow in it, so let's leave this aside for now. B, exactly two of the
costumes have green in them. Well, if one of the costumes
has both yellow and orange in it, then the third color
in that costume has to be indigo, because indigo
and yellow are a pair. We know that under any
circumstances, one of the costumes is red, white and orange,
because red can only be paired with white and orange, and
therefore has to be paired with white and orange, so
only one of the costumes can have green in it. Exactly three of the
costumes have white in them. Well, if one of the costumes
has both yellow and orange in it, then the third color in
that costume has to be indigo because indigo and yellow
are paired, so it can't be the case that three of the
costumes have white in them. At least one of the costumes has both indigo and white in it. Well we figured out that
two of the costumes are red, white and orange, and
indigo, yellow and orange, so if one of the costumes has
both indigo and white in it, it must be the third costume. Because each color has
to appear at least once, the third costume has to include green, and that means that if the
third costume also includes indigo, the third color in
that costume has to be yellow because indigo and yellow
are always paired together. That means that the third
costume cannot contain both indigo and white, so none
of the costumes contains indigo and white, so
we can cross that off. At least two of the
costumes have both green and white in them. Well we already figured out
that only one of the costumes has green in it, so we can rule that out. And that leaves the answer is
A, exactly one of the costumes has yellow in it, which is
possible if the third costume is green, white and orange.