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Course: LSAT > Unit 1
Lesson 5: Analytical Reasoning – Worked examples- Ordering setup | Overview | Rules and deductions
- Ordering setup | Given info–basic 1 | Worked example
- Ordering setup | Given info–basic 2 | Worked example
- Ordering setup | Given info–could be true | Worked example
- Ordering setup | Given info–cannot be true 1 | Worked example
- Ordering setup | Given info–cannot be true 2 | Worked example
- Ordering setup | Given info–must be true | Worked example
- Ordering setup | New info–could be true 1 | Worked example
- Ordering setup | New info–could be true 2 | Worked example
- Ordering setup | New info–could be true 3 | Worked example
- Ordering setup | Completely determines | Worked example
- Ordering setup | New info-must be true | Worked example
- Grouping setup | Overview | Rules and deductions
- Grouping setup | Given info–basic | Worked example
- Grouping setup | Given info–could be true | Worked example
- Grouping setup | Given info–must be false | Worked example
- Grouping setup | Given info–must be true 1 | Worked example
- Grouping setup | Given info–must be true 2 | Worked example
- Grouping setup | New info–could be true 1 | Worked example
- Grouping setup | New info–could be true 2 | Worked example
- Grouping setup | New info–must be true | Worked example
- Grouping setup | "Completely determines" | Worked example
- Mixed setup | Overview | Rules and deductions
- Mixed setup | Given info–basic | Worked example
- Mixed setup | Given info–could be true 1 | Worked example
- Mixed setup | Given info–could be true 2 | Worked example
- Mixed setup | Given info–must be true | Worked example
- Mixed setup | Given info–cannot be true | Worked example
- Mixed setup | New info–could be true | Worked example
- Mixed setup | New info–must be true 1 | Worked example
- Mixed setup | New info–must be true 2 | Worked example
- Mixed setup | Rule substitution | Worked example
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Grouping setup | Given info–basic | Worked example
Watch a demonstration of one way to approach a "Given info: basic orientation" question on a grouping setup from the analytical reasoning section of the LSAT. Created by Annie Hollister.
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Hi, please note that in the video, option E is cut off on the bottom so you can't check your work before she explains it.(4 votes)
Could someone please explain choice A. Im confused because the instructor stated that the answer choice had inidigo but no yellow but in the second row of answer choice A yellow is included with inidigo.(2 votes)- Choice (A) violates the rule "Any costume that has indigo must have yellow" because the first of the three costumes listed (green, indigo, and orange) does not have yellow. The fact that the second costume (green, indigo, and yellow) adheres to this rule does not change the fact that the first costume violates it.(4 votes)
- The explanation is so unclear. No two costumes can have the same color combination. Choice A has green, indigo, orange and the second costume is green, indigo, yellow. Those two are obviously two different combinations and it does not violate the rule that says "no two costumes can have the same color combination. However, in the overview, when indigo and yellow are considered a pair, red cannot be paired with yellow. What rule restricts red not to have yellow as part of the color combination? Can someone explain this nonsense?(1 vote)
- Shouldn't A be crossed off for having the same colors in it? After reading the first rule?(1 vote)
Video transcript
- [Instructor] Which one of the following could be the colors of
each of the three costumes? With this type of question, a good approach is to
take each rule in turn and cross off choices
that violate that rule. So let's start with rule one, no two costumes can have
the same color combination. It doesn't look like any of
the choices violate this rule. In each of the choices, the three costumes have three different color combinations, so this doesn't help us
rule out any options. Rule two says any costume that has indigo in it must
also have yellow in it. So let's make sure that
in all of the choices, any costume that has
indigo also has yellow. Well, right away in A we see that one of the costumes here
is green, indigo, and orange, which means that it has
indigo in it but no yellow, so we can rule that out. In the rest of the choices,
it looks like every costume that has indigo in it
also has yellow in it, so the rest of the these
comply with rule two. Rule three says any costume that has yellow in it must
also have indigo in it. So let's make sure that
everything with yellow also has indigo. In B that's fine. In C that's fine. In D that's fine. And in E we have a costume
with green, white, and yellow, so this costume has yellow
in it but no indigo, so we can rule out E. Rule four says if a costume has red in it, then it have neither
indigo nor green in it. In C there's a costume that's
green, orange, and red, so that violates this rule. And in D there's a costume
that's indigo, red, and yellow, so this also violates that rule. This means that the only
choice that works is B where the costumes are
green, indigo, yellow; green, orange, and white;
and orange, red, and white.