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### Course: 8th grade (Eureka Math/EngageNY) > Unit 4

Lesson 4: Topic D: Systems of linear equations and their solutions- Systems of equations: trolls, tolls (1 of 2)
- Systems of equations: trolls, tolls (2 of 2)
- Testing a solution to a system of equations
- Solutions of systems of equations
- Systems of equations with graphing
- Systems of equations with graphing
- Systems of equations with graphing: 5x+3y=7 & 3x-2y=8
- Systems of equations with graphing: y=7/5x-5 & y=3/5x-1
- Systems of equations with graphing: chores
- Systems of equations with graphing
- Systems of equations with elimination: 3t+4g=6 & -6t+g=6
- Systems of equations with elimination
- Systems of equations with elimination: x+2y=6 & 4x-2y=14
- Systems of equations with elimination: -3y+4x=11 & y+2x=13
- Systems of equations with elimination: 2x-y=14 & -6x+3y=-42
- Systems of equations with elimination: 4x-2y=5 & 2x-y=2.5
- Systems of equations with elimination: x-4y=-18 & -x+3y=11
- Systems of equations with elimination
- Systems of equations with elimination: 6x-6y=-24 & -5x-5y=-60
- Systems of equations with elimination challenge
- Systems of equations with substitution: 2y=x+7 & x=y-4
- Systems of equations with substitution
- Systems of equations with substitution: y=4x-17.5 & y+2x=6.5
- Systems of equations with substitution: -3x-4y=-2 & y=2x-5
- Systems of equations with substitution: 9x+3y=15 & y-x=5
- Systems of equations with substitution
- Systems of equations with substitution: y=-5x+8 & 10x+2y=-2
- Systems of equations with substitution: y=-1/4x+100 & y=-1/4x+120
- Systems of equations with elimination: apples and oranges
- Systems of equations with elimination: TV & DVD
- Systems of equations with elimination: King's cupcakes
- Systems of equations with elimination: Sum/difference of numbers
- Systems of equations with elimination: potato chips
- Systems of equations with elimination: coffee and croissants
- Systems of equations with substitution: coins
- Systems of equations with substitution: potato chips
- Systems of equations with substitution: shelves
- Systems of equations word problems
- Age word problem: Imran
- Age word problem: Ben & William
- Age word problem: Arman & Diya
- Age word problems
- Solutions to systems of equations: consistent vs. inconsistent
- Systems of equations number of solutions: fruit prices (1 of 2)
- Systems of equations number of solutions: fruit prices (2 of 2)
- Systems of equations number of solutions: y=3x+1 & 2y+4=6x
- Solutions to systems of equations: dependent vs. independent
- Number of solutions to a system of equations graphically
- Number of solutions to a system of equations graphically
- Forming systems of equations with different numbers of solutions
- Number of solutions to a system of equations algebraically
- Comparing Celsius and Fahrenheit temperature scales
- Converting Fahrenheit to Celsius

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# Systems of equations with substitution: shelves

Sal solves a system of equations to figure out how long a couple of different shelves will be. Created by Sal Khan and Monterey Institute for Technology and Education.

## Want to join the conversation?

- Jenny mixes a 30% saline solution with a 50% saline solution to make 800 milliliters of a 45% saline solution. How many milliliters of each solution does she use?(5 votes)
- By selling 12 dozen pencils, Alice lost an amount equal to the selling price of 6 pencils. Find the lost percent.(3 votes)
- Ok. So how many pencils do you have in total? If a dozen is 12, and you have 12 dozens, you can multiply it out and reach 144. Now she lost a certain percentage of money that is equal to 6 pencils. Now, you just find out how much 6/144 is, but with a denominator of 100. If you simplify this fraction (6/144), you will get 1/24. So, you would end up with 0.04166666 (you get the idea, it's infinite 6's), and you could say that it is approximately 4.16666 %. Hope this helped!(3 votes)

- Is there a quicker way to do this?(4 votes)
- Step 1: Write down what you know:

1. We know there are 2 investments

2. We know that the total dollars invested in those investments = 5,800

3. We know that one investment, represented by the letter x earns 3.5% interest

4. We know that the other investment is represented by the letter y, and earns 5.5% interest

5. We know that they are asking us to solve for the total dollars invested in investment y

Step 2: Come up with equations with the information that was given:

Dollars invested in first investment = x

Dollars invested in second investment = y

Equation 1: x + y = total dollars invested = 5,800

Equation 2: 0.035x + 0.055y = 283,

I find it easier working with whole numbers, so I will multiplying both sides of

equation 2 by 1000 to get 35x + 55y = 283,000

Step 3: Isolate one of the variables, then use substitution to solve:

We are looking for y, so we need to substitute x for y, using the first equation, we get

x = 5800 - y, substituting that value for x into the second equation, we get

35(5800 - y) + 55y = 283,000, or 203,000 -35y + 55y = 283,000, or

20y = 80,000, y = $4000. So, $4000 was invested at 5.5%

and $1800 (5,800 - 4,000) was invested at 3.5%.

4000 * 0.055 + 1800 * 0.035 = 283.(1 vote)

- This is for those of you that need a challenge :D Here is a systems of equations word problem that I found online.

The sum of the digits of a two-digit number is 7. When the digits are reversed, the number is increased by 27. Find the number.(3 votes)- The digits of a two digit number must be integers so this greatly reduces the number of possibilities. First, what pairs add up to 7?

1 + 6

2 + 5

3 + 4

And the reverses of these. Immediately we can see that the number is either 16, 25, or 34, and cannot be 61, 52, or 43 because the question says when the digits are reversed the number INCREASES so the original number must have a smaller tens digit than units digit.

61 is 45 greater than 16.

52 is 27 greater than 25.

So the number is 25.(2 votes)

- a small plane leave san jose airport and flies to los angeles at 240 miles per hour. a jet plane leaves san jose airport 30 minutes later to follow small plane at 360 miles per hour. how long does it take the jet to overtake to the small plane(4 votes)
- I got a different answer being one hour. So let us say that y is the distance from the airport and x the amount of hours so for the small plane the equation would be 240x + 240 * 0.5 = y (i got 0.5 because 30 minutes = 0.5 hours) and the equation for the jet being 360x = y. So then you set them equal so 360x = 240x +240 * 0.5. simplify it 360x = 240x + 120. get x on one side 120x = 120. and get x alone. x=1 so just one hour to pass it.(1 vote)

- why are there no practice problems for the word problem(3 votes)
- You can suggest for Khan Academy to add practice word problems for this topic in the Help Center (You can find it in the blue area at the bottom of this website under "contact").(2 votes)

- help me solve this problem two linear problem 3x+y =2 3x+2y=7(2 votes)
- Joann,

When you have two equations like

3x+y =2 and

3x+2y=7

And you want to use the substitution method, you first need to isolate either variable by itself on one side of one of the equations.

In this case, the easiest way is to isolate the y on the right in the first equation.

3x+y =2

Subtract 3x from both sides.

3x-3x+y = 2-3x

The 3x-3x becomes 0 and disappears

y=2-3x

Now you can use that information and just

substitute (2-3x) for the y in the second equation

3x+2y=7

Substitute (2-3x) for the y

3x + 2(2-3x) = 7

Now you can find the solution for x

Then you can use that answer for x by putting it in either equation for the x and solve that equation for y

Then you can check you answer by putting the answers for both x and y into the other equation and see that it balances correctly.

I hope that helps make it click for you.(3 votes)

- Please break this down for me, I am stuck.

You invest a total of $5800 in two investments earning 3.5% and 5.5% simple interest. Your goal is to have a total annual interest income of $283. Write a system of linear equations that represents this situation where x represents the amount invested in the 3.5% fund and y represents the amount invested in the 5.5% fund. Solve this system of to determine the smallest amout that you can invest at 5.5% in order to meet your objective.(2 votes)- Step 1: Write down what you know:

1. We know there are 2 investments

2. We know that the total dollars invested in those investments = 5,800

3. We know that one investment, represented by the letter x earns 3.5% interest

4. We know that the other investment is represented by the letter y, and earns 5.5% interest

5. We know that they are asking us to solve for the total dollars invested in investment y

Step 2: Come up with equations with the information that was given:

Dollars invested in first investment = x

Dollars invested in second investment = y

Equation 1: x + y = total dollars invested = 5,800

Equation 2: 0.035x + 0.055y = 283,

I find it easier working with whole numbers, so I will multiplying both sides of

equation 2 by 1000 to get 35x + 55y = 283,000

Step 3: Isolate one of the variables, then use substitution to solve:

We are looking for y, so we need to substitute x for y, using the first equation, we get

x = 5800 - y, substituting that value for x into the second equation, we get

35(5800 - y) + 55y = 283,000, or 203,000 -35y + 55y = 283,000, or

20y = 80,000, y = $4000. So, $4000 was invested at 5.5%

and $1800 (5,800 - 4,000) was invested at 3.5%.

4000 * 0.055 + 1800 * 0.035 = 283. It checks.

Hope that helps and good luck with your studies!(3 votes)

- Is there any practice for this topic?(3 votes)
- I asked this question on a diffferent video but I need this question answered as fast as possible!!

"A certain number when added to 36 gives the same result as adding 6 to this number and doubling the result".

Please help me!!(1 vote)- "A certain number..." -> x

"...when added to 36..." -> x + 36

"...gives the same result as..." -> x + 36 =

"...adding 6 to this number..." -> x + 36 = x + 6

"...and doubling the result." -> x + 36 = 2(x + 6)

Then...

x + 36 = 2x + 12

x = 24(2 votes)

## Video transcript

So we have the question, Devon
is going to make 3 shelves for her father. She has a piece of lumber
that is 12 feet long. She wants the top shelf to be
half a foot shorter than the middle shelf. So let me do this in
different colors. She wants the top shelf to be
half a foot shorter than the middle shelf. So I'll just-- let's just read
the whole thing first. And the bottom shelf to be half a foot
shorter than twice the length of the top shelf. Let me do that in a
different color. I'll do that in blue. The bottom shelf to be half a
foot shorter than twice the length of the top shelf. How long will each shelf
be if she uses the entire 12 feet of wood? So let's define some variables
for our different shelves, because that's what we
have to figure out. We have the top shelf,
the middle shelf, and the bottom shelf. So let's say that t is equal to
length of top shelf-- t for top-- of top shelf. Let's make m equal the length
of the middle shelf. m for middle. And then let's make b equal to
the length of the bottom shelf-- b for bottom--
bottom shelf. So let's see what these
different statements tell us. So this first statement, she
says she wants the top shelf-- and I'll do it in that same
color-- she wants the top shelf to be 1/2 a foot shorter
than the middle shelf. So she wants the length of the
top shelf to be-- so this is equal to 1/2 a foot shorter
than the middle shelf. So, if we're doing everything in
feet, it's going to be the length of the middle
shelf in feet minus 1/2, minus 1/2 feet. So that's what that sentence
in orange is telling us. The top shelf needs to be 1/2 a
foot shorter than the length of the middle shelf. Now, what does the next
statement tell us? And the bottom shelf to be-- so
the bottom shelf needs to be equal to 1/2 a foot shorter
than-- so it's 1/2 a foot shorter than twice the length
of the top shelf. So it's 1/2 a foot shorter
than twice the length of the top shelf. These are the two statements
interpreted in equal equation form. The top shelf's length has to be
equal to the middle shelf's length minus 1/2. It's 1/2 foot shorter than
the middle shelf. And the bottom shelf needs to
be 1/2 a foot shorter than twice the length of
the top shelf. And so how do we solve this? Well, you can't just solve
it just with these two constraints, but they gave
us more information. They tell us how long will each
shelf be if she uses the entire 12 feet of wood? So the length of all of
the shelves have to add up to 12 feet. She's using all of it. So t plus m, plus b needs
to be equal to 12 feet. That's the length
of each of them. She's using all 12
feet of the wood. So the lengths have
to add to 12. So what can we do here? Well, we can get everything here
in terms of one variable, maybe we'll do it in terms of
m, and then substitute. So we already have
t in terms of m. We could, everywhere we see
a t, we could substitute with m minus 1/2. But here we have b
in terms of t. So how can we put this
in terms of m? Well, we know that t is
equal to m minus 1/2. So let's take, everywhere we see
a t, let's substitute it with this thing right here. That is what t is equal to. So we can rewrite this blue
equation as, the length of the bottom shelf is 2 times the
length of the top shelf, t, but we know that t is equal
to m minus 1/2. And if we wanted to simplify
that a little bit, this would be that the bottom shelf is
equal to-- let's distribute the 2-- 2 times m is 2m. 2 times negative 1/2
is negative 1. And then minus another 1/2. Or, we could rewrite this as b
is equal to 2 times the middle shelf minus 3/2. Right? 1/2 is 2/2 minus another
1/2 is negative 3/2, just like that. So now we have everything in
terms of m, and we can substitute back here. So the top shelf-- instead of
putting a t there, we could put m minus 1/2. So we put m minus 1/2, plus
the length of the middle shelf, plus the length
of the bottom shelf. Well, we already put
that in terms of m. That's what we just did. This is the length of the bottom
shelf in terms of m. So instead of writing b there,
we could write 2m minus 3/2. Plus 2m minus 3/2, and
that is equal to 12. All we did is substitute
for t. We wrote t in terms of m, and
we wrote b in terms of m. Now let's combine the m terms
and the constant terms. So if we have, we have one m here, we
have another m there, and then we have a 2m there. They're all positive. So 1 plus 1, plus 2 is 4m. So we have 4m. And then what do our constant
terms tell us? We have a negative 1/2, and then
we have a negative 3/2. So negative 1/2 minus 3/2,
that is negative 4/2 or negative 2. So we have 4m minus 2. And, of course, we still
have that equals 12. Now, we want to isolate just the
m variable on one side of the equation. So let's add 2 to both sides
to get rid of this 2 on the left-hand side. So if we add 2 to both sides
of this equation, the left-hand side, we're just
left with 4m-- these guys cancel out-- is equal to 14. Now, divide both sides by 4, we
get m is equal to 14 over 4, or we could call that 7/2
feet, because we're doing everything in feet. So we solved for m, but
now we still have to solve for t and b. So let's do that. Let's solve for t. t is equal to m minus 1/2. So it's equal to-- our m is 7/2
minus 1/2, which is equal to 6/2, or 3 feet. Everything is in feet,
so that's how we know it's feet there. So that's the top
shelf is 3 feet. The middle shelf is 7/2 feet,
which is the same thing as 3 and 1/2 feet. And then the bottom shelf
is 2 times the top shelf, minus 1/2. So what's that going
to be equal to? That's going to be equal to 2
times 3 feet-- that's what the length of the top shelf is--
minus 1/2, which is equal to 6 minus 1/2, or 5 and 1/2 feet. And we're done. And you can verify that these
definitely do add up to 12. 5 and 1/2 plus 3 and 1/2 is 9,
plus 3 is 12 feet, and it meets all of the other
constraints. The top shelf is 1/2 a foot
shorter than the middle shelf, and the bottom shelf is 1/2
a foot shorter than 2 times the top shelf. And we are done. We know the lengths of
the shelves that Devon needs to make.