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# Finding torque for angled forces

David explains how to determine the torque exerted by a non-perpendicular force. Created by David SantoPietro.

## Want to join the conversation?

• Why does the perpendicular component only exert force? What about the parallel component? Shouldn't it be exerting some type of force too?
• The parallel component does exert force, but it does not exert torque.

Only perpendicular components exert torque.
• What is the actual answer, is it 17Nm?
• Shouldn't the answer by 17.3*4=69 Nm? because you need to multiply by the distance also?
(1 vote)
• The force will be at an angle theta only for that one moment. Assuming the direction of the force doesn't change, the angle theta will change as the thing turns about the axis and because of that the force will change too. So how would you solve that kind of problem? Integral calculus?
• 20sin (120) or 20sin(60) = 17.321 Nm. That's at least what my Casio says. Be sure that if you are working out the answer using a calculator that is in degree mode and not radians. I nearly posted the wrong answer and a question, which upon reflection would be pretty embarrassing. : \
• Why do people use Nm as the units for torque, while a newton meter is equal to a Joule? Wouldn't it be much easier to use Joules?
• While the units Newton Meter and Joule reduce to the same base units they are not really the same thing. Torque is not energy, if you look at the vector equations for work and torque you will see that the equation for work is the dot product of force and distance vectors resulting in a scalar value where as torque is the cross product of distance and force resulting in a vector.

Using joules for torque would confuse the difference between the scalar energy and vector torque.
• At - why is it important that we consider "r" a vector? It seems like only the distance is important, rather than also considering the direction.
• If you have to combine multiple torques, you are going to need to have the direction of each one.
• So you can use any angle? What if that angle was 30 degrees instead of 60. sin(150) and sin(30) are not the same so which one would you use? Thanks so much
• Both sin 150° and sin30° give same answer. Make sure u are using the degree mode
• what is difference b/w torque and moment
briefly explain it
(1 vote)
• A torque is one particular type of moment, moments are much more general. That being said, they are used almost interchangeably at this level, and from what I've seen so far in this course.