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## Physics library

### Course: Physics library > Unit 3

Lesson 1: Newton's laws of motion- Newton's first law of motion introduction
- Newton's first law of motion
- Applying Newton's first law of motion
- What is Newton's first law?
- Newton's first law
- Newton's second law of motion
- More on Newton's second law
- What is Newton's second law?
- Newton's third law of motion
- More on Newton's third law
- What is Newton's third law?
- Newton's third law of motion
- All of Newton's laws of motion

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# What is Newton's second law?

Review your understanding of Newton's second law in this free article aligned to NGSS standards.

## What is Newton's second Law?

In the world of introductory physics, Newton's second law is one of the most important laws you'll learn. It's used in almost every chapter of every physics textbook, so it's important to master this law as soon as possible.

We know objects can only accelerate if there are forces on the object. Newton's second law tells us exactly how much an object will accelerate for a given net force.

To be clear, a is the acceleration of the object, \Sigma, F is the net force on the object, and m is the mass of the object.

Looking at the form of Newton's second law shown above, we see that the acceleration is proportional to the net force, \Sigma, F, and is inversely proportional to the mass, m. In other words, if the net force were doubled, the acceleration of the object would be twice as large. Similarly, if the mass of the object were doubled, its acceleration would be half as large.

## What does net force mean?

A force is a push or a pull, and the net force \Sigma, F is the total force—or sum of the forces—exerted on an object. Adding vectors is a little different from adding regular numbers. When adding vectors, we must take their direction into account. The net force is the

*vector sum*of all the forces exerted on an object.For instance, consider the two forces of magnitude 30 N and 20 N that are exerted to the right and left respectively on the sheep shown above. If we assume rightward is the positive direction, the net force on the sheep can be found by

If there were more horizontal forces, we could find the net force by adding up all the forces to the right and subtracting all the forces to the left.

Since force is a vector, we can write Newton's second law as a, with, vector, on top, equals, start fraction, \Sigma, F, with, vector, on top, divided by, m, end fraction. This shows that the direction of the total acceleration vector points in the same direction as the net force vector. In other words, if the net force \Sigma, F points right, the acceleration a must point right.

## How do we use Newton's second law?

If the problem you're analyzing has many forces in many directions, it's often easier to analyze each direction independently.

In other words, for the horizontal direction we can write

This shows that the acceleration a, start subscript, x, end subscript in the horizontal direction is equal to the net force in the horizontal direction, \Sigma, F, start subscript, x, end subscript, divided by the mass.

Similarly, for the vertical direction we can write

This shows that the acceleration a, start subscript, y, end subscript in the vertical direction is equal to the net force in the vertical direction, \Sigma, F, start subscript, y, end subscript, divided by the mass.

When using these equations we must be careful to only plug

*horizontal*forces into the*horizontal*form of Newton's second law and to plug*vertical*forces into the*vertical*form of Newton's second law. We do this because horizontal forces only affect the horizontal acceleration and vertical forces only affect the vertical acceleration. For instance, consider a hen of mass m that has forces of magnitude start color #e84d39, F, start subscript, 1, end subscript, end color #e84d39, start color #11accd, F, start subscript, 2, end subscript, end color #11accd, start color #1fab54, F, start subscript, 3, end subscript, end color #1fab54, and F, start subscript, 4, end subscript exerted on it in the directions shown below.The forces start color #e84d39, F, start subscript, 1, end subscript, end color #e84d39 and start color #1fab54, F, start subscript, 3, end subscript, end color #1fab54 affect the horizontal acceleration since they lie along the horizontal direction. Applying Newton's second law to the horizontal direction and assuming rightward is positive, we get

Similarly, the forces start color #11accd, F, start subscript, 2, end subscript, end color #11accd and F, start subscript, 4, end subscript affect the vertical acceleration since they lie along the vertical direction. Applying Newton's second law to the vertical direction and assuming upward is positive, we get

**Warning:**A common mistake people make is to plug a vertical force into a horizontal equation, or vice versa.

## What do we do when a force is directed at an angle?

When forces are directed in diagonal directions, we can still analyze the forces in each direction independently. But, diagonal forces will contribute to the acceleration in both the vertical and horizontal directions.

For instance, let's say the force start color #1fab54, F, start subscript, 3, end subscript, end color #1fab54 on the hen is now directed at an angle theta as seen below.

The force start color #1fab54, F, start subscript, 3, end subscript, end color #1fab54 will affect both the horizontal and vertical accelerations, but only the horizontal component of start color #1fab54, F, start subscript, 3, end subscript, end color #1fab54 will affect horizontal acceleration; only the vertical component of start color #1fab54, F, start subscript, 3, end subscript, end color #1fab54 will affect the vertical acceleration. So we'll break the force start color #1fab54, F, start subscript, 3, end subscript, end color #1fab54 into horizontal and vertical components as seen below.

Now we see that the force start color #1fab54, F, start subscript, 3, end subscript, end color #1fab54 can be viewed as consisting of a horizontal force start color #1fab54, F, start subscript, 3, x, end subscript, end color #1fab54 and a vertical force start color #1fab54, F, start subscript, 3, y, end subscript, end color #1fab54.

Using trigonometry, we can find the magnitude of the horizontal component with start color #1fab54, F, start subscript, 3, x, end subscript, end color #1fab54, equals, start color #1fab54, F, start subscript, 3, end subscript, end color #1fab54, start text, c, o, s, end text, theta. Similarly, we can find the magnitude of the vertical component with start color #1fab54, F, start subscript, 3, y, end subscript, end color #1fab54, equals, start color #1fab54, F, start subscript, 3, end subscript, end color #1fab54, start text, s, i, n, end text, theta.

Now we can proceed as usual by plugging all horizontally directed forces into the horizontal form of Newton's second law.

Similarly, we can plug all vertically directed forces into the vertical form of Newton's second law.

## What do solved examples involving Newton's second law look like?

### Example 1: Newton the turtle

A 1.2 kg turtle named Newton has four forces exerted on it as shown in the diagram below.

**What is the horizontal acceleration of Newton the turtle?**

**What is the vertical acceleration of Newton the turtle?**

To find the

*horizontal acceleration*we'll use Newton's second law for the horizontal direction.To find the

*vertical acceleration*, we'll use Newton's second law for the vertical direction.### Example 2: String cheese

A wedge of cheese is suspended at rest by two strings which exert forces of magnitude F, start subscript, 1, end subscript and start color #e84d39, F, start subscript, 2, end subscript, end color #e84d39, as seen below. There is also a downward force of gravity on the cheese of magnitude start color #1fab54, 20, start text, space, N, end text, end color #1fab54.

**What is the magnitude of the force F, start subscript, 1, end subscript?**

**What is the magnitude of the force start color #e84d39, F, start subscript, 2, end subscript, end color #e84d39?**

We'll start by either using the horizontal or vertical version of Newton's second law. We don't know the value of any of the horizontal forces, but we do know the magnitude of one of the vertical forces—start color #1fab54, 20, start text, space, N, end text, end color #1fab54. Since we know more information about the vertical direction, we'll analyze that direction first.

Now to find the force start color #e84d39, F, start subscript, 2, end subscript, end color #e84d39, we'll use Newton's second law for the horizontal direction.

## Want to join the conversation?

- I don't understand how an object with an acceleration of 0 could have a Force. If F=ma and a=0 [so F=m(0)] then why doesn't the Force end up as 0?(10 votes)
- Yes, the force would be zero, but that is the
**Net Force**. So the forces acting on the object can cancel each other out and the object would have 0 acceleration. Using the example of hanging cheese, the vertical forces cancel each other out, as sin60 times 23 is approximately equal to 20, so the net force would end up zero, but there are still these forces acting on it.(10 votes)

- For Newton's second law about acceleration, isn't their another way to calculate it by dividing the change in velocity by time?(8 votes)
- This means that p(or the
**Momentum**) = F⋅∆t(0 votes)

- In Example 2, how does 20 get in the numerator and how did you get it to be divided by sin60?(7 votes)
- 1. "cheese is suspended at rest" means a_total=0 and F_total=0, which means all components of F_y as well as F_x must cancel each other, respectively.

F_y_total = F_y_down + F_y_up = 0N

2. then 20N downward must be offset by 20N upward

F_y_down + F_y_up = -20N + 20N = 0N

F_y_up = 20N

3. and 20N upward must be applied by y component of the diagonal Force as it is the only to offset the downward Force.

F_y_up = 20N = F_y_dia*sin60

F_y_dia = 20N/sin60 = 20N/~0.87 = ~23

(~ means around, you can use a calculator if you want)

in fact, i prefer this path to that starting from Newton's second law like above cause it's faster and irrelevant to mass (in fact, they are same but i simply don't follow the strict steps from a=net_F/m to the starting point of mine)(1 vote)

- When do i know when to use cos and sin?(4 votes)
- There is a common saying in math called Soh Cah Toa. For Sine, Cosine, and Tangent. If the problem gives you the opposite and hypotenuse sides then you will you Sine, because sine is Soh which contains o and h for opposite and hypotenuse. You will use cosine is you are given adjacent and hypotenuse.(5 votes)

- Hey guys! My question is in reference to the second example and has to do with direction. We typically assign the left/down as negative and up/right as positive. Is it because the question is asking for the magnitude that the direction of the force not important? Clearly, F1 is pointing up and to the right, so I can see why that vector is positive, but F2 is pointing left, yet the magnitude was still positive. Why?(4 votes)
- The problem only asks for magnitude. Magnitude refers to a size or quantity ( disregards direction), it is always positive.(4 votes)

- In example 1, the tan = -9/3.3=2.7 why is positive not negative . is tan always(+), also the theta was positive it should be negative ! please explain this ?(2 votes)
- Well, you missed something. The numbers were both between
**modulus**sign, which means that we are only going to work with the**positive**value.(5 votes)

- i need to know about newton's second law on variable mass systems.. in which playlist on khan academy i can find this?(1 vote)
- All of the videos on Newton's second law is in Forces and Newton's laws of motion(7 votes)

- In example 1 (newton the turtle) why is there tanθ = absolute values of acceleration vector a_y / a_x. In physics can't you have negative angles?(2 votes)
- I'm not sure why they did that but maybe for simplicity, although they added a line
**The total acceleration vector points right and down**it's says everything about the direction, there is no need to show that by using a negative sign too. This would've been counted as a repetitive error.

You can have negative angles in physics though saying the direction of something is downward is the same as putting a negative sign followed by the**magnitude or absolute value**.(3 votes)

- I need to know how to calculate acceleration with cooficient and friction I need to know the laws of cooficient(3 votes)
- so sin cos and tan do not require a right triangle? you just use the angle in which it is connected to?(3 votes)
- Well, when you break down a vector into it's horizontal and vertical components they automatically or should I say always take the shape of a right triangle.
*But yeah there are other trig identities which can be used to solve for any angle triangle*.(1 vote)