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Current time:0:00Total duration:5:45

We're asked to subtract all
of this craziness over here. And it looks daunting. But if we really just
focus, it actually should be pretty straightforward
to subtract and simplify this thing. Because right from the get-go,
I have 4 times the fourth root of 81x to the fifth. And from that, I
want to subtract 2 times the fourth root
of 81x to the fifth. And so you really can just say,
look, I have four of something. And then the something
I'll just circle in yellow. I have four of this--
it could be lemons. I have four of
these things, and I want to subtract
two of these things. These are the exact same things. They're the fourth root
of 81x to the fifth. So if I have four lemons and
I want to subtract two lemons, I'm going to have
two lemons left over. Or if I have four of this
thing, and I take away two of this thing,
I'm going to have two of these things left over. So these terms right over
here simplify to 2 times the fourth root of
81x to the fifth. And I got this 2 just by
subtracting the coefficients. Four of something
minus two of something is equal to two
of that something. And then that, of
course, we still have this minus the regular
principal square root of x to the third. Now I want to try to
simplify what's inside of these under the radical
sign so that we can, in this example, actually
take the fourth root, and over here actually take,
maybe, a principal square root. So first of all, let's
see if 81 is something to the fourth power,
or at least could be factored into
something that is a something to the fourth power. So 81, if we do prime
factorization, is 3 times 27. 27 is 3 times 9. And 9 is 3 times 3. So 81 is exactly 3
times 3 times 3 times 3. So 81 actually is 3 to
the fourth power, which is convenient
because we're going to be taking the
fourth root of that. And then x to the fifth
we can write as a product. Let me write it over here
so it doesn't get messy. So I'm going to write what's
under the radical as 3 to the fourth power times x
to the fourth power times x. x to the fourth times x
is x to the fifth power. And I'm taking the fourth
root of all of this. And taking the fourth root
of all of this-- that's the same thing as taking
the fourth root of this, as taking the
fourth root of this. And I'm going to
want to skip steps. So I'm taking the fourth root
of all of it right over there. And of course, I
have a 2 out front. And then x to the third could
be written as x squared times x. So it's minus the
principal square root of x squared times x. And I broke it up like this
because this right over here is a perfect square. Now, how can we simplify
this a little bit? And you're probably getting
used to the pattern. This is the same thing as the
fourth root of 3 to the fourth, times the fourth root
of x to the fourth, times the fourth root of x. So let's just skip
straight to that. So what is the fourth root? I could write it-- let
me write it explicitly, although you wouldn't have
to necessarily do this. This is the same thing as the
fourth root of 3 to the fourth, times the fourth root
of x to the fourth, times the fourth root of x. And 2 is being multiplied
times all of that. And then this over here is
minus the principal square root of x squared, times the
principal square root of x. And so if we try to
simplify it, the fourth root of 3 to the fourth
power is just 3. So we get a 3 there. The fourth root of x
to the fourth power is just going to be x. Actually, I just
reminded myself, we have to be careful there. It is not just x, because
what if x is negative? If x is negative, then
x to the fourth power is going to be a positive value. And when you take the
fourth-- remember, this is the fourth
principal root-- you're going to get the
positive version of x. Or really, you're going to
get the absolute value of x. So here, you're
going to be getting the absolute value of x. Although, well, you
could make an argument that x needs to be positive
if this thing is going to be well-defined
in the real numbers, because then what's under the
radical has to be positive. But let's just go with
this for right now. And then we have the
fourth root of x. And then over here, the
principal square root of x squared, by
the same logic, is going to be the
absolute value of x. And then this is just the
principal square root of x. So let's multiply
everything out. We have 2 times 3 times
the absolute value of x. So 2 times 3 is 6,
times the absolute value of x, times the principal
fourth root of x, I should say, minus we took out the
absolute value of x, times the principal root of x. And we can't do any
more subtracting. Just because you have to
realize this is a fourth root. This is a regular square
root, principal square root. If these were the
same root, then maybe we could simplify this
a little bit more. And so then we are all done. And we have fully simplified it. And if you make the
assumption that this is defined for real numbers. So that the domain
over here, what has to be under these
radicals, has to be positive, actually, in every
one of these cases. And if they need to
be positive, we're not going to be dealing
with imaginary numbers. All of these need
to be positive. Their domains are x has to be
greater than or equal to 0, then you could assume that
the absolute value of x is the same as x. But I'll just stick
it right here. If you restrict the
domain, you could get rid of the
absolute value signs.