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## Algebra (all content)

### Course: Algebra (all content)ย >ย Unit 11

Lesson 8: Radicals (miscellaneous videos)- Simplifying square-root expressions: no variables
- Simplifying square roots of fractions
- Simplifying rational exponent expressions: mixed exponents and radicals
- Simplifying square-root expressions: no variables (advanced)
- Intro to rationalizing the denominator
- Worked example: rationalizing the denominator
- Simplifying radical expressions (addition)
- Simplifying radical expressions (subtraction)
- Simplifying radical expressions: two variables
- Simplifying radical expressions: three variables
- Simplifying hairy expression with fractional exponents

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# Simplifying hairy expression with fractional exponents

Sal simplifies hairy expressions with rational exponents. For example, he simplifies (125^-โ
*125^โ
)/(5^½) as 5.

## Want to join the conversation?

- Can someone help me? How did (3w^2)^-2/3 * (3w^2)^-5/6 turned into (3w^2)^-3/2??(9 votes)
- When multiplying, exponents get added. For example:
`X^2 * X^3 = X^5`

.

Your problem is very similar, but we have to add fractions. So, we need a common denominator (LCD = 6).

Add the exponent:`-2/3 * 2/2 - 5/6 = -4/6 - 5/6 = -9/6`

Then reduce the fraction:`-9/6 = -3/2`

So that is how`(3w^ 2)^-2/3 * (3w^2)^-5/6`

became`(3w^2)^-3/2`

Hope this helps.(12 votes)

- At6:05, shouldn't the w in the answer be in the denominator? making the answer:

1/(8w^15/2)

but then you'd have to separate the 15/2 to get it out of the denominator?(3 votes)- i personally don't think you can simplify them that way,and you need to have a common denominator,they and all numbers are basically having 1 as a denominator and are fractions of 1.. it can't go the other way around without changing the expression. but it can work since it's multiplication(2 votes)

- why can't u cancel 1/2 by 1/2 if its in fractions .(2 votes)
- The 1/2's are exponents, not base numbers. Division divides bases to cancel things out. We don't cancel out exponents and leave the bases.

Also, notice the bases of the exponents are different.

If the problem was 5^(1/2)/5^(1/2), then the bases match and the exponents match so the numbers are equal and you can divide them and get 1. But the problem in the video is 125^(1/2)/5^(1/2). These are not the same number. So, you need to use properties of exponents to convert to a common base. Or, as Sal shows in the video, we can rewrite the problem has one fraction raised to the common exponent. This then lets him reduce the fraction.

Hope this helps.(4 votes)

- At6:55pm How would i simplify sqrt(n)/sqrt(n+1) ? (This is just part of a problem that has to do with power series..)(3 votes)
- At5:38, why is 4^(-3/2) equal to 1/8?(2 votes)
- ok, so first thing, it's basically 4^3 * 4^1/2(or radical of 4). 4 at the third power is 64, all that is a radical,therefore radical of 64 is 8(3 votes)

- hi how are you guys doing(2 votes)
- None of these videos are helping me. I am doing a math book that gave me a question like this one:

* (0.3x^-1)^3 (3xy^-2)^2 *

Somehow the answer is**0.243/xy^4**

These question make no sense to me and there is nothing on Khan that explains it (or if there is, I haven't found it). If you have anything to help me, please do!(2 votes) - If a and b are positive constants,simplify (abโab)/(โ(a^4 ) โ(b^3 )).(2 votes)
- can you guys make a video just explaining what the number outside the radical means? Like 4โ6ยฒ(1 vote)
- 4x means 4 times x

4โ6ยฒ means 4 times โ6ยฒ

If the 4 is on the arm of the radical, then you have 4th root of 6ยฒ.

Hope this helps.(2 votes)

- Could you rationalize one over the cube root of two?

The answer given is the cube root of four over two. I don't understand how this answer was derived.

Thank you for your time.(1 vote)- The goal of rationalizing the denominator is to eliminate the radicel. To eliminate a cube root, you need a perfect cube inside the radical (something cubed).

You are starting with cuberoot(2). The 2 has an exponent of 1. To create a perfect cube, you need to create 2^3 = 8 inside the radical.

Thus we multiply: 1/cubert(2) * cubert(2^2)/cubert(2^2)

= cubert(2^2)/cubert(2^3)

= cubert(4)/2

Hope this helps.(2 votes)

## Video transcript

- [Voiceover] So let's get some practice simplifying hairy expressions
that have exponents in them. And so we have a hairy
expression right over here and I encourage you to pause the video and see if you can rewrite
this in a simpler way. All right, let's work
through this together and the first thing that jumps out at me is the numerator here. I have the number 125
raised to the 1/8 power times the same number, the same base, 125, raised to the 5/8 power. So I can rewrite this numerator. I can rewrite this
numerator using what I know of exponent properties as being equal to 125 to the sum of these two exponents. To the negative 1/8 power plus 5/8 power. All of that is going to be
over the existing denominator we have, which is five to the 1/2. All of that is going to be
over five to the 1/2 power. So, these are equivalent. Notice, all I did is
I added the exponents, these two exponents
because I had the same base and we were taking the
product of both of these 125 to the negative
1/8 and 125 to the 5/8. And so negative 1/8 plus 5/8, well that is 1/2. So, this is, this right over here is, 1/2. So, this is 125 to the
1/2, over five to the 1/2. Well, that's going to be the same thing. This is going to be equivalent to 125 over five, over five, to the 1/2 power. To the 1/2 power. If I raise 125 to the 1/2 and I'm dividing by five to the 1/2, that's the same thing as
doing the division first and then raising that to the 1/2 power. Well, what's 125 divided by five? Well, that's just 25. Now what's 25 to the 1/2? Well, that's the same thing
as the principal square root of 25, which is equal to five. And we're all done, that
simplified quite nicely. Let's do another one of these. And this one is a little more interesting, 'cause we are starting
to involve a variable, we have the variable w, but it's really going to be
somewhat the same process. And here the thing that jumps
out at me is the denominator. I have the same base, 3w-squared. 3w-squared raised to
one power, one exponent, times the same base, 3w-squared,
raised to another power. So, this is going to be equal to, this is going to be equal to our numerator we can just rewrite it 12w to the seventh power over negative 3/2 over our denominator we
can write as this base, 3w-squared, and we can add these two exponents. So, we could add negative
2/3 to negative 5/6. Negative 2/3 to negative 5/6. Well, what is that going to be? So, let's see, if I do negative, negative 2/3 is the same
thing as negative 4/6, minus 5/6, which is equal to negative 9/6, which is equal to negative 3/2. So, this right over here is
the same thing as negative 3/2. Let me just write that. Negative 3/2 power. Negative 2/3 plus negative
5/6 is negative 3/2. Now, what's interesting is I
have a negative 3/2 up here and I have a negative 3/2 over here, so, we can do the same thing
we did in the last problem. This could simplify to 12w, 12w to the seventh power, over 3w-squared. 3w-squared. All of that, all of that to the, all of that to the negative 3/2 power. Notice what we did here. I had something to the negative 3/2 divided by something
else to the negative 3/2. Well, that's the same thing
as doing the division first and then raising that
quotient to the negative 3/2. And what's nice about this, this is pretty
straightforward to simplify. 12 divided by three is four, and w to the seventh divided by w-squared, well, we could divide both by w-squared or you could say this is the same thing as w to the seven-minus-two power. So this is going to be
w to the fifth power. W to the fifth power. And so it all simplified to 4w to the fifth power to the negative 3/2. To the negative 3/2. Now, if we want to, this
is already pretty simple and at some point it becomes somewhat someone's opinion on which is expression is simpler than another,
and it might depend on what you're using the expression for, but one could argue that
you could keep trying to simplify this, this
is the same thing as, this is the same thing as
four to the negative 3/2. To the negative 3/2. Times w to the fifth to the negative 3/2. And once again this is
just straight out of our exponent properties. Now, four to the negative 3/2, let's just think about that. Four to the negative 3/2. We're using a different color
just as a bit of an aside. So, four to the negative 3/2 is equal to, that's the same thing as
one over four to the 3/2, and, let's see. The square root of four is
two and then we raise that to the third power, it's gonna be eight. So, this is equal to 1/8. So, that's equal to
1/8, and so all of this is going to be equal to 1/8. And then w to the fifth, and then that to the negative 3/2, we can
multiply these exponents. That's going to be w to the
five times negative 3/2. Well, it's gonna be the
negative 15/2 power. So, I don't know which one
you would say is simpler. This one over here or this one over here but they are equivalent and
they both are a lot simpler than where we started.