Digital SAT Math
Systems of linear equations word problems — Basic example
Watch Sal work through a basic Systems of linear equations word problem.
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- hi, wont it be much easier if you just said:
Hazel amount of keys is X, Leo has 4 more keys, means X+4
and the both combined = 18:
2X = 18-4
and that's it.(71 votes)
- Bingo. That is also very quick 😉(4 votes)
- you could just do 18-4= 14/2=7(54 votes)
- i get how this works but, it's not something that comes to my mind. i've been thinking so hard why i would even think of doing 18-4 lol, like i get it but it's not intuitive and i'd not think of it in a problem...(0 votes)
- Do this:
divide 4 by 2, you get 2. (4 is the difference between the two values)
now add 2 to one side, and subtract 2 from the other.
Some of you guys will overthink something as simple as this, read the problem carefully and evaluate what you have learned one by one to successfully get the answer.
Please understand that I'm using the equal signs in a means to separate the two numbers, it holds no weight in this problem.
Good luck in the future!
-Sincerely from the man who will probably score a 600 on tomorrow's SAT.(11 votes)
- if L + H=18 take away 4 you get 14 leo=7 Hazel=7 then add the four back to Leo so Leo=11 Hazel=7(7 votes)
- what are equations to be precise?(5 votes)
- You mean the definition of equations?
"In mathematics, an equation is a statement that asserts the equality of two expressions."
https://en.wikipedia.org/wiki/Equation (link goes off-KA)(4 votes)
- I did this:
L > H
L := H + 4 (L is bigger by H 4 more)
L + H = 18 total keys
(H+4) + H = 18
2H + 4 = 18(3 votes)
- cant you just do 18 minus 4 for this one?(3 votes)
- you'll have to divide 18 by 2 first, because 18 is the total keys.
so hazel and leo both get 9 keys each, but you want to add 4 to Leo's keys, because he has 4 extra. then you minus 4 from Hazel's keys.(1 vote)
- The difference between in cost between a larger bag and a small bag of chips was $1.48. We bought 6 large bags and 4 small bags and spent $33.88. What was the cost of a small bag?(1 vote)
- Let's say the smaller bag's cost is
And the larger bag's cost is
s + 1.48(because the difference is 1.48
6 large bags cost (6 times the price): 6(s + 1.48)
and 4 small bags cost (4 times the price): 4s
The sum of both costs is 33.88
Do you think you can continue the solution from where I left off?(2 votes)
- Is it okay to use the equation 18=x+(x+4) ? I still got Hazel has 7 and Leo has 11.(1 vote)
- [Instructor] We are told that Hazel and Leo are comparing the number of keys on their keychains. If Leo has four more keys on his keychain than Hazel does on hers and the two of them have 18 keys combined, how many keys does Hazel have on her keychain? So pause this video and see if you can figure that out. Okay now let's do it together. So there's two things that we don't know here. We don't know how many keys Hazel has on her keychain, and that's what they're asking us for, but we also don't know how many keys Leo has on his keychain. And they give us two pieces of information, Leo has four more keys on his keychain than Hazel, and that the two of them have 18 keys combined. So it's feeling like we can set up two equations with two unknowns. If we let L be equal to the number of keys Leo has, keys, I'll just say for Leo, and then H equaled the number of keys for Hazel, and obviously if you were doing this on a test, like the SAT, you wouldn't have to write all this out, you would trying to be getting to the solution, but I'm trying to explain it out for you, so I will do that. And so let's see how we can set up these two constraints that they gave us as equations. So it says if Leo has four more keys on his keychain than Hazel does. So how can we write that mathematically? So Leo has four more keys on his keychain than Hazel, so we could write that Leo is equal to, the number of keys that Leo has is four more than the number Hazel has, so it's Hazel plus four. So we could write it like that, we could also write it that the difference between the number of keys Leo has and the number of keys Hazel has is four, so another alternative, we could have written it like this, Leo minus Hazel is equal to four, and these are algebraically equivalent, it doesn't take much manipulation to go from one to the other. But that's ways that we can mathematically write that first sentence. And now what about that second one? And the two of them have 18 keys combined. Well that just means that L plus H is equal to 18. So we could just write it that way L plus H is equal to 18. I could write it like that again, L plus H is equal to 18, and obviously there's other ways that you could mathematically write this or that would be equivalent to this. But in either case now, we have two equations with two unknowns, and there's two ways that we could go about approaching them. When I look at this version, these two, this system of equations right over here on the left, where I've already solved for L, to me this feels like substitution might be really valuable. Because I have an L here, and we know that L is equal to H plus four, so if I substitute H plus four in for L, then I have one equation with one unknown, if L is equal to H plus four, I get H plus four plus H plus H is equal to 18. And then if I add the Hs I get two H plus four is equal to 18, and let me scroll down a little bit, and then if I subtract four from both sides, and remember I'm doing that to isolate the Hs on one side of the equation, well then I'm going to get two H is equal to 14, and then dividing both sides by two gives me H is equal to seven. And we could then use that information to say okay, L is equal to H plus four, so it's seven plus four is equal to 11, but they're not even asking us for the number of keys Leo has, they're just asking us for the number of keys Hazel has on her keychain, and we just figured that out, Hazel has seven keys. Now, we could go to this other system, and we could have solved this one as well, and here, it feels like elimination would be the more natural method. The reason why it jumps out at me that elimination would be the natural method, we have a negative H here and we have a positive H there. Now one issue to think about, and there's many ways to solve these, is if we just add the left hand sides of this equation and add the right hand sides of this equation, then we're gonna get an equation in terms of L, because the Hs will cancel out. So then we would solve for L and use one of these equations to figure out H. Another way you could do it is, you could multiply one of these equations by a negative one on both sides, and then when you do the elimination, it would eliminate the L immediately. And so let's try it out that way. So let's multiply this top equation by negative one on both sides. So negative one times L is negative L, negative one times a negative H is positive H, and then this would become a negative four. And now when we add the left hand sides, negative L plus L cancels out, H plus H is two H, and that's going to be equal to negative four plus 18, which is 14, and then divide both sides by two, and we get once again, H is equal to seven. You could have very easily done it the other way, you could have said L minus H is equal to four, and that L plus H is equal to 18, and then immediately just add the two sides of the equation. On the left hand side those would cancel out, you would get two L is equal to 22, divide both sides by two, you would have gotten L is equal to 11. But remember, they don't ask us about Leo, they're asking us about Hazel. So then we would have to substitute that back in to one of these equations to figure out that H is equal to seven.