where did the 1500 come from?

It is most likely the average expected loss of crops in kg when harvesting.

Could someone please explain where 6750a came from in Problem One? How was that number found?

The problem gave you: M(C(a))=6750a−1400 This was created by combining the 2 functions C(a) and M(c) by making C(a) as the input to M(c). Here's how that was done... We were also given: C(a)=7500a−1500 M(c) = 0.9c - 50 Insert C(a) as the input into M(c) and here's what M(C(a)) looks like before simplifying: M(C(a))=0.9(7500a−1500)−50 After you simplify, you get M(C(a)) = 6750a−1400 Hope this helps.

can i get some help with this its kinda getting confusing?

How to find if a composite function is valid or not? How to find its range and domain?

How would you find the value of the function if like you had f(g(-1)) how would you put that into in equation to solve?

Since this is currently real world problems, having a negative amount of land is impossible. You would solve it the same way though such as the potato farmer problem by solving P of -1, or substituting it at the end.

In defining composite functions paragraph 3 it says (M*C)(a) = M(C(a)). Isn't that just multiplying functions? If it says (M*C)(a) why can't I just multiply the two functions?

Same answer as your other question. Composite function uses an open circle/dot, not a solid dot like multiplication. Composite: (M o C)(a) Multiplication: (M * C)(a) or (M • C)(a)

How do you find the domain of a composite function?

The domain of a composite function f(g(x)) is all x in the domain of g such that g(x) is in the domain of f. Let's break this down. First off, the x has to be in the domain of g; if g(x) were say 1/x, then x = 0 could not be in the composite domain. Second of all, even if g(x) is defined, it has to be in the domain of f. Say f(x) equals 1 / (x - 1). Then if you choose an x such that g(x) = 1, making f(g(x)) = 1 / 0, that x cannot be in the domain of the composite function. Hope that I helped.

Problem 1 Shouldn't you solve for C(1.5), then input that value into M(C(a)) rather than just use M(1.5)?? For example, here's my work: 1.5 acres C(1.5) = 7500(1.5) - 1500 11250-1500 = 9750 M(9750) = 6750(9750) - 1400 65812500-1400 = 65811100 I realize that the solution I came up with is unrealistic, but my method of solving seems to me to follow the method taught. So, my question is: why don't you solve it the way I did?

Your method would work if you used M(c) = 0.9c - 50 You used M(c(a)), which already has both functions combined into one. So, you basically applied function C(a) twice. Hope this helps.

What do I do if I have to find f(x)h(x)?

Multiply the two functions. so say f(x) = 5x and g(x) = 3x^2 then f(x)g(x) = 5x*3x^2 = 5*5*x*x^2 = 15x^3 Does that make sense? EDIT Changed 15x^2 to 15x^3, thanks to Mr. K for pointing it out.

I don't understand problem 3 can anyone explain?

Question, problem 3 is it just another method to get the answer to problem 2? Because I used a 2 step formula of solving the equation separately and then plugging in the answers; and I got both problem 1 and 2 correct. But got problem 3 incorrect.

Main content

Precalculus

Unit 1: Lesson 1

Composing functions

Intro to composing functions

CCSS.Math:

HSF.BF.A.1c

Google Classroom

Learn why we'd want to compose two functions together by looking at a farming example.

Cam is a farmer. Each year he plants seeds that turn into corn. The function below gives the amount of corn, C, in kilograms (kg), that he expects to produce if he plants corn on a acres of land.

C, left parenthesis, a, right parenthesis, equals, 7500, a, minus, 1500

For example, if Cam plants two, he expects to produce C, left parenthesis, 2, right parenthesis, equals, 7500, left parenthesis, 2, right parenthesis, minus, 1500, equals, 13, comma, 500 start text, k, g, end text of corn.

What Cam really wants to know is how much money he will make from selling this corn. So he uses the following function to predict the amount of money, M, in dollars, that he will earn from selling c kilograms of corn.

M, left parenthesis, c, right parenthesis, equals, 0, point, 9, c, minus, 50

So if Cam produces 13, comma, 500, start text, space, k, g, end text of corn, he can expect to make M, left parenthesis, 13, comma, 500, right parenthesis, equals, 0, point, 9, left parenthesis, 13, comma, 500, right parenthesis, minus, 50, equals, dollar sign, 12, comma, 100.

Notice that Cam has to use two separate functions to get from acres planted to expected earnings. The first function, C, takes acres to corn, while the second function, M, takes corn to money.

Wouldn't it be great if Cam could write a function that turned planted acres directly into expected earnings?

Creating a new function

We can indeed find the function that takes acres planted directly to expected earnings! To find this new function, let's think about the most general question: how much money does Cam expect to make if he plants corn seed on a acres of land?

Well, if Cam plants corn on a acres, he expects to produce C, left parenthesis, a, right parenthesis kilograms of corn. And if he produces C, left parenthesis, a, right parenthesis kilograms of corn, he expects to make M, left parenthesis, C, left parenthesis, a, right parenthesis, right parenthesis dollars.

So, to find a general rule that converts a acres directly into expected earnings, we can find the expression M, left parenthesis, C, left parenthesis, a, right parenthesis, right parenthesis.

But just how do we do this? Well, notice that in the expression M, left parenthesis, start color #1fab54, C, left parenthesis, a, right parenthesis, end color #1fab54, right parenthesis, the input of function M is start color #1fab54, C, left parenthesis, a, right parenthesis, end color #1fab54. So, to find this expression, we can substitute start color #1fab54, C, left parenthesis, a, right parenthesis, end color #1fab54 in for start color #e07d10, c, end color #e07d10 in function M.

$\begin{aligned} M(\goldD c)&=0.9\goldD c-50\\\\ M({\greenD{C(a)}})&=0.9(\greenD{C(a)})-50\\ \\ &= 0.9(\greenD{7500a-1500})-50~~~~~~~~~~\small{\gray{\text{Since }}}\small{\gray{C(a)=7500a-1500} }\\\\ &= 6750a-1350-50\\\\ &=6750a-1400 \end{aligned}$

So the function M, left parenthesis, C, left parenthesis, a, right parenthesis, right parenthesis, equals, 6750, a, minus, 1400 converts acres planted directly into expected earnings. Let's use this new function to predict the amount of money that Cam would make from planting corn on two acres.

M, left parenthesis, C, left parenthesis, 2, right parenthesis, right parenthesis, equals, 6750, left parenthesis, 2, right parenthesis, minus, 1400, equals, dollar sign, 12, comma, 100

Cam can expect to make dollar sign, 12, comma, 100 from planting corn on two acres of land, which is consistent with our previous work!

Defining composite functions

We just found what is called a composite function. Instead of substituting acres planted into the corn function, and then substituting the amount of corn produced into the money function, we found a function that takes the acres planted directly to the expected earnings.

We did this by substituting C, left parenthesis, a, right parenthesis into function M, or by finding M, left parenthesis, C, left parenthesis, a, right parenthesis, right parenthesis. Let's call this new function M, circle, C, which is read as "M composed with C".

We now know that left parenthesis, M, circle, C, right parenthesis, left parenthesis, a, right parenthesis, equals, M, left parenthesis, C, left parenthesis, a, right parenthesis, right parenthesis. This, in fact, is the formal definition of function composition!

Visualizing the two methods

Here's a visual to help interpret the above definition.

Using both functions C and M, function C—the corn function—takes two to 13,500. Then, function M—the money function—takes 13,500 to dollar sign12,100.

Using the composite function, we see that function M, circle, C takes two directly to dollar sign12,100.

The two are equivalent!

Now let's practice some problems.

Problem 1

Using the functions presented in the example, how much can Cam expect to earn if he sells all the corn produced on 1.5 acres?

For reference: C, left parenthesis, a, right parenthesis, equals, 7500, a, minus, 1500, M, left parenthesis, c, right parenthesis, equals, 0, point, 9, c, minus, 50 and M, left parenthesis, C, left parenthesis, a, right parenthesis, right parenthesis, equals, 6750, a, minus, 1400

dollars

[I need help. Please show me the solution.]

Problem 2

Ben is a potato farmer. The function P, left parenthesis, a, right parenthesis, equals, 25, comma, 000, a, minus, 1000 gives the amount of potatoes, P, in kilograms, that he expects to produce from planting potatoes on a acres of land. The function M, left parenthesis, p, right parenthesis, equals, 0, point, 2, p, minus, 200 gives the amount of money, M, in dollars, that Ben expects to make if he produces p kilograms of potatoes.

How much money can Ben expect to make if he sells all of the potatoes produced on the 3 acres?

[I need help. Please show me the solution.]

Problem 3

Which of the following expressions gives the amount of money that Ben expects to make if he plants potatoes on a acres of land?

[I need help. Please show me the solution.]

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ashley santana
Posted 7 years ago. Direct link to ashley santana's post “where did the 1500 come f...”
where did the 1500 come from?
(25 votes)
Answer
- xilverd020
  Posted 6 years ago. Direct link to xilverd020's post “It is most likely the ave...”
  It is most likely the average expected loss of crops in kg when harvesting.
  (27 votes)
Liah C.
Posted 6 years ago. Direct link to Liah C.'s post “Could someone please expl...”
Could someone please explain where 6750a came from in Problem One? How was that number found?
(16 votes)
Answer
- Kim Seidel
  Posted 6 years ago. Direct link to Kim Seidel's post “The problem gave you: M(...”
  The problem gave you: M(C(a))=6750a−1400
  This was created by combining the 2 functions C(a) and M(c) by making C(a) as the input to M(c). Here's how that was done...
  We were also given:
  C(a)=7500a−1500
  M(c) = 0.9c - 50
  Insert C(a) as the input into M(c) and here's what M(C(a)) looks like before simplifying:
  M(C(a))=0.9(7500a−1500)−50
  After you simplify, you get M(C(a)) = 6750a−1400
  
  Hope this helps.
  (29 votes)
Shalaya
Posted 7 years ago. Direct link to Shalaya's post “How would you find the va...”
How would you find the value of the function if like you had f(g(-1)) how would you put that into in equation to solve?
(4 votes)
Answer
- Dawson Stokes
  Posted 7 years ago. Direct link to Dawson Stokes's post “Since this is currently r...”
  Since this is currently real world problems, having a negative amount of land is impossible. You would solve it the same way though such as the potato farmer problem by solving P of -1, or substituting it at the end.
  (2 votes)
Jason Reed
Posted 7 years ago. Direct link to Jason Reed's post “can i get some help with ...”
can i get some help with this its kinda getting confusing?
(5 votes)
Answer
- anishbanerjee65
  Posted 5 years ago. Direct link to anishbanerjee65's post “How to find if a composit...”
  How to find if a composite function is valid or not? How to find its range and domain?
  (3 votes)
Liam Heraty
Posted 6 years ago. Direct link to Liam Heraty's post “In defining composite fun...”
In defining composite functions paragraph 3 it says (M*C)(a) = M(C(a)). Isn't that just multiplying functions? If it says (M*C)(a) why can't I just multiply the two functions?
(3 votes)
Answer
- Kim Seidel
  Posted 6 years ago. Direct link to Kim Seidel's post “Same answer as your other...”
  Same answer as your other question. Composite function uses an open circle/dot, not a solid dot like multiplication.
  Composite: (M o C)(a)
  Multiplication: (M * C)(a) or (M • C)(a)
  (4 votes)
Silverleaf.yen
Posted 4 years ago. Direct link to Silverleaf.yen's post “How do you find the domai...”
How do you find the domain of a composite function?
(3 votes)
Answer
- Alex
  Posted 4 years ago. Direct link to Alex's post “The domain of a composite...”
  The domain of a composite function f(g(x)) is all x in the domain of g such that g(x) is in the domain of f.
  
  Let's break this down. First off, the x has to be in the domain of g; if g(x) were say 1/x, then x = 0 could not be in the composite domain. Second of all, even if g(x) is defined, it has to be in the domain of f. Say f(x) equals 1 / (x - 1). Then if you choose an x such that g(x) = 1, making f(g(x)) = 1 / 0, that x cannot be in the domain of the composite function. Hope that I helped.
  (3 votes)
Alex Cail
Posted 6 years ago. Direct link to Alex Cail's post “Problem 1 Shouldn't you s...”
Problem 1
Shouldn't you solve for C(1.5), then input that value into M(C(a)) rather than just use M(1.5)??

For example, here's my work:
1.5 acres
C(1.5) = 7500(1.5) - 1500
11250-1500 = 9750
M(9750) = 6750(9750) - 1400
65812500-1400 = 65811100

I realize that the solution I came up with is unrealistic, but my method of solving seems to me to follow the method taught. So, my question is: why don't you solve it the way I did?
(3 votes)
Answer
- Kim Seidel
  Posted 6 years ago. Direct link to Kim Seidel's post “Your method would work i...”
  Your method would work if you used M(c) = 0.9c - 50
  You used M(c(a)), which already has both functions combined into one. So, you basically applied function C(a) twice.
  Hope this helps.
  (2 votes)
Ace Matei
Posted 3 years ago. Direct link to Ace Matei's post “What do I do if I have to...”
What do I do if I have to find f(x)h(x)?
(2 votes)
Answer
- loumast17
  Posted 3 years ago. Direct link to loumast17's post “Multiply the two function...”
  Multiply the two functions. so say f(x) = 5x and g(x) = 3x^2 then f(x)g(x) = 5x*3x^2 = 5*5*x*x^2 = 15x^3 Does that make sense?
  
  EDIT
  
  Changed 15x^2 to 15x^3, thanks to Mr. K for pointing it out.
  (3 votes)
Helen
Posted 6 years ago. Direct link to Helen's post “I don't understand proble...”
I don't understand problem 3 can anyone explain?
(2 votes)
Answer
- semo.199114
  Posted 6 years ago. Direct link to semo.199114's post “Question, problem 3 is it...”
  Question, problem 3 is it just another method to get the answer to problem 2? Because I used a 2 step formula of solving the equation separately and then plugging in the answers; and I got both problem 1 and 2 correct. But got problem 3 incorrect.
  (2 votes)
Jonathan
Posted 4 years ago. Direct link to Jonathan's post “Just to clarify one thing...”
Just to clarify one thing: if (f o g) (x) is equal to f(g(x)), then would (f o g o h) (x) be equal to f(g(h(x)))? Thanks!
(1 vote)
Answer