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### Course: Integral Calculus > Unit 5

Lesson 13: Power series intro# Power series intro

Power series is a sum of terms of the general form aₙ(x-a)ⁿ. Whether the series converges or diverges, and the value it converges to, depend on the chosen x-value, which makes power series a

*. Created by Sal Khan.***function**## Want to join the conversation?

- How are there any applications for this? A function, whose x-values are restricted between -1 and 1 doesnt seem to be very useful?(10 votes)
- A couple points on that:

1. Not all functions have such a small radius of convergence. The power series for sin(x), for example, converges for**all real values of x**. That gives you a way to calculate sin(x) for any value using nothing but a polynomial, which is an extremely powerful concept (especially given that we can't just evaluate a number like sin(47) because 47 doesn't fit nicely with the periodicity of the sine function; we have to use some other method that we can*actually calculate*, which generally boils down to polynomial approximations -- power series).

2. Even for functions with small radii of convergence, power series still give us the ability to calculate values that would otherwise be unapproachable. The series for ln(x) centered at x=1 converges only over a radius of 1, but for calculating a number like ln(0.36), it's obviously still useful.

3. We can just shift the center of our power series if we want to approximate a value outside the interval of convergence. For example, to calculate ln(5), we could use a power series for ln(x) centered at x=e^2 instead of x=1, which would put x=5 inside our interval of convergence.

In short, power series offer a way to calculate the values of functions that transcend addition, subtraction, multiplication, and division -- and they let us do that using only those four operations. That gives us, among other things, a way to program machines to calculate values of functions like sin(x) and sqrt(x).

Hope that helps.(39 votes)

- 1.) Is a polynomial a type of power series where a_n is 0 for certain n (it has to be 0 because a polynomial has a finite number of terms)?

2.) Could the geometric series be generalized to the summation from n=0 to Infinity of a*(*x-c*)^n?(7 votes)- 1) Yes, polynomials could be said to be special cases of the power series.

2) Sure. The new convergence condition would be that |x - c| < 1.(15 votes)

- Hey guys, I had trouble of understanding what Power Series is. What is this power series for? is it just expanding a given function or something? your reply will be helpful thanks!(10 votes)
- A power series is simply a category of series. If a series follows that specific form, then it's called a power series.(1 vote)

- This tells how to find the interval of convergence for a geometric series but doesn't explain how to do so for a power series, which is what i thought this video was supposed to be about......(3 votes)
- It was subtle and easy to miss, but at1:07Sal mentions that Geometric Series is a special case of the Power Series where the common ratio is an x, rather than an r. This is important, he is saying that geometric series, while you may not have thought about them as power series, or even as a representation of a function, they are, and that when you analyse a geometric series, it is just a special case of a power series. In fact, this is the usual method of introducing power series, by developing the concept of a geometric series, and applying that when meeting the power series with the "good news" that the general formula a/(1-r) becomes a/(1-x) and can be used to determine the radius of convergence.

The following videos will make this point clearer.(8 votes)

- At0:54, Sal says that the first term in the series will simplify to a_0. Is that still true when x = c? Wasn't 0^0 an indeterminate form?(4 votes)
- You are correct that 0^0 is an indeterminate form! Three things that come to mind:

1) the limit as x --> 0 for x^0 is 1.

2) 0^0 does not exist, because it is indeterminate (only the limit exists)

3) if x-c = 0 then all of the rest of the series terms would go to zero

So if I had to make an educated guess, I would say that there are two possible outcomes:

1) we start our summation at n = 0 and then the series fails, because it contains an indeterminate form

2) we start our summation at n = 1 and then the series = 0(2 votes)

- Whats the difference between a power series as a function of x and a geometric series as a function of x?(3 votes)
- A geometric series is simply a special case of a power series, where c = 0 and aₙ = a.(3 votes)

- At around the6:15mark, if the interval of convergence included 1 or -1, would the radius of convergence still be 1?(2 votes)
- To determine the radius of convergence, do not worry about whether the endpoints are included or not. The radius of convergence would be one regardless of whether or not the endpoints were included.(5 votes)

- So is radius always half the difference in values for the interval?(4 votes)
- Yes, assuming the absolute value of the values are equal. For example if the interval of convergence is -2 < x < 1 and c = 0, the radius of convergence is actually 1, since the series converges as long as x is within 1 of 0. The series does not converge as long as x is within 2 of 0, since x = 2 will not converge.(1 vote)

- I'm confused how it simplifies to a/(1-x) because if you run it with say x = .5 it doesn't work(3 votes)
- This is actually a result of adding a geometric sequence if you add a sequence to infinity where there is a common ration between each term and the absolute value of that ratio is less than one then that series converges and it equals a/1-r where r is the common ratio and a is the first term I suggest watching these videos to refresh your memory about geometric series

https://www.khanacademy.org/math/algebra2/sequences-and-series/alg2-geometric-sequence-series/v/series-as-sum-of-sequence

I don't understand what led you to believe that it doesn't work when x=0.5 if you set x=0.5 you get 2a which makes sense remember that we are adding a + a/2 + a/4 + a/8 .. to inf.

if you take a common then you will have a * ( 1 + 1/2 + 1/4 + 1/8 .... )

there are beautiful visualization why the right term results in two and so you would have a*2

which doesn't seem wrong to me.

here is a visualization for the previous result hope this helps and keep studying and good luck.

https://twitter.com/brilliantorg/status/974450173110898688(2 votes)

- What is center of convergence specifically?(2 votes)
- The center of convergence is where the distance from the lowest point to a specific number(the center) is the same as the distance from the highest point to a specific number(the center). Another word for the distance is the radius of convergence. Example: the center of convergence of the interval -1<x<1 is 0, because the radius is 1. You can find the center by subtracting the bigger number of the interval by the smaller number of the interval and then dividing by 2. Example: Center of -1<x<1= (1-(-1))/2=2/2=1.(3 votes)

## Video transcript

We've already seen many
examples of infinite series. But what's exciting about what
we're about to do in this video is we're going to use infinite
series to define a function. And the most common
one that you will see in your mathematical
careers is the power series. And I'm about to write a general
case of the power series. So I could imagine
a function, f of x, being defined as
the infinite sum. So going from n equals 0
to infinity of a sub n-- so a sub n is just going to be
the coefficient on each term-- times our variable x
minus some constant c. You could almost
imagine this is shifting our function to the n-th power. So if I were to
expand this out, I have my first term's
coefficient, a sub 0, times x minus c
to the 0-th power, plus a sub 1 times x minus
c to the first power. This one, of course, will
simplify just a sub 0. This would simplify to a sub
1 times x minus c plus a sub 2 times x minus c squared. And I could just keep
going on and on and on. Now, when you see
this, you might say, aren't our geometric
series, don't those look like a special
case of a power series if our common ratio was an x
instead of an r in that case, or if our common ratio was a
variable, I guess I could say? And you would be right. That absolutely
would be the case. So a geometric series. So let's just think about
defining a function in terms of a geometric series. And of course, we
don't have to use x all the time as the
independent variable, but this is kind of the
most typical convention. I guess we could also use r
as an independent variable if we wanted as well. But let's imagine
a function g of x. We could have g of r
if we wanted, but let's do g of x is equal
to the sum from n equals 0 to infinity
of a times x to the n. So this is kind of a typical
geometric series here. And what's the difference
between this and this? Well, the difference is is
here, for every term we're going to have the
same coefficient a, while over here we have a sub n. We're multiplying by a different
thing every time up here. We're multiplying by the
same thing over here. And in this case, this
particular geometric series I just made, instead of
having x minus c to the n, we have just x to the n. So you could say, well,
this is a special case when c is equal to 0. And we can expand it out. This is a times
x to the 0, which is just going to be a, plus
a times x to the first, plus a times x squared. And we just go on and
on and on forever. Now, what's exciting
about this is we know that this, under
certain conditions, will actually give
us a finite value. This will actually converge. This will actually, I guess,
give us a sensical answer. So under what conditions
does that happen? Well, this converges
if each of these terms gets smaller and
smaller and smaller. And each of these terms gets
smaller and smaller and smaller if the absolute value of our
common ratio is less than 1. So let me write that down. So this converges if
the absolute value of our common ratio
is less than 1. Or another way of
thinking about it, this is another way
of saying that x is in the interval
between-- it's less than 1 and it is greater
than negative 1. And this term right over
here, now x is a variable. x can vary between those values. We're defining a
function in terms of x. We call this the
interval of convergence. And so we know that if
x is in this interval, this is going to
give us a finite sum. And we know what
that finite sum is. It's going to be equal
to-- if it converges. So if it converges,
this is going to be equal to our first
term, which is just a-- this simplifies to a
right over here-- over 1 minus our common ratio. What's our common ratio? Our common ratio in
this example is x. Going from one term to the next,
we're just multiplying by x. We're just multiplying
by x right over there. Now, this is pretty
neat, because we're going to be able
to use this fact to put more
traditionally-defined functions into this form, and
then try to expand them out using a geometric series. And this whole idea
of using power series, or in this special
case, geometric series to represent functions,
has all sorts of applications in
engineering and finance. Using a finite number of
terms of these series, you could kind of
approximate the functions in a way that's simpler
for the human brain to understand, or
maybe a simpler way to manipulate in some way. But what's interesting
here is instead of just going from the sum
to-- instead of going from this expanded-out version
to this kind of finite value, we're now going to start
being able to take something in this form and expand it
out into a geometric series. But we have to be
careful to make sure that we're only doing it over
the interval of convergence. This is only going to be
true over the interval of convergence. Now, one other term you might
see in your mathematical career is a radius. Radius of convergence. And this is how far--
up to what value, but not including this value. So as long as our x value stays
less than a certain amount from our c value, then
this thing will converge. Now in this case,
our c value is 0. So we could ask
ourselves a question. As long as x stays
within some value of 0, this thing is going to converge. Well, you see it
right over here. As long as x stays
within one of 0. It can't go all the
way to 1, but as long as it stays less
than 1, or as long as it stays greater
than negative 1. It can stray anything
less than one away from 0, either in
the positive direction or the negative direction. Then this thing
will still converge. So we could say that our radius
of convergence is equal to 1. Another way to think about it,
our interval of convergence-- we're going from
negative 1 to 1, not including those
two boundaries, so our interval is 2. So our radius of
convergence is half of that. As long as x stays
within one of 0, and that's the same thing as
saying this right over here, this series is
going to converge.