Sal finds the magnitude of a vector given its components of (5, -3).
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- So wait, do we always have to assume a vector starts at (0,0) if ve are only given one of its components? (In this case a)(26 votes)
- No. It is convenient to draw vectors starting at the origin, but it is NOT necessary.
5 is just the vector's LENGTH, and -3 is just the vector's HEIGHT. You can draw the vector starting at any point on the graph, but you have to make sure it has a length of 5 and a height of negative 3.
For example: If you drew the vector starting at point (1, 1) then its terminal point would be (6, -2)(38 votes)
- Why does Sal use two bars to indicate magnitude (||a||) instead of one (|a|)? Is there a reason for that or can either way be used interchangeably?(8 votes)
- Can the magnitude of a vector formed by irrational scalars be negative?(3 votes)
- My understanding of MAGNITUDE is that it is the length of the vector and therefore cannot be negative. But its DIRECTION can be positive or negative.(9 votes)
- Why does Sal use the
formula to find the
of the vector?
- Because the magnitude is the length of the vector. In other words, it's the distance between 2 points.(4 votes)
- isn't the proper way to denote a vector something like: <1,1> and not (1,1)? I've always seen vectors with <> but maybe that's only for unit vectors?(2 votes)
- I've never seen the <x,y> notation however, I have seen the (x,y) row vector or column vector notation (two big brackets with the x on top and y on bottom inside the brackets). The row vector/column vector notation will be used in matrix algebra.(1 vote)
- my teacher always draws the vectors with pointy parentheses. Is there a reason why? They are called angle brackets.(1 vote)
- This is a notational norm. Since you could potentially confuse (x,y) with a coordinate point, using <x,y> simply tells you, "this is a vector" so you just know when you see the brackets.(3 votes)
- Does all vectors have to start at the origin?(2 votes)
- No.And even this problem is just showing its length over both the axes.That is also represented as 5i-3j(1 vote)
- If I have a vector's magnitude, and it's heading (angle) then how do I calculate the components?(1 vote)
- The short version is.
Given a vector with v with the magnitude r and direction θ. The x component is r•cos(θ) and the y component is r•sin(θ)(2 votes)
- What are the two lines he uses on the both sides of vector a called? I have not learnt it yet, seems to be confusing.
Can someone help me out here?(1 vote)
- That just means the magnitude of the vector. If v is a vector, then ||v|| is a real number, the magnitude of v.(2 votes)
- [Voiceover] Let's do some examples figuring out the magnitude of a vector if we're just given some information about it. So, one of the simplest cases would be well, if they just told us the actual components of the vector. So if they said vector a is equal to, let's say five comma negative three, this means that its x-component is positive five, its y-component is negative three. Well, if we have this, then the magnitude of a, the magnitude of a is just going to be, and this really just comes from the distance formula which just comes from the Pythagorean theorem, the magnitude of a is just going to be the square root of the x-component squared. So let me do that in a different color. So the square root of the x-component squared, so five squared, plus the y-component squared, so plus negative three squared. And this is going to be equal to the square root of 25, 25 plus nine, plus nine, which is equal to the square root of 34, which is equal to the square root of 34. And if you want to think about this visually, this is very easy to do just looking at the actual components. But if you want to make sense of this, why this is essentially just the Pythagorean theorem, we could draw out a quick coordinate axis right over here. So that's our y-axis. This is our, let's see, I have a y-component of negative three. So let's see. That is our, actually let me draw it a little bit different. Let me draw it like this. That is our x-axis. And we see its x-component is positive five, so one, two, three, four, five. That's five there. And its y-component is negative three. So one, two, three. And so this is negative three. And so we can draw this vector with its initial point. Remember, we can always shift around a vector as long as we don't change its magnitude and to direction. We can start it at the origin, and make it go five in the x-direction and negative three in the y-direction, and so its terminal point will be right over there at the point five comma negative three. And so the vector, the vector, will look like this. And if we want to figure out the magnitude, that's just the length of this line. And what we can do is just set up a right triangle where our change, our change in y is this negative three right over here. That is our change in y. And our change in x is this positive five, is that positive five. And so this is a right triangle. Five squared plus, you could just view the absolute value of this side as three, so five squared plus three squared is going to be the hypotenuse squared. Comes straight out of the Pythagorean theorem.