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Creating an equation with no solutions

Sal shows how to complete the equation -11x + 4 = __x + __ so that it has no solutions. Created by Sal Khan.

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  • blobby green style avatar for user Alexandra Hamilton
    How do I find the value of a constant, such as (k) where there are no solutions? How would I solve it if the equation 4(80 + n) = (3k)n ?
    (17 votes)
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    • stelly blue style avatar for user Kim Seidel
      I think you are saying that you need to find a value of "k" so that the equation will have no solution.
      For this to happen...
      1) the coefficient of "n" must match on both sides of the equation
      2) the constant on each side must be different.

      Start by simplifying your equation -- distribute the 4: 320 + 4n = 3kn
      The constants on each side are different: 320 on left, and 0 on right. So, one condition is met.
      We now know that the coefficient of "n" must = 4. You can find "k" by setting 3k = 4 and solving for "k".

      Hope this helps.
      (2 votes)
  • leaf blue style avatar for user Logeswaran SaCh
    Is there any simple trick to find the equation which has no solution without even solving it
    (5 votes)
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    • mr pink green style avatar for user David Severin
      This trick is based on simplifying and as soon as you see the same coefficients of the variable on both sides and any different numbers on the two sides, you know that there are no solutions.
      Example: 2(2x+7)= 5x +12 -x
      Distribute on left to get 4x +14
      Combine like terms on right to get 4x + 12
      Since the coefficients of x are both 4, but the constants are different, you know there are no solutions because if you took it to the end, you would get 2=0 which can never be true.
      (1 vote)
  • marcimus purple style avatar for user jg18697
    how many solution does 4(2x – 3) – 5 = 4x have
    (4 votes)
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  • duskpin tree style avatar for user Pan
    why would we want to make a linear equation that has no solution, isn't the point of an equation to solve for the variable?
    (0 votes)
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    • leaf grey style avatar for user Arzal
      Wow, this comment is old, where are you now? anyway, my guess is that by creating a linear equation with no solution at all we could instantly distinguish equations with no solution with just 1 step or less and thus saving time.
      (5 votes)
  • orange juice squid orange style avatar for user Jon Winder
    Is there any real world application for making an equation with no solution?
    (1 vote)
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  • leaf green style avatar for user Anonymous
    Wait. Equations with no solution cannot apply to something in real life because of the laws of thermodynamics, so if these equations have no real life use why are we learning about them at all. Or do they have a real life use.
    (2 votes)
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    • leafers ultimate style avatar for user Scott R.
      That is actually almost true, but the reason we learn them is to show that there are equations with no answer, but yes there is no real life application since you will never in real life with real problems ever really experience something with no solution.
      (2 votes)
  • aqualine tree style avatar for user Shyann Clarkson
    how do we find the equations with one solution
    (2 votes)
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  • blobby green style avatar for user Heriberto.Zavala
    For example in the inequality 75x+57= -75x+57 you end up with 150x=0. When it's equal to zero how many solutions does it have??
    (1 vote)
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  • female robot grace style avatar for user preeti
    What is the website that the guy used for this video? I think that would be really good to practice on. Thanks!
    (2 votes)
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  • duskpin sapling style avatar for user Hodakarim64
    If Sal put 4x + 4 instead of -11x + -11, would he still get the question right?
    (2 votes)
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Video transcript

We're asked to use the drop-downs to form a linear equation with no solutions. So a linear equation with no solutions is going to be one where I don't care how you manipulate it, the thing on the left can never be equal to the thing on the right. And so let's see what options they give us. One, they want us to-- we can pick the coefficient on the x term and then we can pick the constant. So if we made this negative 11x, so now we have a negative 11x on both sides. Here on the left hand side, we have negative 11x plus 4. If we do something other than 4 here, so if we did say negative 11x minus 11, then here we're not going to have any solutions. And you say, hey, Sal how did you come up with that? Well think about it right over here. We have a negative 11x here, we have a negative 11x there. If you wanted to solve it algebraically you could add 11x to both sides and both of these terms will cancel out with each other and all you would be left with is a 4 is equal to a negative 11, which is not possible for any x that you pick. Another way that you think about it is here we have negative 11 times some number and we're adding 4 to it, and here we're taking negative 11 times that same number and we're subtracting 11 from it. So if you take a negative 11 times some number and on one side you add four, and on the other side you subtract 11, there's no way, it doesn't matter what x you pick. There's no x for which that is going to be true. But let's check our answer right over here.