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AP Calc: LIM‑2 (EU), LIM‑2.D (LO), LIM‑2.D.1 (EK), LIM‑2.D.2 (EK)

Video transcript

- [Instructor] In a previous video, we explored the graphs of Y equals one over X squared and one over X. In a previous video we've looked at these graphs. This is Y is equal to one over X squared. This is Y is equal to one over X. And we explored what's the limit as X approaches zero in either of those scenarios. And in this left scenario we saw as X becomes less and less negative, as it approaches zero from the left hand side, the value of one over X squared is unbounded in the positive direction. And the same thing happens as we approach X from the right, as we become less and less positive but we are still positive, the value of one over X squared becomes unbounded in the positive direction. So in that video, we just said, "Hey, "one could say that this limit is unbounded." But what we're going to do in this video is introduce new notation. Instead of just saying it's unbounded, we could say, "Hey, from both the left and the right it looks like we're going to positive infinity". So we can introduce this notation of saying, "Hey, this is going to infinity", which you will sometimes see used. Some people would call this unbounded, some people say it does not exist because it's not approaching some finite value, while some people will use this notation of the limit going to infinity. But what about this scenario? Can we use our new notation here? Well, when we approach zero from the left, it looks like we're unbounded in the negative direction, and when we approach zero from the right, we are unbounded in the positive direction. So, here you still could not say that the limit is approaching infinity because from the right it's approaching infinity, but from the left it's approaching negative infinity. So you would still say that this does not exist. You could do one sided limits here, which if you're not familiar with, I encourage you to review it on Khan Academy. If you said the limit of one over X as X approaches zero from the left hand side, from values less than zero, well then you would look at this right over here and say, "Well, look, it looks like we're going unbounded in the negative direction". So you would say this is equal to negative infinity. And of course if you said the limit as X approaches zero from the right of one over X, well here you're unbounded in the positive direction so that's going to be equal to positive infinity. Let's do an example problem from Khan Academy based on this idea and this notation. So here it says, consider graphs A, B, and C. The dashed lines represent asymptotes. Which of the graphs agree with this statement, that the limit as X approaches 1 of H of X is equal to infinity? Pause this video and see if you can figure it out. Alright, let's go through each of these. So we want to think about what happens at X equals one. So that's right over here on graph A. So as we approach X equals one, so let me write this, so the limit, let me do this for the different graphs. So, for graph A, the limit as x approaches one from the left, that looks like it's unbounded in the positive direction. That equals infinity and the limit as X approaches one from the right, well that looks like it's going to negative infinity. That equals negative infinity. And since these are going in two different directions, you wouldn't be able to say that the limit as X approaches one from both directions is equal to infinity. So I would rule this one out. Now let's look at choice B. What's the limit as X approaches one from the left? And of course these are of H of X. Gotta write that down. So, of H of X right over here. Well, as we approach from the left, looks like we're going to positive infinity. And it looks like the limit of H of X as we approach one from the right is also going to positive infinity. And so, since we're approaching you could say the same direction of infinity, you could say this for B. So B meets the constraints, but let's just check C to make sure. Well, you can see very clearly X equals one, that as we approach it from the left, we go to negative infinity, and as we approach from the right, we got to positive infinity. So this, once again, would not be approaching the same infinity. So you would rule this one out, as well.
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