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Algebra 1
Course: Algebra 1 > Unit 8
Lesson 13: Intro to inverse functionsGraphing the inverse of a linear function
CCSS.Math: ,
Sal is given a line segment on the coordinate plane, and he graphs the inverse of the function represented by that segment.
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Are all linear functions invertible around y=x?(22 votes)
All functions are at least in part invertible (for some functions you have to only take a small part of the function in order for it to be invertible), but once you invert them, graphically they all look like they were mirrored about the liney = x.(17 votes)
- Sal said in his first video in inverse function that he will explain why he constrained the domain of function. Where is the video that explain the reason ?(11 votes)
In Algebra 1, the first module is functions. Check it up, it's there(0 votes)
- Will the line Y=X stay the same or would something strange happen?(7 votes)
- Can someone please explain to me the concept of the horizontal line test? I'm doing the domain and range with inverse functions exercise.(3 votes)
The horizontal line test is used for figuring out whether or not the function is an inverse function. Picture a upwards parabola that has its vertex at (3,0). Then picture a horizontal line at (0,2). The line will touch the parabola at two points. This is how you it's not an inverse function.(5 votes)
how do you solve the inverse function of y=x^2 +2(2 votes)
The inverse can be found by switching the x and y, then solving for y again.
So the inverse is x=y^2 +2
x-2=y^2
y=√(x-2)(5 votes)
- So i have never understood how to get Domain and Range of anything or where it comes from or why. I've tried again again to understand.... Maybe you could help me ?(2 votes)
TRL, I think of domain as the possible values of x that will result in a point on a curve; and range are the possible values of y that could result in a point on a curve. Think of a parabola... any x can be substituted into the equation to get a y on the curve, so the domain is all real numbers. But our parabola has a minimum or maximum, so there's a point where the y-values stop being an option. That's a restriction on the range, that y can only be greater than or equal to the minimum, or less than or equal to the maximum, depending on the way it's facing. In this inverse video, the trick is to remember that the range of a function affects the domain of the inverse, and the domain of a function affects the range of the inverse :-)(3 votes)
If the graphs of a function and its inverse function intersect, would the two graphs intersect on the line y=x? What is the possibility for the two graphs to intersect on other lines?(3 votes)
Since the idea that you switch x and y, it makes sense that the primary place that this happens is along the y=x (or if you switch places, x=y) line. They could possibly intersect on an infinite number of other lines because any point has an infinite number of lines that go through it, but it has to be on the y=x line. Say the point of intersection is (2,2) this is on the y=x line, but is it also on the y = 4x - 6, y = 3x-4, etc. lines, but these are just arbitrary lines that just happen to contain the point (2,2) but are otherwise totally unrelated to the inverse function. Because they reflect across the y=x line, one rule of reflection is that if a point is on the line of reflection, then it maps back to itself. That would be true of my other examples, but none of the other points on the function and its inverse would reflect across these line.(1 vote)
Implicitly defined curves do have "inverses" but I don't understand why they may not be the graph of a function. For example, if I plot the inverse relation of f(x) = x^3-4x, how can you say it is not the graph of a function? It would really help me out if you could answer this question. Thank you : )(2 votes)- So the function you present has an inverse that is not a function. If you factor this out to x(x^2-4) or x(x-2)(x+2) you have three x intercepts at (0,0) (2,0) and (-2,0). If you switched x and y, your inverse function would have 3 y intercejpts at (0,0) (0,2) and (0,-2) which does not pass the vertical line test and has one x value go to 3 different y values, and is thus not a function. Some cubic functions such as the parent function (y=x^3) or with just a cube and constant (y=x^3 - 27) would have inverses that are functions.
By starting out with a function, you know it passes the vertical line test by definition. However, for its inverse to be a function, it also has to pass the horizontal line test to insure the one-to-one correspondence of x and y values.(2 votes)
- If h^-1(x) is the inverse of h(x) then are h^-1(y) and h(x) the same?(2 votes)
How can you reflect a line across y=x without graphing each point? Is there any way to do it in a graphing calculator?(2 votes)- Develop the inverse equation from the original line equation. For example suppose that y = 2x +6.
solve for f(x) inverse by isolating x as a function of y. x = (y-6)/2. Now swap the variables so that y = (x-6)/2 and use your graphing calculator.(2 votes)
Video transcript
This right over here is our understanding inverses of functions
exercise on Khan Academy. It's a good exercise to make sure
you understand inverses of functions. It's an interactive one
where we can move this line around and it tells us 'the graph of h(x)
is the green', so that's this dotted green line,
'the dashed line segment shown below'. So that's this. 'Drag the endpoints of the segment below
to graph h inverse of (x). There's a couple of ways to tackle it. Perhaps the simplest one
is we say, okay, look, h(x), what does h(x)
map from and to? So h(x), this point
shows that h(x), if you input -8 into h of (x),
h of -8 is 1, so it's mapping from -8 to 1. Well, the inverse of that, then,
should map from 1 to -8. So let's put that point on the graph,
and let's go on the other end. On the other end of h of x, we see that when you input 3 into h of x,
when x is equal to 3, h of x is equal to -4. So this point shows us
that it's mapping from 3 to -4. So the inverse of that would map
from -4 to 3. If you input -4 it should output 3. Since we took
the two end points of this line and found the inverse mapping of it, what I have just done here
is that I have graphed the inverse. Another way to think about the inverse is if you were to draw the line y = x, these things should be reflections
around the line y =x because one way to think about it is,
you're swapping the xs for the ys. If you were to draw the line y = x, if you flipped it around,
the line y = x, the green line, you would actually get the old line. This would flip over there
and this would flip over there. But either way, we're done.
We have graphed h inverse of x.