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## Algebra (all content)

### Unit 10: Lesson 7

Special products of binomials- Special products of the form (x+a)(x-a)
- Squaring binomials of the form (x+a)²
- Multiply difference of squares
- Special products of the form (ax+b)(ax-b)
- Squaring binomials of the form (ax+b)²
- Special products of binomials: two variables
- More examples of special products
- Polynomial special products: perfect square
- Squaring a binomial (old)
- Binomial special products review

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# More examples of special products

CCSS.Math:

Sal gives numerous examples of the two special binomial product forms: perfect squares and the difference of two squares. Created by Sal Khan and CK-12 Foundation.

## Want to join the conversation?

- Could you use FOIL to do these kind of problems?

Thanks!(12 votes)- Of course! These methods are just faster ways of getting the same answers. FOIL is usually used for numbers with no such patterns.(1 vote)

- i dont understand how Sal got x squared plus 18x. i understand where he got the 81, but i got lost after that. please help!(7 votes)
- He multiplied the binomials. The x squared came from multiplying the one x by the other in the second binomial. Sal multiplied the 9 and the x from one binomial, and the x and the 9 from the other binomial, and got 9x twice. Since they have a variable of the same degree, you can add them. 9x + 9x = 18x With the 81 which came from multiplying the two 9's, Sal got x^2+18x+81. Hope this was helpful.(9 votes)

- expand and simplify the following binomial : (a-2b)^4(6 votes)
- It's simply (a-2b)(a-2b)(a-2b)(a-2b).

Then if you square (a-2b) you get (a^2 - 4ab + 4b^2), then simply square that again to get (a-2b)^4... (a^2 - 4ab + 4b^2)(a^2 - 4ab + 4b^2) which is

(a^4 - 4a^3b + 4a^2b^2 - 4a^3b + 16a^2b^2 - 16ab^3 + 4a^2b^2 - 16ab^3 +16b^4)

Bare with me it looks like a lot, but when you combine like terms,you get:

(a^4 -8a^3b + 24a^2b^2 -32ab^3 + 16b^4)

NOTE: The ^2 is simply meaning squared.(1 vote)

- what is the name of the method used at1:08?(3 votes)
- Not sure what you would call it, but he goes over it in this video as well: https://www.khanacademy.org/math/algebra-basics/quadratics-polynomials-topic/multiplying-binomials-core-algebra/v/multiplication-of-polynomials(4 votes)

- If you square -1 don't you get positive one?(3 votes)
- Yes, when you square any negative integer you get its positive. In the video, he is not squaring -1, he is subtracting +1 squared. The shortcut used will always turn out as a subtraction. If this is confusing, look at the answer for this problem the long way. Hope this helps.

(2x-1)(2x+1) =

2x -1 First we multiply1 and -1.

(*)2x +1 Next we multiply 1 and 2x.

-------------

2x -1 Leaving us with 2x-1.

+ 4x^2 -2x Next we multiply 2x and -1, followed by 2x and 2x.

----------------- Leaving us with 4x^2 -2x.

4x^2 -1 When we add them together the 2x -2x cancel out,

leaving us with 4x^2 -1.(3 votes)

- why don't you just do the magic x method ?

is eaiser to do my teacher taught me that.(1 vote)- I think Sal wants us to understand, not just memorize a method.(1 vote)

- Wait, if (x+9)2 doesn't equal (x2+92) then why does (x+9)2 equal (x+9)*(x+9) which does equal (x2+92)?(2 votes)
- (x+9)*(x+9) does NOT equal (x^2 +9^2)

You have to use FOIL to multiply the factors

x*x + 9x + 9x + 81(3 votes)

- can the same method be used in squaring trinomials?(1 vote)
- Dang it. I had a very long explanation typed out, but I hit the wrong button and lost it. Suffice to say, yes. And it can be used for polynomials of any size:

(a + b + c +d)² = a² + b² + c² + d² + 2ab + 2ac + 2ad + 2bc + 2bd + 2cd

Go ahead and perform an expansion on a trinomial and prove to yourself that the pattern works.(5 votes)

- Are you sure that foil method is effective?(1 vote)
- It's a pretty effective method when it comes to multiplying binomials as it is a shortcut to tackle the problem, but if you don't like to use it or don't feel comfortable using it, then you solve the problem your way :)(4 votes)

- At9:30, why is (2x)^2 equal to 4x^2?(1 vote)
- Because (2x)^2 is the same as 2^2 * x^2. We know 2 squared is 4, so that simplifies to 4x^2. (2x)^2 is actually 2x * 2x which is 4x^2.(3 votes)

## Video transcript

And now I want to do a bunch
of examples dealing with probably the two most typical
types of polynomial multiplication that you'll see,
definitely, in algebra. And the first is just
squaring a binomial. So if I have x plus 9 squared, I
know that your temptation is going to say, oh, isn't that
x squared plus 9 squared? And I'll say, no, it isn't. You have to resist every
temptation on the planet to do this. It is not x squared
plus 9 squared. Remember, x plus 9 squared,
this is equal to x plus 9, times x plus 9. This is a multiplication of this
binomial times itself. You always need to
remember that. It's very tempting to think that
it's just x squared plus 9 squared, but no, you have
to expand it out. And now that we've expanded it
out, we can use some of the skills we learned in the last
video to actually multiply it. And just to show you that we can
do it in the way that we multiplied the trinomial last
time, let's multiply x plus 9, times x plus a magenta 9. And I'm doing it this way just
to show you when I'm multiplying by this
9 versus this x. But let's just do it. So we go 9 times 9 is 81. Put it in the constants'
place. 9 times x is 9x. Then we have-- go switch to this
x term-- we have a yellow x. x times 9x is 9x. Put it in the first
degree space. x times x is x squared. And then we add everything up. And we get x squared
plus 18x plus 81. So this is equal to x squared
plus 18x plus 81. Now you might see a little bit
of a pattern here, and I'll actually make the pattern
explicit in a second. But when you square a binomial,
what happened? You have x squared. You have this x times this
x, gives you x squared. You have the 9 times
the 9, which is 81. And then you have this term
here which is 18x. How did we get that 18x? Well, we multiplied this x times
9 to get 9x, and then we multiplied this 9 times
x to get another 9x. And then we added the two
right here to get 18x. So in general, whenever you have
a squared binomial-- let me do it this way. I'll do it in very general
terms. Let's say we have a plus b squared. Let me multiply it this way
again, just to give you the hang of it. This is equal to a plus b, times
a plus-- I'll do a green b right there. So we have to b times
b is b squared. Let's just assume that this
is a constant term. I'll put it in the b squared
right there. I'm assuming this is constant. So this would be a constant,
this would be analogous to our 81. a is a variable that we--
actually let me change that up even better. Let me make this into x plus b
squared, and we're assuming b is a constant. So it would be x plus b, times x
plus a green b, right there. So assuming b's a constant,
b times b is b squared. b times x is bx. And then we'll do
the magenta x. x times b is bx. And then x times
x is x squared. So when you add everything,
you're left with x squared plus 2bx, plus b squared. So what you see is, the end
product, what you have when you have x plus b squared, is
x squared, plus 2 times the product of x and b,
plus b squared. So given that pattern, let's
do a bunch more of these. And I'm going to do
it the fast way. So 3x minus 7 squared. Let's just remember
what I told you. Just don't remember it, in the
back of your mind, you should know why it makes sense. If I were to multiply this
out, do the distributive property twice, you know you'll
get the same answer. So this is going to be equal
to 3x squared, plus 2 times 3x, times negative 7. Right? We know that it's 2 times each
the product of these terms, plus negative 7 squared. And if we use our product rules
here, 3x squared is the same thing as 9x squared. This right here, you're going
to have a 2 times a 3, which is 6, times a negative 7,
which is negative 42x. And then a negative 7
squared is plus 49. That was the fast way. And just to make sure that I'm
not doing something bizarre, let me do it the slow
way for you. 3x minus 7, times 3x minus 7. Negative 7 times negative
7 is positive 49. Negative 7 times 3x
is negative 21x. 3x times negative 7
is negative 21x. 3x times 3x is 9 x squared. Scroll to the left
a little bit. Add everything. You're left with 9x squared,
minus 42x, plus 49. So we did indeed get
the same answer. Let's do one more, and we'll
do it the fast way. So if we have 8x minus 3--
actually, let me do one which has more variables in it. Let's say we had 4x squared plus
y squared, and we wanted to square that. Well, same idea. This is going to be equal to
this term squared, 4x squared, squared, plus 2 times the
product of both terms, 2 times 4x squared times y
squared, plus y squared, this term, squared. And what's this going
to be equal to? This is going to be equal to
16-- right, 4 squared is 16-- x squared, squared, that's 2
times 2, so it's x to the fourth power. And then plus, 2 times
4 times 1, that's 8x squared y squared. And then y squared, squared,
is y to the fourth. Now, we've been dealing with
squaring a binomial. The next example I want to show
you is when I take the product of a sum and
a difference. And this one actually comes
out pretty neat. So I'm going to do a very
general one for you. Let's just do a plus
b, times a minus b. So what's this going
to be equal to? This is going to be equal to a
times a-- let me make these actually in different colors--
so a minus b, just like that. So it's going to be this green
a times this magenta a, a times a, plus, or maybe I should
say minus, the green a times this b. I got the minus from
right there. And then we're going to have the
green b, so plus the green b times the magenta a. I'm just multiplying every
term by every term. And then finally minus the green
b-- that's where the minus is coming from--
minus the green b times the magenta b. And what is this going
to be equal to? This is going to be equal
to a squared, and then this is minus ab. This could be rewritten as
plus ab, and then we have minus b squared. These right here cancel out,
minus ab plus ab, so you're just left with a squared
minus b squared. Which is a really neat
result because it really simplifies things. So let's use that notion to
do some multiplication. So if we say 2x minus
1, times 2x plus 1. Well, these are the
same thing. The 2x plus 1, you could view
this as, if you like, a plus b, and the 2x minus 1, you can
view it as a minus b, where this is a, and that b is 1. This is b. That is a. Just using this pattern that
we figured out just now. So what is this going
to be equal to? It's going to be a squared, it's
going to be 2x squared, minus b squared, minus
1 squared. 2x squared is 4x squared. 1 squared is just
1, so minus 1. So it's going to be 4x
squared minus 1. Let's do one more of these,
just to really hit the point home. I'll just focus on
multiplication right now. If I have 5a minus 2b, and
I'm multiplying that times 5a plus 2b. And remember, this only applies
when I have at a product of a sum and
a difference. That's the only time that
I can use this. And I've shown you why. And if you're ever in doubt,
just multiply it out. It'll take you a little
bit longer. And you'll see the terms
canceling out. You can't do this for just any
binomial multiplication. You saw that earlier in the
video, when we were multiplying, when we were
taking squares. So this is going to be, using
the pattern, it's going to be 5a squared minus 2b squared,
which is equal to 25 a squared minus 4b squared. And, well, I'll leave it there,
and I'll see you in the next video.