# Line slope calculator 6x+y=36

**Straight line given by points A[5; 6] and B[6; 0]**

## Calculation:

**Slope-intercept form of line:**y = -6x+36

**Canonical form of the line equation:**6x+y-36 = 0

**Parametric form of the line equation:**

x = t+5

y = -6t+6 ; t ∈ R

**Slope:**m = -6

**Slope angle of line: φ =**-80°32'16″ = -1.4056 rad

**X intercept:**x

_{0}= 6

**Y intercept:**y

_{0}= q = 36

**Distance line from the origin:**d

_{0}= 5.9184

**The length of the segment AB: |AB| =**6.0828

**Vector: AB =**(1; -6)

**Normal vector: n =**(6; 1)

**Midpoint of the segment AB: M =**[5.5; 3]

**Perpendicular Bisector equation:**x-6y+12.5 = 0

**Vector OA = (5; 6) ; |OA| = 7.8102**

**Vector OB = (6; 0) ; |OB| = 6**

**Scalar product OA .OB = 30**

**Angle ∠ AOB = 50°11'40″ = 0.8761 rad**