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Parabolas and their quadratic equations

What you should be familiar with before taking this lesson

What you will learn in this lesson

So far you worked with graphs of linear equations, which have the shape of a straight line. In this lesson, you will learn about the graphs of quadratic equations, which have a different shape that we call a parabola.
You will learn about the main features of parabolas and the way they relate to the quadratic equations that define them.

The graph of y=x2

Here is the graph of y=x2 with a few of its points highlighted.
Let's note a few of the graph's prominent features:

1. It is U-shaped

This curvy shape is shared by all graphs of quadratic functions, and it is what we call a parabola.

2. It has a minimum point at (0,0)

This point, the tip of the U-shape, is what we call the vertex of the parabola.
This minimum point is at (0,0) because for any non-zero x-value (both positive and negative), x2>0. Only for x=0, we have y=02=0.

3. It is symmetrical about the y-axis

In other words, we can fold the graph across the y-axis and both halves would match exactly. We call this line the axis of symmetry of the parabola.
y=x2 is symmetrical about the y-axis because the square of any number is equal to the square of its opposite number.

Parabolas with vertical shifts

Here is the parabola y=x24 with a few of its points highlighted.
This graph has the exact same shape as the graph of y=x2, but it is located 4 units below it. For example, the x-coordinate of the vertex is still 0, but the y-coordinate is now 4 instead of 0.
This is because for every x-value, y=x24 assigns a y-value that is exactly 4 units less than x2, which is what y=x2 assigns.
The graph is still symmetrical about the y-axis. Specifically, note that both x=2 and x=2 correspond to y=0. In other words, both (2,0) and (2,0) are x-intercepts of the graph. Unlike linear graphs, parabolas can have two x-intercepts!
Here is the parabola y=x2+4 with a few of its points highlighted.
This parabola is the same as y=x2, only 4 units above it. Specifically, its vertex is at (0,4).
Another interesting thing to note is that this parabola has no x-intercepts at all.

Putting things together

  • For any number k, the parabola y=x2+k is located |k| units above the parabola y=x2 (if k>0) or |k| units below it (if k<0).
  • Specifically, the vertex of the parabola is at (0,k).
  • No matter what k is, the axis of symmetry is always the y-axis.
Now check your understanding with some practice questions.
Which of the following graphs can be the graph of y=x25 ?
Choose 1 answer:

Choose the equation that corresponds to the graph.
Choose 1 answer:

What is the vertex of y=x2+7?
Choose 1 answer:

Parabolas with horizontal shifts

Here is the parabola y=(x3)2 with a few of its points highlighted.
This graph is also a parabola, but it is located 3 units to the right from y=x2. For example, the y-coordinate of the vertex is still 0, but the x-coordinate is now 3 instead of 0.
This is because for every y-value, y=(x3)2 assigns x-values that are 3 units greater than what y=x2 would assign to that same y-value.
Another thing that was shifted 3 units to the right is the parabola's axis of symmetry, which is now the line x=3.
Here is the parabola y=(x+5)2 with a few of its points highlighted.
In this parabola, everything is shifted 5 units to the left.

Putting things together

  • For any number h, the parabola y=(xh)2 is located |h| units to the right of the parabola y=x2 (if k>0) or |k| units to the left of it it (if k<0).
  • Specifically, the vertex of the parabola is at (h,0) and the axis of symmetry is x=h.
Now check your understanding with some practice questions.
Which of the following graphs can be the graph of y=(x6)2 ?
Choose 1 answer:

Choose the equation that corresponds to the graph.
Choose 1 answer:

What is the vertex of y=(x+7)2?
Choose 1 answer:

Parabolas with vertical and horizontal shifts

Let's put everything we learned so far together, by considering the general parabola y=(xh)2+k:
  • it is U-shaped,
  • its vertex is at (h,k), and
  • its axis of symmetry is the line x=h.
Let's have a little practice with that before moving on.
Which of the following graphs can be the graph of y=(x4)24 ?
Choose 1 answer:

Parabolas with vertical reflections

Here is the parabola y=x2 with a few of its points highlighted.
Note that the graph is still U-shaped, but now it's turned upside down (you can say it's -shaped). It is the exact reflection of y=x2 over the x-axis.
The vertex of this parabola is (0,0), like the parabola y=x2, only now this vertex is the maximum point of the graph. The axis of symmetry remains unchanged as well, the line x=0.
Here is the parabola y=(x3)2+5 with a few of its points highlighted.
We can see this graph as a result of the following transformations on y=x2:
  • a shift to the right by 3 units, resulting ni the equation y=(x3)2,
  • a vertical reflection across the x-axis, resulting in the equation y=(x3)2, and
  • a shift up by 5 units, resulting in the equation y=(x3)2+5.
Because of the above transformations, the graph of y=(x3)2+5 has the following properties:
  • it opens down (),
  • its vertex is at (3,5), and
  • its axis of symmetry is the line x=3.

Stretched and compressed parabolas

Here are the parabolas y=x2, y=2x2, and y=12x2.
The parabola y=2x2 seems like y=x2 was stretched vertically. This is because for any x-value, y=2x2 assigns a y-value which is twice the y-value assigned by y=x2.
For similar reasons, the parabola y=12x2 seems like a vertical compression of y=x2.
This can be made general by thinking about the parabola y=ax2:
  • If |a|>1, the parabola is a vertical stretch of y=x2, and the greater |a| is, the more the parabola is stretched.
  • If |a|<1, the parabola is a vertical compression of y=x2, and the smaller |a| is, the more the parabola is compressed.

Conclusion

Everything we learned here can be summarized by considering the most general parabola of them all, y=a(xh)2+k:
  • If a>0 the parabola opens up (), and if a<0 the parabola opens down ().
  • If |a|>1 the parabola is stretched vertically, and if |a|<1 the parabola is compressed vertically.
  • The vertex is at (h,k).
  • The axis of symmetry is the line x=h.
Now let's practice everything together.

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