For this question:If the last two cars washed receive the same kind of wash as each other, then which one of the following could be true? How was it deduced that the last two cars received super washes?? I understood everything else except for how this was derived. Could someone else explain TY

We know from the initial rules that exactly one car gets a premium wash, so that's excluded right away - neither 4 nor 5 is premium in this question. We also determined, as shown in the diagrams, that 2 and 3 MUST be regular. Since there is exactly one premium wash, and only car 1 is left, car 1 must be premium. That leaves us with 1-P, 2-R, 3-R and 4 and 5 being identical. Since we need at least one super as well, they must both be super.

When it says, "(C) must be true. In our diagram, Marquitta is 3rd and Taishah is 4th or 5th—so Taishah must be after Marquitta," I think it should actually (C) must be false, since answer choice (C) states "(C) Taishah's car is washed before Marquitta's car." I think it was just a typo, since answer choice (B) was already noted as the only could be true answer.

I agree. Option C asks if T can come before M. In the explanation, it says it MUST be true, followed by an explanation as to why it CANNOT be true.

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Course: LSAT > Unit 1

Lesson 3: Analytical Reasoning – Articles

How to approach mixed setups

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Mixed setups overview

You will see at least one mixed setup on Test Day. Many students feel intimidated by them because they seem more difficult than pure ordering/grouping setups—and sometimes they are! But they’re manageable with practice and patience. In this article, we’ll examine mixed setups and share some tips to raise your game and boost your score.

Note: If you have not yet consulted the articles and overview videos on Ordering Setups and Grouping Setups, we strongly recommend that you work through those articles and videos before continuing with this one, as the foundations of ordering and grouping are critical to success in mixed setups.

Ordering setups overview article

Ordering setup video lesson

Grouping setups overview article

Grouping setup video lesson

How do we recognize mixed setups?

Mixed setups typically involve more than one task; for example, an ordering setup with a grouping component is a mixed setup. A setup with two sets of elements to be grouped is a mixed setup. A setup with two sets of elements to be ordered and a grouping component is a mixed setup (and sounds like a formidable one!). Note that mixed setups, in comparison to ordering setups, have quite a bit more variety in how they’re presented to you, since so many combinations are possible.

Sometimes, a mixed setup can involve some kind of relationship or relationships other than ordering and grouping—you'll hear us refer to this as an "atypical setup" since they're rarer.

A few examples of mixed tasks:

Determine which days 7 employees will have their annual review, and whether each employee is part-time or full-time (ordering + grouping—this is one of the most common types of mixed setups).
Determine which 5 students (out of 8 students) make the swim team, and in what order they will swim on Saturday (“in/out” grouping + ordering).
Determine which sport each of 8 children play, and we’re told what color shirt each child will wear (grouping + grouping).
Determine which sport each of 8 children play, and what color shirt each child will wear, and what time each child’s game is (grouping + grouping + ordering).
Atypical: Determine who's in the final cast of a play after 5 rounds of auditions that follow a certain process of elimination.

You may be able to see the challenge that mixed setups present: there are more types of elements and actions to keep track of! Don’t worry, though—we’ll help you stay organized and focused so that you maintain control and so that you don’t feel like you’re “guessing.”

What should we pay attention to in the passage?

In the passage for a mixed setup, you’ll see more information (and more complex information) than what you’d see in the passage for a typical ordering setup, for example.
There will be at least two types of elements—for example, students ABCDEF and sports tennis, hockey, and golf.
You will often see restrictions, such as, “Each sport is played by a maximum of three students”, and it’s imperative to pay close attention to such restrictions. “Exactly three students per sport” has a very different impact on the setup than “a maximum of three students per sport”, for example.

What does the sketch look like for a mixed setup?

In general, it’s good to represent what’s happening in the setup with a diagram or sketch. The diagrams of mixed setups can be quite varied, since mixed setups are much more diverse in their tasks than ordering setups, for example.

One recommendation we can give you is that if the mixed setup includes an ordering component, then it often helps to “prioritize” that ordering component in the diagram—that’s because ordering involves some kind of spatial arrangement. Another “strong” action is that of grouping elements into “in” and “out” categories—it often helps to prioritize that in your sketch as well.

We’ll show you a few different setups here, to render this somewhat abstract information more concrete!

Ordering + grouping:

Suppose we have a task in which employees ABCDEF will have their performance review on the 1st through 6th day of the month, and we also need to determine whether each employee is part-time or full-time. Your empty diagram (before establishing any rules or deductions) might look like this:

Notice that any rule that purely groups elements (for example, “C is a part-time employee”) will need to be noted off to the side. That’s because the diagram prioritizes the ordering portion of the mixed setup.
The top line of our diagram is where the employees will be noted, which is why we wrote the list of elements ABCDEF to the left of the top line.
The bottom row of the diagram is for the part-time and full-time designations.

In/Out grouping + sequencing:

Suppose we have a task in which 5 out of 8 students ABCDEFGH are selected to be part of a 5-person swim team. Additionally, they will each swim one at a time from 1 pm to 5 pm.
Here are two options that you can use. Note that the first option (if we were to remove the blank slots) would be used in a situation in which you aren’t told exactly how many students make the swim team, whereas either the first or second option could be used if you know exactly how many students make the swim team (as in the example we just gave):

Note that the order of the elements in the Out column doesn’t matter! Ordering only applies to the students who make the swim team. That concept is somewhat clearer in the second version of the diagram above.
You can anticipate that some of the rules will focus on the ordering component of this task, and other rules will focus on the grouping component of the task.
Prepare yourself for several rules in this particular type of mixed setup (i.e., one that has an “in/out” grouping component) to be conditional rules. That means you’ll want to know how to form logically equivalent rules (such as the version called the “contrapositive”) in order to be accurate and efficient.
A helpful article on forming logically equivalent rules can be found here.

Grouping + grouping

Suppose we have a task in which eight students (ABCDEFGH) will play one of three sports (Tennis, Rugby, and Soccer ). We’re also given information in the passage that students A, B, and C wear yellow shirts, students D, E, and F wear orange shirts, and students G and H wear magenta shirts.
Depending on how neat your handwriting is and what your preference is, you could list the colors and students in a few different ways. Your empty diagram (before establishing any rules or deductions) might look like this:

If you prefer not to use subscripts due to handwriting or clarity, you could also list the players in this way:

Note that we didn’t draw any blanks under the sports groups, because we weren’t told that each sport is played. In other words, it could be that all eight students play Tennis.
Let’s say that you’re given a rule that states: “At least one student wearing a yellow shirt plays Rugby." In that case, you could represent that rule this way:

You could then make the deduction that either A, B, or C must play Rugby, and we’d likely encounter additional rules that would narrow those options down even further.
You can anticipate that some of the rules will address which students play (or don’t play) which sports, and that other rules will address which sports are played by students wearing certain colors. Stay organized and neat with your notes!

What kind of rules are typical in mixed setups?

Since mixed setups involve several different actions (such as grouping + ordering), you can anticipate that some of the rules will be typical of one type of action, and other rules will be typical of the other type(s) of action. Less frequently, some rules will treat multiple actions at the same time. Review the articles on Ordering and Grouping setups if you want to refresh on what the typical rules for each type of setup are.

It’s important to manage the rules well so that you don’t feel overwhelmed. There will be a fair amount of off-to-the-side notation that you’ll be able to combine for deductions later, so be patient as you go through the rules—and make sure you get the rules right the first time!

Practice Example

Now, let’s take everything we’ve learned and apply it to an actual LSAT setup!

Exactly five cars—Frank's, Marquitta's, Orlando's, Taishah's, and Vinquetta's—are washed, each exactly once. The cars are washed one at a time, with each receiving exactly one kind of wash: regular, super, or premium. The following conditions must apply:

The first car washed does not receive a super wash, though at least one car does.

Exactly one car receives a premium wash.

The second and third cars washed receive the same kind of wash as each other.

Neither Orlando's nor Taishah's is washed before Vinquetta's.

Marquitta's is washed before Frank's, but after Orlando's.

Marquitta's and the car washed immediately before Marquitta's receive regular washes.

What does the setup tell us?

We have five car owners whose cars are washed exactly once, one at a time—that indicates an ordering task. Since we’re also told that each car will receive exactly one kind of wash, then that’s a grouping task! In other words, cars are “grouped” into regular, super, or premium washes. Therefore, this is a mixed scenario—go ahead and make a basic sketch based on this information before we look at the rules!

You may have created something like this for your sketch:

Now, go ahead and note the rules, making sure to take the time to understand them! What do your notes look like?

What do the rules tell us?

Go through the rules one at a time, making sure to get the rules right the first time. Include the rule directly in the diagram if it makes sense to; otherwise, note the rule off to the side.

If you followed our notation suggestions from the Ordering and Grouping articles, your notes could look like this. If you used your own and they make sense to you—great!

Check the rules summary if you aren't sure how we arrived at a certain notation.

Rule 1: The 1st car is not a super wash, but at least one car does receive a super wash. We noted the first part of this rule directly in the diagram, and the second part of the rule off to the side.
Rule 2: Exactly one car receives a premium wash. Since we don’t know which car that is, we noted this off to the side.
Rule 3: The 2nd and 3rd cars receive the same kind of wash as each other. There are a number of ways to note this, but we like to note directly in the diagram wherever possible—we’ve chosen to use two identical squares to indicate that the two spots are the same kind of wash.
Rule 4: Neither Orlando nor Taishah are before Vinquetta, so that means that they’re both after Vinquetta! We noted this off to the side.
Rule 5: Marquitta is sometime before Frank, and Marquitta is sometime after Orlando. This gives us a chain that we can mark below the diagram: O...M...F.
Rule 6: Marquitta’s car and the car immediately before Marquitta’s both receive regular washes. That doesn’t mean that these are the only two to receive regular washes, but we can make a note that indicates this ordering and grouping relationsihp.

What can we deduce?

Now it’s time to make deductions! Can you use what we covered in the Ordering and Grouping articles in order to deduce what must be true, beyond what’s presented to us at face value?

Since the 1st car can’t get a super wash (Rule 1), then it must be either premium or regular. We can note that as a positive deduction in the diagram.
Rules 4 and 5 can be nicely combined, since they both involve Orlando. We can make a longer, branching chain:

This tells us a lot, because all five car owners are represented in the chain! Careful with Taishah, though: Taishah only has a relationship with Vinquetta. That means that Taishah can be in any position except 1st (so far).

The only owner who could be 1st is Vinquetta; the deduction chain shows that all other owners are sometime after Vinquetta. We can establish Vinquetta 1st in the diagram.
Moving to the other end of the chain, we see that the only owners who could be last (5th) are Frank and Taishah, so we can establish that as a positive deduction in the diagram as well.
Since the 4th owner could be either Marquitta, Frank, or Taishah, we’re looking at too many possibilities; let’s move to the beginning of the chain again.
The 2nd owner could only be Orlando or Taishah, so let’s note that.
Here’s what we have so far:

Now that we’ve made some key deductions, we can do something really interesting and useful!
Looking at our rules, we haven’t done anything with Rule 6, that Marquitte’s car and the car immediately before Marquitte’s car gets a regular wash.
Now, looking at our diagram so far, we can only see two spots where Marquitte could go! That means that we can build two scenarios around Marquitte and the regular washes associated with Marquitte:

Now, can you make the appropriate deductions for each scenario?

Scenario 1: Marquitte is 3rd.

Since Marquitte is 3rd in this case, then only Orlando can be 2nd (because of the V-O-M part of the main chain).
The 2nd and 3rd cars must get a regular wash, since Marquitte is 3rd and gets a regular wash (Rule 6).
We can also deduce that Frank and Taishah are 4th and 5th, but we don’t know in what order:

Scenario 2: Marquitte is 4th.

In this case, the 3rd and 4th washes are regular washes, since Marquitte is 4th (Rule 6).
We can deduce that the 2nd car also gets a regular wash, since the 2nd and 3rd cars must get the same kind of wash (Rule 3).
That means that the 1st car can’t get a regular wash! Why? Because if it did, then we wouldn’t have enough cars left to get one premium wash and (at least) one super wash.
So, the 1st car (Vinquitta’s car) gets a premium wash, and
The 5th car gets a super wash.
Since Marquitte is 4th in this scenario, then Frank must be 5th (because of the O-M-F part of the main chain).
The 2nd and 3rd cars must be either Orlando’s or Taishah’s, based on our main chain:

Here’s an example of an initial diagram for this setup, based on what we uncovered:

We’re in a really great spot to move on to the questions! With our initial diagram, we won’t have to use much (if any) of the “trial and error” that would consume a ton of time on Test Day.

We strongly recommend against using this initial diagram to “test” choices or sketch possibilities. It’s generally better for accuracy purposes (even if it takes a tiny bit more time!) to do a quick re-sketch when a question provides you with a new condition to consider.

What “new condition” questions present are temporary conditions. You likely don’t want to mix temporary conditions with permanent conditions. That said, you don’t need to resketch the entire initial diagram for each “new condition” question; using a bare-bones version while you simultaneously consult the original version can work great.

Which one of the following could be an accurate list of the cars in the order in which they are washed, matched with type of wash received?

(A) Orlando's: premium; Vinquetta's: regular; Taishah's: regular; Marquitta's: regular; Frank's: super
(B) Vinquetta's: premium; Orlando's: regular; Taishah's: regular; Marquitta's: regular; Frank's: super
(C) Vinquetta's: regular; Marquitta's: regular; Taishah's: regular; Orlando's: super; Frank's: premium
(D) Vinquetta's: super; Orlando's: regular; Marquitta's: regular; Frank's: regular; Taishah's: super
(E) Vinquetta's: premium; Orlando's: regular; Marquitta's: regular; Frank's: regular; Taishah's: regular

One approach that tends to be very efficient might seem a little counterintuitive at first. Instead of looking at each choice and evaluating it against all of the rules, it makes sense to look at each rule one at a time and eliminate the choices that violate that rule. Think about it this way: if the answer is (E), then looking at each choice first means going through all of the rules five times. But if you start with the rules and eliminate choices after looking at each rule, then you only have to go through the rules once!

What choice(s) does each rule eliminate when you evaluate each rule one at a time? Let’s take a look at them together!

Rule 1: The 1st car is not a super wash, but at least one car does receive a super wash. (D) and (E) each break a different part of this rule, so we can eliminate (D) and (E).
Rule 2: Exactly one car receives a premium wash. None of the remaining choices violates this rule.
Rule 3: The 2nd and 3rd cars receive the same kind of wash as each other. No remaining choices break this rule.
Rule 4: Vinquetta is before both Orlando and Taishah. We can cross off (A).
Rule 5: O...M...F. Choice (C) violates this rule.

The only choice remaining is (B), so that’s our answer!

If Vinquetta's car does not receive a premium wash, which one of the following must be true?

(A) Orlando's and Vinquetta's cars receive the same kind of wash as each other.
(B) Marquitta's and Taishah's cars receive the same kind of wash as each other.
(C) The fourth car washed receives a premium wash.
(D) Orlando's car is washed third.
(E) Marquitta's car is washed fourth.

This question gives us a new and temporary rule to apply. This temporary rule won’t conflict with any of our original rules, and we’re meant to determine the consequences of considering this new rule. Then we’ll identify the choice that must be true.

Important note for you: since we built two scenarios for this setup, you’ll want to first decide which scenario allows this condition to take place. It could be one scenario, or it could be both. The choice that must be true is the choice that’s true in all applicable scenarios.

Which scenario allows this question’s condition to be true?

Only Scenario 1 allows Vinquetta’s car to not receive a premium wash. When given a new condition, it usually makes sense to re-draw a bare-bones sketch of the appropriate diagram (in this case, Scenario 1) and incorporate the new condition that Vinquetta doesn’t get a premium wash. So, since we deduced early on that Vinquetta gets either a premium or a regular wash, but for this question, Vinquetta doesn’t get a premium wash, we can determine that Vinquetta gets a regular wash:

Now, can you use this new diagram to make further deductions? In other words, what is the impact of Scenario 1 being the only active scenario and Vinquetta* getting a *regular*** wash?

Since three cars now get a regular wash, that means that one premium wash and one super wash must be 4th and 5th, in some order.
We don’t have enough information to determine anything beyond this, so we’re at the end of our deductions:

We should be able to find the answer from this diagram! Can you identify which statement must be true?

(A) must be true! We deduced that Vinquetta gets a regular wash and Orlando gets regular wash in Scenario 1 (the only scenario that allows this question’s new condition to apply).

On Test Day, we would stop there, select (A), and move on—there can’t be two correct choices on the LSAT! Here are the explanations for the remaining choices:

(B) must be false! We know that Marquitta gets a regular wash, and whether Taishah is 4th or 5th, Taishah will not get a regular wash.
(C) could be true, but it could also be false. The 4th car gets either a premium or a super wash.
(D) must be false. In Scenario 1 (the only scenario that’s usable for this question), Orlando’s car is 2nd, not 3rd.
(E) must be false. In Scenario 1 (the only scenario that’s usable for this question), Marquitta’s car is 3rd, not 4th.

Great job! We determined which scenario applies, incorporated the new condition, and used the setup rules to make further deductions.

If the last two cars washed receive the same kind of wash as each other, then which one of the following could be true?

(A) Orlando's car is washed third.
(B) Taishah's car is washed fifth.
(C) Taishah's car is washed before Marquitta's car.
(D) Vinquetta's car receives a regular wash.
(E) Exactly one car receives a super wash.

Only Scenario 1 allows cars 4 and 5 to receive the same kind of wash. When given a new condition, it usually makes sense to re-draw a bare-bones sketch of the appropriate diagram (in this case, Scenario 1) and incorporate the new condition. We’ll use squares to show that the two washes are of the same type:

Now, can you use this new diagram to make further deductions? In other words, what is the impact of Scenario 1 being the only active scenario and the last two cars getting the same kind of wash?

The 4th and 5th cars must get a super wash. Why? We can’t have more than one car that gets a premium wash (Rule 2), and if the last two cars got a regular wash, then no car would be able to get a super wash.
Since cars 2 and 3 get regular washes and we just deduced that cars 4 and 5 get super washes, then Vinquetta’s car (car 1) must get the premium wash.
We’re at the end of our deductions:

We should be able to find the answer from this diagram! Which statement could be true?

(A) must be false. In our diagram for this question, Orlando is 2nd, not 3rd.
(B) could be true! We deduced that Taishah could be 4th or 5th.

On Test Day, we would stop there, select (B), and move on—it can feel scary to not look at all of the remaining choices, but have confidence in the work that you did! Good work and confidence will save you the time that uncertain students spend checking the wrong choices after finding the answer. Here are the explanations for the remaining choices:

(C) must be false. In our diagram, Marquitta is 3rd and Taishah is 4th or 5th—so Taishah must be after Marquitta.
(D) must be false. Vinquetta’s car gets a premium wash, not a regular wash.
(E) must be false. We deduced that the last twocars receive a super wash.

(B) is the answer!

Good work! Once again, we determined which scenario applies, incorporated the new condition into that scenario, and used the setup rules to make further deductions.

Which one of the following must be true?

(A) Vinquetta's car receives a premium wash.
(B) Exactly two cars receive a super wash.
(C) The fifth car washed receives a super wash.
(D) The fourth car washed receives a super wash.
(E) The second car washed receives a regular wash.

First, we’d want to look at our initial diagram and see if the answer is apparent there, by comparing the choices against the diagram. If that doesn’t work, we’d need to test each choice to see which statements could be false. Let’s hope the first way works, because it’s much less time-consuming!

(A) is true in Scenario 2, but it doesn’t have to be true. It could be false in Scenario 1, where it’s possible for Vinquetta’s car to receive a regular wash.
(B) could be false at first glance—in Scenario 2, exactly one car receives a super wash, so we don’t need to check Scenario 1!
(C) is true in Scenario 2, but it doesn’t have to be true. In Scenario 1, the 5th car washed could receive any of the three types of washes.
(D) could be false at first glance—in Scenario 2, the 4th car receives a regular wash, so we don’t need to look at Scenario 1.

At this point, many students start getting nervous, because they’re worried that choice (E) will also be wrong, and they’ll have to start over. Again, have confidence in the work that you did! If we set the task up correctly and analyzed each choice well, then (E) should be the answer.

(E) must be true! In both scenarios, the 2nd car gets a regular wash. We did it!

Let’s say the choices weren’t as clear to evaluate as these. For a must be true question, you would need to quickly test each choice with your pencil, making the statements be false—if you can create a scenario that works even when the statement is false, then the choice is wrong. If you can’t create a scenario that works, then you have your answer!

Which one of the following is a complete and accurate list of the cars that must receive a regular wash?

(A) Frank's, Marquitta's
(B) Marquitta's, Orlando's
(C) Marquitta's, Orlando's, Taishah's
(D) Marquitta's, Taishah's
(E) Marquitta's, Vinquetta's

First, we’d want to look at our initial diagram and make a prediction. We should be able to clearly see which cars must receive a regular wash in both scenarios. If we can’t do that, then we’d have to start testing the choices by pencil.

What can we deduce?

In Scenario 1, the cars belonging to Orlando and Marquitta must receive a regular wash.
In Scenario 2, Marquitta again must get a regular wash, and Orlando does too! Why? Even though we don’t know exactly where in the order Orlando’s car is, we know that it’s either 2nd or 3rd. We also know that both the 2nd and 3rd car receive regular washes!

Which choice matches our prediction?

Use your initial diagram and knowledge of the rules to predict the answer and find the choice efficiently!

(A) This isn’t accurate or complete. Our diagram doesn’t show that Frank has to get a regular wash in either scenario.

(B) This is both accurate and complete! In both scenarios, Marquitta and Orlando get regular washes, even though we don’t know exactly where in the order Orlando falls in Scenario 2.

(D) This is neither complete nor accurate. Taishah doesn’t have to get a regular wash, and the list is missing Orlando, who does have to get a regular wash.

(E) This is neither complete nor accurate. Vinquetta doesn’t have to get a regular wash, and the list is missing Orlando, who does have to get a regular wash.

Takeaways

Keep the “actions” (grouping + ordering, for example) separate in your mind as you work through the rules and deductions. Notice which action(s) a given rule attends to.
There is no one “magic diagram” that is uniformly correct for mixed setups. The key is to make sure that the diagram reflects the actions of the task in a clear way.
Be patient and diligent! The fundamentals of pure ordering setups and pure grouping setups still apply more than ever—mixed setups are simply a way of testing your ability to stay organized.

Next steps

Watch a demonstration of how to approach a mixed setup

Then, once you've finished your diagnostics and created a practice schedule, head over to the practice area and try some mixed setups on your own!

Want to join the conversation?

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naqsha.biliangady
Posted 5 years ago. Direct link to naqsha.biliangady's post “I have a question about t...”
I have a question about timing-- what is the ideal amount of time to spend on each setup? Can it be equally divided? 8.5 minutes each setup. And how should this time be divided? How much time should be devoted to deductions and drawing?
TIA!
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(11 votes)
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valdezcyn
Posted 6 years ago. Direct link to valdezcyn's post “For this question:If the ...”
For this question:If the last two cars washed receive the same kind of wash as each other, then which one of the following could be true?

How was it deduced that the last two cars received super washes?? I understood everything else except for how this was derived. Could someone else explain
TY
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(2 votes)
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- b t
  Posted 6 years ago. Direct link to b t's post “We know from the initial ...”
  We know from the initial rules that exactly one car gets a premium wash, so that's excluded right away - neither 4 nor 5 is premium in this question. We also determined, as shown in the diagrams, that 2 and 3 MUST be regular. Since there is exactly one premium wash, and only car 1 is left, car 1 must be premium. That leaves us with 1-P, 2-R, 3-R and 4 and 5 being identical. Since we need at least one super as well, they must both be super.
  Comment on b t's post “We know from the initial ...”
  (5 votes)
Ryan
Posted 6 years ago. Direct link to Ryan's post “When it says, "(C) must b...”
When it says, "(C) must be true. In our diagram, Marquitta is 3rd and Taishah is 4th or 5th—so Taishah must be after Marquitta," I think it should actually (C) must be false, since answer choice (C) states "(C) Taishah's car is washed before Marquitta's car." I think it was just a typo, since answer choice (B) was already noted as the only could be true answer.
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(2 votes)
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- Scott Chrisman
  Posted 6 years ago. Direct link to Scott Chrisman's post “I agree. Option C asks if...”
  I agree. Option C asks if T can come before M. In the explanation, it says it MUST be true, followed by an explanation as to why it CANNOT be true.
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  (2 votes)
Jalah Falcher
Posted 3 years ago. Direct link to Jalah Falcher's post “Can you give us an exampl...”
Can you give us an example of the Grouping + Grouping + Ordering Set Up?
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Cassady Tercek
Posted a year ago. Direct link to Cassady Tercek's post “Why can the second spot o...”
Why can the second spot only be O/T?
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(1 vote)
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LSAT