If you're seeing this message, it means we're having trouble loading external resources on our website.

If you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked.

Main content

Select problems from miscellaneous exercise

Solutions of a few selected problems from miscellaneous exercise on Chapter 2.
In this article we will look at solutions of a few selected problems from miscellaneous exercise on chapter 2 of NCERT.
Problem 1:
Let f={(x,x21+x2):xR} be a function from R into R. Determine the range of f.
Note: R is the set of real numbers.
Solution:
Remember that range is the set of all outputs of a function. Here,
f(x)=x21+x2
The input x can take any real value. The question is, as x varies across R, what values does the function take?
Look at the expression x21+x2. Remember x20. So, this expression
Choose all answers that apply:

See that the numerator and denominator are always positive, so the expression is always positive. Also the denominator is always greater than the numerator, so the expression is always less than 1.
Let's verify what we found above by checking the output of the function at various values of x.
xx2f(x)=x21+x2
000
0.10.010.0099
0.50.250.2
110.5
4160.9412
100100000.9999
Try this out for some negative values of x as well.
The lowest value f(x) takes is 0 at x2=0. It increases towards 1 as x2 increases. But however hard we try, we never reach exactly 1 because the denominator always stays greater than the numerator.
The function takes all values between 0 and 1, including 0 but excluding 1.
The range of f is [0,1).
Problem 2:
Let f be the subset of Z×Z defined by f={(ab,a+b):a,bZ}. Is f a function from Z to Z? Justify your answer.
Note: Z is the set of integers.
Proving something is not a function is generally much more easier than proving something is a function.
So first, let's try to prove that f is not a function. To do so, we need to match at least one input to two or more outputs.
Consider the pair (ab,a+b). Here ab is the input and a+b is the output.
Pick a input. Let's say 12. Now let's try to match this input to two (or more) outputs.
aba+b
12=2×6268
12=3×4347
12=1×1211213
See that we got multiple outputs for the same input 12.
Therefore, f is not a function.

Want to join the conversation?

No posts yet.