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Course: Class 12 > Unit 1
Lesson 8: Solutions to select NCERT problemsSelect problems from exercise 1.1
Solutions to few selected problems from exercise 1.1 NCERT class 12.
In this article we will look at solutions of a few selected problems from exercise 1.1 of NCERT.
Problem 1:
Determine whether the following relation is reflexive, symmetric and transitive:
Relation in the set as
Solution:
Let's check whether the given relation is reflexive, symmetric and transitive one-by-one.
Any number is divisible by itself. So all pairs like , etc. belong to . Thus, the relation is reflexive.
Let's see an example. The set of pairs , and belong to . This hints that is transitive.
In general, let and belong to . This means is divisible by and is divisible by . So, is divisible by . Hence the pair will also belong to . The relation is transitive.
Finally, is reflexive and transitive, but not symmetric.
Problem 2:
Show that the relation in the set of real numbers, defined as is neither reflexive nor symmetric nor transitive.
Solution:
To show that the given relation is neither reflexive nor symmetric nor transitive, we just need to find one counter-example for each case.
Consider this example.
From above, we can conclude the relation is not transitive.
Finally, is neither reflexive nor symmetric nor transitive.
Problem 3:
Show that the relation in the set given by is an equivalence relation. Show that all the elements of are related to each other and all the elements of are related to each other. But no element of is related to any element of .
A relation is an equivalence relation if it is reflexive, symmetric and transitive. Let's show that the given relation is all three one-by-one.
Let's see an example. The set of pairs , and belong to . This hints that is transitive.
In general, let and belong to .
Hence the pair will also belong to . The relation is transitive.
Finally, is an equivalence relation.
For the next part of the question, consider the two sets and .
See that the difference between any two elements of is even, and same is the case with . However, if we pick one element from and another from the difference between them will be odd, and hence they cannot relate to each other.
Problem 4:
Give an example of a relation which is
(i) Symmetric but neither reflexive nor transitive
(ii) Transitive but neither reflexive nor symmetric
(iii) Reflexive and symmetric but not transitive
(iv) Reflexive and transitive but not symmetric
(v) Symmetric and transitive but not reflexive
(ii) Transitive but neither reflexive nor symmetric
(iii) Reflexive and symmetric but not transitive
(iv) Reflexive and transitive but not symmetric
(v) Symmetric and transitive but not reflexive
Solution:
There are two ways to write examples. One is to write mathematical relations, for example, . Another way is to write a relation explicitly with all the pairs in it, for example, .
For each case given in the question, a list of relations are given below. Try and find the right examples on your own from that list. Be careful, there might me multiple correct options.
(i) Symmetric but neither reflexive nor transitive
(ii) Transitive but neither reflexive nor symmetric
(iii) Reflexive and symmetric but not transitive
(iv) Reflexive and transitive but not symmetric
(v) Symmetric and transitive but not reflexive
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- For "(v) Symmetric and transitive but not reflexive " why is "R in the set A given by R = {(1,1),(1,2),(2,1),(2,2)}" the correct answer? It is a reflexive set since (1,1) and (2,2) are elements of R.(2 votes)