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Graphing linear equations — Harder example

Watch Sal work through a harder Graphing linear equations problem.

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• The practices have no relation to these examples. So how do I do the practices?
• For me, all the practice questions had to do with finding the slope of the line. Assuming you had the same questions as I did, just count how many blocks you have to the next point on your y axis (going up). That number would be your numerator. Then count how many blocks along your x axis (going across) you have between your points and that will be your denominator. Your points are wherever your line goes right across the corner of a block. That's just how i learned it at least.
• why is the video cut short?
• Hello Test takers you've got this!!
• Its not showing the full video
• I understand how you got the answer, but shouldn't D be correct as well? If x=0 and y=1, it would give you -6=-6. Could someone clear this out for me? Thank you!
• Nasim Mahdi, The eqaution should satisfy both points, i.e. (0,1) and (6,1).
The last equation doesn't satisfy the equation.
So, second choice is only the correct choice.
I hope you are clear.
• why we multiply -3 in the end? i didn't get that
• We multiply by -3 because -3 is the slope that we found our line to have. The last step of the problem is for us to plug in our equation for g (the second line) for the point -2. The equation of a line is y = mx + b, where m is the slope, b is the y-intercept, and x and y is a coordinate on the graph. We multiply by the slope simply because we have x and want to get to y, so we should multiply by m and add b to get y. Does that make it clearer?
• around , with the fraction 1/6x .. why is it that he multiplied 6 to both sides instead of 1/6 ? i understand the key is to get x alone , so basically its 1x/6 ?
• how many methods are there for solving a quadratic equation apart from the following:
1. factoring method
2. middle term splitting
4. completing the square method