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SAT
Course: SAT > Unit 10
Lesson 4: Additional topics in math- Volume word problems — Basic example
- Volume word problems — Harder example
- Right triangle word problems — Basic example
- Right triangle word problems — Harder example
- Congruence and similarity — Basic example
- Congruence and similarity — Harder example
- Right triangle trigonometry — Basic example
- Right triangle trigonometry — Harder example
- Angles, arc lengths, and trig functions — Basic example
- Angles, arc lengths, and trig functions — Harder example
- Circle theorems — Basic example
- Circle theorems — Harder example
- Circle equations — Basic example
- Circle equations — Harder example
- Complex numbers — Basic example
- Complex numbers — Harder example
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Circle equations — Harder example
Watch Sal work through a harder Circle equations problem.
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Why h and k? Standard way of doing it?(13 votes)
I imagine that it's arbitrary. Usually, you use x and y, but since they are variables and the numbers are given, they are using h and k as constants.(2 votes)
How do u find the radius if it not simple like this problem?(8 votes)
You can always calculate the distance between the center and the point lying on the circumference (ie. the radius) by using this formula:
[(x-h)^2 + (y-k)^2]^1/2
For more info you can check out this website. It's very useful:
http://www.mathwarehouse.com/algebra/distance_formula/index.php
Hope this helps! :-)(12 votes)
- what is the circumference of a circle whose area is 100 pie(5 votes)
20 pie. The equation for the area of the circle is A= (pie)(radius^2). Using that, you can calculate that the radius of the circle is 10. The equation for the circumference of a circle is C=2(pie)(radius) or C=(pie)(diameter). Plug the radius of 10 into an equation and you should find the circumference of the circle to be 20 pie.(7 votes)
- HERE IS THE PROVIDED QUESTION:
"A circle in the xy-plane contains the points (−1,1), (1,1), and (−1,−1). Which of the following is an equation of the circle?"
HERE IS THE PROVIDED ANSWER:
The formula for a circle with a center (h,k) is:
(x−h)^2+(y−k)^2=r^2
We could check which formula is satisfied by the three given points.
Alternatively, let's substitute the three points for (x,y)
First, substituting (1,1), we have:
(1−h)^2+(1−k)^2=r^2
Substituting (−1,1), we have:
(−1−h)^2+(1−k)^2=r^2
Finally, substituting (−1,−1), we have:
(−1−h)^2+(−1−k)^2=r^2
Next, let's subtract the second equation from the first. We get:
(1−h)^2−(−1−h)^2=0
OR
h^2−2h+1−(h^2+2h+1)=0
−4h=0
h=0
Let's subtract the third equation from the second. We get:
(1−k)^2−(−1−k)^2=0
This is the same equation as that above with
k instead of h. So k=0, and the center of the circle is (0,0). Now, let's find r.
Since (1,1) is a point on the circle, and the center is (0,0), the radius is squarerootof2.
The equation of the circle is
x^2+y^2=2x OR x^2+y^2−2=0
HERE ARE MY QUESTIONS:
I don't understand how the answer was found, and I also have a few general questions:
1. Is it assumed that none three given points are the center of the circle?
Because I do not know how to write a circle equation without knowing the center. If the center is known to not be one of the three listed points, then it is obviously (0,0), but if the center IS one of the listed points, then it is (-1,1). However, I do not know if the center is included in the listed points or not, so I couldn't figure much else out without that information....
2. The provided answer talks about subtracting equations from each other like it's a normal thing. I have never encountered a situation where an equation is subtracted form another when dealing with circles... elaborate?(3 votes)
Yes, if a point lies ON the circle, then it cannot be its center. That point must be on the circle's edge. I would suggest imagining the coordinates in your head, since the provided points on the circle were very simple. It wouldn't be too difficult to visualize that the center must be (0,0) from the given points.(4 votes)
So...based on this video, can it be assumed that when the SAT says "a point on a circle," it is the radius? Like in this case it was 20?(3 votes)
A point on the circle is literally any point lying on the circumference. To get the radius, you would have to calculate the distance between that point and the circle's center. A point on the circle does NOT mean radius.
Hope this helps.(4 votes)
- Best of luck for today everyone ! Do your best !!(4 votes)
What if the x co-ordinates are different ?(2 votes)- if x co-ordinates are diff then the point will lie either inside the circle or outside circle...so another condition will be given...to justify that...point eqn...and 3 eqn will form and easily u can find the required things asked in the question..(2 votes)
- In the video, he mentions "The equation of a circle videos on khan academy" does anyone know where I can find that?(1 vote)
- https://www.khanacademy.org/math/geometry/xff63fac4:hs-geo-conic-sections/hs-geo-circle-expanded-equation/a/circle-equation-review
https://www.khanacademy.org/math/geometry/xff63fac4:hs-geo-conic-sections/hs-geo-circle-standard-equation/v/writing-standard-equation-of-circle
Hope these help! :)(2 votes)
im confused on this whole problem.(1 vote)
Video transcript
- [Instructor] A circle in the xy-plane has its center at seven comma 14. If the point seven comma
34 lies on the circle, which of the following is
an equation of the circle? Let's just remind
ourselves the general form of the equation of a circle. If any of this looks like,
looks unusual to you, you haven't seen it before,
I encourage you to watch the equation of a circle
videos on Kahn Academy. The general form for the
equation of a circle, if we have a circle that's
centered at the point h comma k, the x-coordinate of the center is h. The y-coordinate of the center is k. If it has a radius of r, so the circle is gonna
look something like that. I'm trying to draw it
as circular as I can. Man, that's not so circular. I think you get the point. The radius is r. This equation, the
equation of this circle, of all the points that are exactly r away from the point h comma k, is going to be x minus the x-coordinate
of the center squared plus y minus the y-coordinate
of the center squared is equal to the radius squared. Now in this case, we
know what our h and k is. H is seven, and k is 14, and we just need to figure out the radius. We figure that out, we
will be able to figure out the equation of the entire circle. Now, they tell us that the
center's at seven comma 14, so that point right over
there is seven comma 14, and then the point seven comma
34 also lies on the circle, so it has the same x-coordinate. Its y-coordinate is just
higher, so this might be, that right over there might
be the point seven comma 34. It would be right above it. We just increased our y
without changing our x. So, seven comma 14 is the center. This point right over
here is seven comma 34, lies on the circle, so
the circle is gonna look something like this, and so
the radius of this circle, what we have to figure
out, is just the distance between these two points. These two points, you don't
even have to really apply the distance formula
or anything like this. The distance here is just our change in y. Our x doesn't change. It's gonna be 34 minus 14. So, the radius here is equal to 20. So, now we know. We know h is equal to seven. K is equal to 14, and r is equal to 20. So, it's gonna be x minus
h, x minus seven squared plus y minus k, y minus 14 squared is equal to r squared. 20 squared is 400. So let's see, that is this
choice right over here. X minus seven squared
plus y minus 14 squared is equal to 400, and we're done.