If you're seeing this message, it means we're having trouble loading external resources on our website.

If you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked.

Main content


Course: MCAT > Unit 3

Lesson 1: Chemical and physical sciences practice passage questions

Electromyography and passive filters: Circuitry in action


Electromyography, or EMG, is a means of measuring electric potentials produced by a person’s muscles in order to determine if there are any abnormalities within the muscle, such as neuromuscular disease. Various electric properties can be measured via electrodes placed in a muscle, including the amplitude and the duration of an action potential. Additionally, an EMG will not record any electrical activity when a muscle is at rest, so the presence of electrical activity can be a sign of pathology as well.
To perform the test, two electrodes can be inserted into muscle tissue which measure the difference in voltage between the two points. The signals generated during muscle contraction are then passed through an amplifier to boost the signal, a filter to remove noise from the amplified signal, and then an analog-to-digital converter.
Though the filtering process is now digital itself, the original design of an EMG involved an analog system of fundamental circuit components, the simplest being a resistor and capacitor, known as a passive low pass filter (Figure 1). As long as the current passes through the circuit below the cut-off frequency, it behaves essentially like a normal circuit. However, frequencies above the cut-off frequency of the filter will cross the capacitor and go to the ground. The cut-off frequency is determined by both the resistance and capacitance of the circuit; the higher the capacitance or resistance, the lower the cut-off frequency will be.
Figure 1. Passive, first order low-pass RC filter
While DC current does not work with an RC filter, it will charge up the capacitor until it is fully charged, and afterward the current will go through Vstart text, end text, start subscript, o, u, t, end subscript instead (no current will go to the ground). If the capacitance is 3 Farads, and there is a charge of 150 Coulombs at the precise moment the DC current passes through Vstart text, end text, start subscript, o, u, t, end subscript; what is the voltage?
Choose 1 answer: