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MCAT
Course: MCAT > Unit 9
Lesson 5: Stereochemistry- Stereochemistry questions
- Chiral drugs
- Structural (constitutional) isomers
- Chiral vs achiral
- Stereoisomers, enantiomers, and chirality centers
- Identifying chirality centers
- R,S system
- R,S system practice
- Optical activity
- Enantiomers and diastereomers
- Cis–trans isomerism
- E–Z system
- Conformations of ethane
- Conformational analysis of butane
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Identifying chirality centers
How to determine which atoms in a molecule are chirality centers. Created by Jay.
Want to join the conversation?
- Do chiral centers only have carbon atoms at their core? Is a nitrogen atom with three bonds and a lone pair not considered a chiral center?(6 votes)
- A nitrogen atom with three bonds and a lone pair is technically a chiral center, but typically it can convert back and forth between conformations so quickly that in practice, you wouldn't be able to isolate the enantiomers.(7 votes)
- what are the L and D amino acids? what is the basic difference between them?(2 votes)
- An amino acid has the general formula H₂N-CH(R)-COOH, where R stands for the different acids.
Notice that the central C atom is chiral — it has four different groups attached — so the molecule can exist as a pair of enantiomers (nonsuperimposable mirror images).
One of these is the D isomer, and the other is L (i.e. a pair of R/S isomers).
There are about 20 amino acids normally found in the human body. All of them are the L-isomers.(5 votes)
- If a molecule has a Chiral center they are enantiomer, but if a molecule is a enantiomer is it necessary that its a chiral molecule ?(3 votes)
- 1 of the definitions I found says that enantiomer is " molecule that exhibits stereoisomerism because of the presence of one or more chiral centres"(2 votes)
- So this does this chiral center have an R-configuration?(2 votes)
- the molecules in the video are not in the dash/wedge notation. The dashes and wedges are what differentiates a chiral molecule drawing from its stereoisomers. By simply looking at the line drawing, such as the one at, it is impossible to tell which stereoisomer it is. The R or S configuration depends on the geometry, which cannot be inferred directly from these drawings. 5:50(5 votes)
- At, the paths are considered different. So does this mean that the "groups" are different due to the double bond? 4:43(2 votes)
- Do carbon in COOH-R called as chirality centre(2 votes)
- A chiral center of an atom is the atom in a molecule that is bonded to four different chemical species.
Remember that a chemical species is an atom/molecule with a specific molecular structure.
If we draw out COOHR as a Lewis diagram, then the carbon (C) is not attached to four different species (remember, we have 2 oxygens which are the same species).
Hope this helps,
- Convenient Colleague(2 votes)
- What does sp3 hybridized mean in relation to a chiral center? I only know what sp3 means in terms of electron configurations. Please help!(1 vote)
- sp3 hybridized means there's 4 bonds, and since it's chiral it means the carbon is bonded to 4 different substituents. For example, a carbon bonded to Hydrogen, Bromine, Fluorine, and Chlorine would be sp3 hybridized (4 bonds) and chiral (4 different substituents).(4 votes)
- Does a double bond not have 2 hydrogens? And one bond needs two hydrogens? Help!(1 vote)
- Assuming that the molecule is a hydrocarbon (meaning it is made of only carbon and hydrogen) then the number of hydrogens will depend on the number of bonds that carbon has to other carbons. Carbon wants to have 4 bonds. A double bond counts as 2 bonds. Take the following carbon chain as an example:
CH3--CH==CH2
Starting on the left, the first carbon has 3 hydrogens because it is only singly bonded to one other carbon. (3 hydrogen bonds + 1 carbon bond = 4 totals bonds)
The second carbon only has 1 hydrogen because it has one single bond to a carbon and one double bond (counts as 2 bonds) to another carbon. This gives it a total of 3 bonds to other carbons, so one hydrogen is needed to complete the 4 bonds.
The third carbon has 2 hydrogens because it has one double bond (counts as 2 bonds) to another carbon. Two hydrogen bonds are then needed to complete all 4 bonds.
If the molecule also contained other types of atoms the same principle would apply--the carbon will form 4 bonds.(3 votes)
- atcant we break the rest of the ring (say assumption) and then there will be two different groups 3:49(2 votes)
- Don't break any bonds when determining stereochemistry. But yes, if you did break it, then the molecule would have a chiral center.(1 vote)
- With the first chlorohexane example - if you go one way around the ring you have a CH2-CH2-CH2 group, and the other way gives you a CH2-CH2 group. As well as this the top carbon is of course attached to a Cl and an H. I can visually conceptualise why this isn't a chiral centre but applying the rule that a C with 4 different groups = chiral carbon then wouldn't this fall under that category as its groups could be said to be CH2-CH2-CH2; CH2-CH2; Cl; and H? Like I said it is easy for me to understand why it is not but I'm a little unclear about how the application of the 'four group' rule works here.(2 votes)
- C-3 is a chiral centre.
When you go around the ring, you stop at the first point of difference.
The groups directly attached to C-3 in 3-chlorocyclohexene are H, Cl, CH₂, and CH. You can stop there, because these are four different groups.
If you go one atom further, the groups are H, Cl, CH₂-CH₂, and CH=CH. Again, four different groups.
If you go out still one more atom, the groups are H, Cl, CH₂-CH₂-CH₂, and CH=CH-CH₂. Still four different groups.(1 vote)
Video transcript
Voiceover: Once you understand
the concept of chirality, the next skill is to be able
to identify a chirality center. So, I'm using the term
"chirality center" here, but you also might hear "chiral center" or "stereo center" or "stereogenic center" or "assymetric center," and they're all pretty much referring to the same concept: a tetrahedral carbon,
sp3 hybridized carbon that has four different
groups attached to it. So, let's look for some
chirality centers in these molecules, and we'll start
with this alcohol here. So I'm going to redraw this. I'm just going to draw
out all of the atoms here. So we have four carbons. The carbon on the left has
three hydrogens attached to it. So there's no way that's
a chirality center. I need four different groups,
and I have three of the same thing on that carbon,
so that one is not one. This next carbon here, we have an OH, and then we also have a
hydrogen attached to it. So that's this carbon over here. And this is a chirality center. We have four different groups
attached to this carbon, so I'm going to mark
this carbon right here. This is a chirality center. There's a methyl group on this side, so that's one different group. There's an OH group. There's an ethyl group, and
then there's also a hydrogen. So draw in that hydrogen. There are four different
groups attached to that carbon, so that carbon is a chirality center. So this carbon right here
is a chirality center. I'm going to draw in the other hydrogens. So I have two hydrogens on this carbon, so that's not a chirality center. I have two of the same
thing bonded to this carbon. And then finally this carbon over here with three hydrogens,
three of the same thing, so that carbon is not a chirality center. So, one chirality center in this alcohol. For our next example, let me go ahead and draw in the carbons, so we have three carbons. And the carbon on the left has
three hydrogens bonded to it. So that carbon is not a chirality center. Same with the carbon on
the right, three hydrogens, so there's no way it could
be a chirality center. Let's focus in on this carbon right here. So let's think about the
hybridization of that carbon. We know from earlier videos, that's an sp2 hybridized carbon with trigonal planar geometry. So immediately you know that
it's not a chirality center. That has to be sp3 hybridized, giving you a tetrahedral geometry, and we don't have four different things
bonded to that carbon, so none of these carbons
are chirality centers. So there are zero chirality
centers in this molecule. So that's acetone. Let's do a ring example. Let's do this ring example right here. Let me draw it out on
the molecule this time. So we have a hydrogen here. We have two hydrogens on this carbon. Two hydrogens on this carbon all the way around our rings. Let me draw in all these hydrogens. Then we look for chirality
centers or chiral centers. All of these carbons, let me
highlight them in magenta. All of these carbons have two hydrogens bonded to them, so that's
two of the same thing. So, there's no way those are
going to be chiral centers. What about this carbon right here? It looks like it might
be a chirality center. We have a chlorine
bonded to it, a hydrogen, and then we have these things
going in opposite directions. But in actuality, this
is not a chiral center, and that's because there's the same path around this ring here. So the hydrogen is like
one different group, the chlorine is another different group, so that's two different groups. But if you go around the ring this way, and you go around the ring this way, it's the same path both ways. You hit a CH2, and you hit a CH2. You hit a CH2, and you hit a CH2, and then you hit a CH2. So it's the same path around the ring. It's like two of the exact same groups bonded to that carbon. Another way of thinking about this is if I focus in on that
carbon at the top again, so I have a hydrogen
here and a chlorine here, and I draw in a molecule like that. So, I took out this last carbon down here, so I'm leaving out the last carbon. One way to think about it is, that's two of the same things
attached to this carbon. Here's an ethyl group,
and here's an ethyl group. So, two of the same thing
attached to that carbon. So this is not a chiral center. There are zero chirality
centers for this molecule. However, if we change things up, so let's look at this molecule now, we have a different path around the ring. So once again, we're focused
in on this carbon because we know we have a hydrogen
bonded to that carbon here. So the paths around the ring, there's a different path around the ring. Let me draw in the hydrogens once again. There are two hydrogens on this carbon, only one hydrogen on this carbon. If you go to the left around the ring, you hit a CH2 right here. If you go to the right around the ring, you hit a carbon bonded
to only one hydrogen. So, it's a different path. It's like there are four different things attached to this carbon right here. So this carbon is a chirality center. If we look at some of these other carbons, let me use red for this, if we look at this carbon right here, this carbon is sp2 hybridized. There's a double bond there, so it's not a chirality center. Same with this carbon. This carbon has two
hydrogens bonded to it. This carbon has two
hydrogens bonded to it. This carbon has two
hydrogens bonded to it. So there's only one chirality
center in this molecule. Now let's finally do one more example which just looks a little
bit more challenging than the ones we've been doing. It's a little bit scarier looking. This is the ibuprofen molecule. Let's go through this one
by one, but let's start with this benzene ring here in the center. Let's just start with
this carbon right here. This carbon is sp2 hybridized,
and as you go around the benzine ring, all of these
carbons are sp2 hybridized. So that immediately means that these can't be chiral centers. Need to be a type of tetrahedral geometry to be a chirality center. So those carbons are all out. Let's look at this carbon right here. I know that there are two hydrogens bonded to that carbon,
so that carbon is out. Let's look at this carbon. Well, I know that this carbon is bonded to two methyl groups, which
is two of the same thing. So that carbon is out. Let's look at this carbon. I know there are three
hydrogens bonded to that carbon, so that one's out. Same with this carbon. So, these three are the same thing. So none of these carbons over here, on the left side of the molecule,
are chirality centers. Let's go over here. Let me use a different color
for this carbon right here. I know that there's only one
hydrogen bonded to this carbon. I'll just put it in right here. So let's think about the different groups. I have a methyl group right here. I have a hydrogen. I have this carboxylic acid over here. Then I have my benzene ring over here in the rest of the molecule. So that's four different
groups attached to this carbon. This carbon that I've marked in blue here, is a chirality center. So this is a chiral center. Go ahead and mark it. Let's focus in on this
carbon on the methyl group. There are three hydrogens, so
that's not a chiral center. This carbon right here has a double bond to it, so it's sp2 hybridized. So that cannot be a
chirality center either. So, we have only one chiral
center in this molecule. This is a very important
skill to practice. To look at the carbons, think
about what's bonded to them, and if there are four
different groups bonded to that carbon, and it's
a tetrahedral carbon, sp3 hybridized, then we can call it a chirality center or a chiral center, or whatever term your
professor wants to use.