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Saponification - Base promoted ester hydrolysis

Created by Ryan Scott Patton.

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  • marcimus pink style avatar for user rareflower
    At , the carbonyl double bond is re-formed, and this kicks off the -OR group. Why is the -OR group more likely to leave than the -OH which just joined the molecule?
    (8 votes)
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    • piceratops ultimate style avatar for user Darmon
      The preceding answer is incorrect. In fact, alkoxides (-OR) are stronger bases than is water, mainly due to the donation of electron density by alkyl groups in the former, which further destabilizes the negative charge on the oxygen. The reason why the -OR group leaves rather than the -OH is that the equilibrium of the reaction is shifted toward formation of the product, i.e., the hydroxide concentration in the solution is high while the alkoxide concentration is low.

      In order to understand this concept, the idea of probability must be implicated; when we look at a single molecule in a mechanism, we may think that one pathway is more favorable than another, however in an actual reaction, an inordinate number of molecules are reacting simultaneously and therefore we must also consider the overall direction of the reaction as the products equilibrate with the reactants. Yes, most of the time the hydroxide group will be ejected and the reactant reformed, however there are so many hydroxide ions that, eventually, the -OR group will be replaced by -OH in most of the reactant molecules despite the fact that the probability of the hydroxide remaining bonded to the molecule is relatively low in each individual case. :)
      (3 votes)
  • blobby green style avatar for user Zadriana
    How does this differ from transesterification?
    (4 votes)
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    • eggleston orange style avatar for user t0mato
      Transesterification is the transformation of an ester into an alcohol and has to be done in an ACIDIC environment. Saponification is catalyzed by a BASE. The overall reaction mechanism is similar, I think the main difference is the esterification has a proton added to remove the ester and produce an alkene while Saponification has a nucleophilic attack with the OH-
      Probably not a lot of help 3 years later but hopefully this can help someone else
      (3 votes)
  • primosaur ultimate style avatar for user Shreya
    Oils are long chain acids. Do they also turn blue litmus red? Please answer. Thanks for the answer.
    (3 votes)
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  • aqualine ultimate style avatar for user Afrasiab Khan
    By the process of saponification, we can prepare soap,1) By which process we can prepare detergents. 2) What is the reason behind it that if grease sticks to our clothes we use detergents instead of soaps ?
    Detergents can remove it.
    (2 votes)
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    • piceratops seed style avatar for user manokamna bajaj
      the same reaction is used but the difference is in the salts that are attached
      you see... Instead of a carboxylic acid group, the detergent contains a more highly ionic group, such as a sulfate or sulfonate group (OS(O)₂-OH). so they act better on hard water which contain calcium and magnesium salts and soaps on the other hand are made of fatty acids (carboxylic acids)i.e. an organic compound most often of animal or plant origin.
      (2 votes)
  • blobby green style avatar for user Linnea
    Why is OR the leaving group?
    In other examples H20 often is the leavning group.
    What makes a certain group "good to go?" :)

    edit: I now understand that a good leaving group often is a weak base, and that makes everything even more confusing, because in the video you say that OR is a strong base...
    (2 votes)
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  • leafers ultimate style avatar for user Ngoc Dat Pham Nguyen
    Where does the Na+ go if ester is circle like xiclohexane ? My image : https://1drv.ms/i/s!An3GFdEHyJtrg7sddGYruZmH4EHeBQ
    (2 votes)
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  • blobby green style avatar for user Iftikhar Imrul Khan
    Hey, anyone tell me that ....why alkali like sodium/potassium are used in soap?
    (1 vote)
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  • aqualine ultimate style avatar for user PranksALot
    So, is saponification an SN2 reaction?
    (1 vote)
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  • leaf red style avatar for user ahmed khatab
    why carboxylate ion is very unreactive toward nucleophilic substitution as well as it has a negative formal charge which makes it a strong nucleophile...?
    (1 vote)
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  • leaf red style avatar for user ahmed khatab
    meaning of hydrolysis here by base is hydrolysis itself which is formation of alcohol and carboxylic acid or formation of soaps only...? plz any one answer me...!
    (1 vote)
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Video transcript

- [Voiceover] Okay now, I said in a previous video that triglycerols, and I'm drawing an example here. Triglycerols are hydrolyzable lipids. Which means that they're lipids that can be broken down into smaller pieces in a hydrolysis reaction. So, hydrolysis reaction. And maybe a more general way of looking at this reaction is as an ester hydrolysis. Because, really what's being broken down in here are the individual ester bonds. You see, this is an ester. This carbon is double-bonded to an oxygen and then bonded to an additional OR group, as well, here. This would be an ester, and this, when we break these triglycerols down, this bond right here and right here and right here. These are the bonds that we're breaking. So, this is actually, more generally, an ester hydrolysis reaction. Now, this reaction can occur in the presence of either an acid or a base. But, I want to concentrate on the base promoted ester hydrolysis because it has some specific implications for these trigylcerols that we've been talking about that I want to build towards. So, the base promoted ester hydrolysis. So, to give us a headstart on this base promoted ester hydrolysis, I went ahead and I kind of drew us in a backbone here for this reaction mechanism. And I'll just try to go ahead and walk us all the way through it. So, starting off what we have is an OH group, right here. An OH group, this is going to be our base. It comes in and it nucleophilically attacks this carbon. So, this is a nucleophilic addition reaction. And when these electrons come here, that forces some of the electrons from the carbon oxygen double bond to kick up to the oxygen. Which the oxygen pretty readily accepts these electrons. It's pretty electronegative as an atom. So, in this tetrahedral intermediate, we end up with an anion of this oxygen. This is our carbanion tetrahedral intermediate. But, these electrons end up coming back down to reform this carbon oxygen double bond, because the double bond is a little bit more stable, and it forces these electrons from this OR group to push out, and this OR group becomes a leaving group. So, this would be step one. We kind of had the addition of this OR group. And then, step two, here, we have the OR group which has now got an extra pair of electrons leaves. So, you can see in this step, our OR group which would be negatively charged has left. And what happens is this OR group now is a really strong base. It's got this extra pair of electrons. It was a good leaving group, but, it's a strong base. And we've formed a carboxylic acid. You see here, we've got a carbon double bonded to an oxygen and then with an OH group. And this is a strong acid. So, in this third. That would be the second step. In this third step, we have an acid based proton transfer. So, this OR group, this strong base, is going to pick up this proton. And these electrons are going to move back on to this pretty electronegative oxygen which was willing to give up this hydrogen because it's such a strong acid. You end up with a product of a carboxylate anion. So, we've got that negative charge, and then our alcohol. So, this would be the base promoted ester hydrolysis reaction. And you can see that this is the bond that we're breaking. We've broken that bond, right here. Now, in our body, this base promoted ester hydrolysis it allows us to break up these triglycerols, is the starting point for all of our fat metabolism reactions. So, if we want to take a fat and metabolize it and break it down so that we can get the energy out of it, remember that we had nine kilocals of energy. If we want to metabolize fat, so I'm going to write that up here as one of the uses of this based promoted ester hydrolysis reaction. We're going to start with this mechanism, right here. So, in the cells of our body, we're able to use specific enzymes called lipases. So, lipases. Lipases to facilitate this reaction so that we can break down fats, and eventually get energy out of them. And that reaction is hugely significant in our bodies. But, another application for this reaction is actually in the creation of soaps. So soaps and what happens is when you use a strong base like NaOH. So maybe like, NaOH which is sodium hydroxide, as this base promotion, you end up with a sodium cation at the beginning of this relationship. That's where this hydroxyl base group comes from, from the sodium hydroxide. And you end up with this sodium cation that just kind of floats through this reaction unused until the very end. Because, what you have is a cation here and an anion, this is a polyatomic anion, this carboxylate anion, and it links up with the sodium cation to form a ionic salt. This is an ionic bond. So, we've got a salt, here. Now, if the carboxylate anion in the salt that you just formed happens to be from a fatty acid, which is the case in this triglycerol. Remember, these are individual. These are three fatty acids. Then you have a really neat property in the product because this R group, right here, is actually a really long tail. Remember with the fatty acid tails. I'll just go ahead and draw a whole fatty acid, here. So, this might be an example of the carboxylate anion with the fatty acid. You have this really long carbon tail. And then you have this sodium cation that comes in. If this is the salt product, which again, is the case with the triglycerol, then you have a long non-polar section, here, for the tail. So, non-polar with a really polar head in this ionic bond. And this allows this salt, which is a soap, to dissolve both non-polar molecules and polar molecules. So, the non-polar side is going to wash away. It's going to dissolve things like grease and oil. And then the polar side is going to allow this mixture to wash away with water. Because, the polar side can dissolve in with water. And this is exactly what allows you to take the grease which gets all over your hand when you're working, say on a car, or on a bike, and wash it away with soap, with heavy soap. So, this soap actually kind of lends towards the reaction name for a based promoted ester hydrolysis which is saponification. Kind of a long word, but saponification. This is exactly what saponification is referring to the base promoted ester hydrolysis reaction.