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Course: LSAT > Unit 1
Lesson 5: Analytical Reasoning – Worked examples- Ordering setup | Overview | Rules and deductions
- Ordering setup | Given info–basic 1 | Worked example
- Ordering setup | Given info–basic 2 | Worked example
- Ordering setup | Given info–could be true | Worked example
- Ordering setup | Given info–cannot be true 1 | Worked example
- Ordering setup | Given info–cannot be true 2 | Worked example
- Ordering setup | Given info–must be true | Worked example
- Ordering setup | New info–could be true 1 | Worked example
- Ordering setup | New info–could be true 2 | Worked example
- Ordering setup | New info–could be true 3 | Worked example
- Ordering setup | Completely determines | Worked example
- Ordering setup | New info-must be true | Worked example
- Grouping setup | Overview | Rules and deductions
- Grouping setup | Given info–basic | Worked example
- Grouping setup | Given info–could be true | Worked example
- Grouping setup | Given info–must be false | Worked example
- Grouping setup | Given info–must be true 1 | Worked example
- Grouping setup | Given info–must be true 2 | Worked example
- Grouping setup | New info–could be true 1 | Worked example
- Grouping setup | New info–could be true 2 | Worked example
- Grouping setup | New info–must be true | Worked example
- Grouping setup | "Completely determines" | Worked example
- Mixed setup | Overview | Rules and deductions
- Mixed setup | Given info–basic | Worked example
- Mixed setup | Given info–could be true 1 | Worked example
- Mixed setup | Given info–could be true 2 | Worked example
- Mixed setup | Given info–must be true | Worked example
- Mixed setup | Given info–cannot be true | Worked example
- Mixed setup | New info–could be true | Worked example
- Mixed setup | New info–must be true 1 | Worked example
- Mixed setup | New info–must be true 2 | Worked example
- Mixed setup | Rule substitution | Worked example
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Grouping setup | New info–could be true 2 | Worked example
Watch a demonstration of one way to approach questions that ask you to identify what could be true, given new information on an LSAT analytical reasoning grouping setup. Created by Annie Hollister.
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Why is it I,Y,W/O specifically?
Could it have been I,Y,G/O pr I,Y,G/W?(1 vote)- How is it that green, orange, or white as possibly false. Green was plaçe in the second costume, but I don't understand how.(1 vote)
Video transcript
- [Woman] If exactly two of the costumes have yellow in them, then which one of the
following could be false? With this question, we wanna add the new information, that two costumes have yellow in them, to the information we already have and the inferences we've already made, and then cross out
things that must be true given that information. So, first, let's think about what we know. We know that indigo and yellow are paired, so, if two of the costumes
have yellow in them, then two of the costumes must
also have indigo in them. So, we can add that to
out diagram like this. We also know, as we figured out before, that one of the costumes
is red, white, and orange, because red can't be paired
with indigo or green, and indigo and yellow are paired, so red also can't be with yellow, which means that red has to
be with white and orange. So, if exactly two of the
costumes have yellow in them, what else must be true? Since green has to appear
somewhere in the three costumes, one of these costumes is
indigo, yellow, and green. Since no two costumes have
the same color combination, the other indigo-yellow costume can't be indigo, yellow, and green. It could be indigo, yellow, and white, or indigo, yellow, and orange. So, we can write that like this. Now, let's cross off
choices that must be true. For instance, if exactly two of the
costumes have yellow in them, then it must be true that exactly two of the costumes
have indigo in them, because indigo and yellow are paired. We also figured out that
exactly one of the costumes has both green and indigo in it, because green has to appear somewhere, but, we also know that no two costumes can be exactly the same, so, it can't be the case that two costumes have both green and indigo. Exactly one of the costumes
has both red and white in it. Well, that has to be true no matter what, whether or not two of the
costumes have yellow in them. We already figured out that red has to be paired
with white and orange, and that only one costume can
have red, white, and orange, so that definitely must be true. Exactly one of the
costumes has green in it. Well, we already figured out that, if two of the costumes
have yellow in them, then exactly one of the costumes is indigo, yellow, and green, and no two costumes are
the same color combination, only one of the costumes has green in it. Finally, exactly one of the
costumes has white in it. Well, this could be either true or false. We know that one of the costumes, the red, white, and orange
one, has white in it, and we know that one of the costumes definitely doesn't have white in it, because it's indigo, yellow, and green, but, the third costume could
have white in it or not. It could be indigo, yellow, and white, or indigo, yellow, and orange. So, this could be false. It could be false that exactly one of the
costumes has white in it.