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## GMAT

### Course: GMAT > Unit 1

Lesson 1: Problem solving- GMAT: Math 1
- GMAT: Math 2
- GMAT: Math 3
- GMAT: Math 4
- GMAT: Math 5
- GMAT: Math 6
- GMAT: Math 7
- GMAT: Math 8
- GMAT: Math 9
- GMAT: Math 10
- GMAT: Math 11
- GMAT: Math 12
- GMAT: Math 13
- GMAT: Math 14
- GMAT: Math 15
- GMAT: Math 16
- GMAT: Math 17
- GMAT: Math 18
- GMAT: Math 19
- GMAT: Math 20
- GMAT: Math 21
- GMAT: Math 22
- GMAT: Math 23
- GMAT: Math 24
- GMAT: Math 25
- GMAT: Math 26
- GMAT: Math 27
- GMAT: Math 28
- GMAT: Math 29
- GMAT: Math 30
- GMAT: Math 31
- GMAT: Math 32
- GMAT: Math 33
- GMAT: Math 34
- GMAT: Math 35
- GMAT: Math 36
- GMAT: Math 37
- GMAT: Math 38
- GMAT: Math 39
- GMAT: Math 40
- GMAT: Math 41
- GMAT: Math 42
- GMAT: Math 43
- GMAT: Math 44
- GMAT: Math 45
- GMAT: Math 46
- GMAT: Math 47
- GMAT: Math 48
- GMAT: Math 49
- GMAT: Math 50
- GMAT: Math 51
- GMAT: Math 52
- GMAT: Math 53
- GMAT: Math 54

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# GMAT: Math 9

49-54, pgs. 158-159. Created by Sal Khan.

## Want to join the conversation?

- -8×=96 what's the answer to this problem(2 votes)
- ABCD is square and ABE is an equilateral triangle outside the square prove that angle ACE is equal to half of angle ABE(2 votes)
- rationalise denominator ( 2sqrt 3-sqrt3)/2+sqrt2+3sqrt3(2 votes)
- a man does double the work done a boy at the same time. in how many days will 3 men and 4 boys finish a work which can be done by 10 men 8 days ?(2 votes)
- 16 days for 3 Men and 4 Boys - effectively the work capacity of 5 men.

This seems pretty straightforward...

A boy does HALF the work a man can do in the same amount of time, so

2 (Boy)= 1 (Man) (2 boys accomplish the same work as 1 man in 1 day, for example).

SO: 4 (Boy) = 2 (Men)...

therefore 3 (Men) + 4 (Boy) = 5 (Men) for work capacity.

If it takes 10 Men 8 days, it should take 5 Men 16 days.(3 votes)

- the volumes of the sphere are in the ratio64:27. Find their radii of the radii is 21cm(2 votes)
- Find their radii of the radii?? I think something is missing from your question.(0 votes)

- what would the answer be for this question be, Tickets for the zoo are of two types: A for adults, C for children and senior citizens. The cost of 7 type A and 4 type C tickets is 46 €, whereas the cost of 8 type A and 6 type C tickets is 57 €. Calculate the cost 5 type A and 3 type C tickets.(1 vote)
- two circles of radii 5cm and 3cm intersect at two points and the distance between their centers is 4cm. find the length of the common chord(1 vote)
- hi sai are u the creator(1 vote)
- is it the same when there fliped(1 vote)
- What's the answer to this problem-8×=96(1 vote)

## Video transcript

We're on problem 49. And it says, what is the square
root of 7 plus the square root of 7, and
all of that squared. So this is really just a little
bit of simplification. So if I have two of something,
in this case, I have 2 square roots of 7, if I add them
together, I get 2 of it, so I get 2 square roots of 7,
and I'm squaring that. And 2 square roots of 7 squared,
that's equal to 2 squared times the square root
of 7 squared, right? That's just your exponent
properties, so that is equal to 4 times-- what's the square
root of 7 squared? Well, it's just 7, right? So it's 4 times 7, which
is equal to 28, which is choice C. Next problem. 50. In a certain population, there
are three times as many people aged 21 or under as there
are people over 21. OK, so let's say that x is equal
to under 21 and y is equal to over 21. So in a certain population,
there are three times as many people aged 21 or under as
there are people over 21. So this is the number of people
under 21 and there are three times as many as
there are over 21. The ratio of those 21 or under
to the total population is? So they want to know the ratio
of x, 21 or under, to the total population, not just to
the over 21 population. So what's the total
population? That's everyone, right? x plus
y is equal to total. So what they want is the
ratio of x to x plus y. And then we could do a little
bit of substitution. We know x is equal
to 3y, so let's substitute that into this. Remember, this is the ratio
they're trying to figure out: the ratio of 21 or under to
the total population. So x is equal to 3y
over 3y plus y. And I just did that because,
wow, if we do that then it looks like we could be able
to cancel out all the y's. So we get 3y over what? What's 3y plus another y? Well, it's 4y. The y's cancel out. You get 3/4. And that is choice E, 3:4. Next question. 51. And actually, you know, you
didn't even have to do it algebraically. If you just think about question
50, you could have just played with numbers. You can say, OK, there are three
times as many people aged 21 or under as there
are people over 21. So you just say, OK, if there's
one person over 21, there'd be three people under
21, and there'd be a total of four people, so it
would be 3:4. But anyway, either way it
didn't take us too long. So they've drawn
a figure here. Let me draw it as well. So they have two lines that
intersect something like that. And they say that this angle
right here is 3x degrees. This angle is y plus 30 degrees,
and they say this angle is 2x degrees. And they say, in the figure
above, the value of y is what? Well, there's a bunch of
ways you can do it. The way this pops out to me is
we could figure out x because we know that this angle plus
this angle is equal to 180 degrees, because they
are supplementary. They go all the way halfway
around a circle. So we know that if we add 3x
plus 2x, that should equal 180 degrees, or 5x is
equal to 180. Or that x is equal to what? Let's see, 30 times 5 is 150,
then you have 30 left over, so it's 36 degrees, right? 36 times 5 is, yep, 180. And now we know if x is 36
degrees, what is this angle? Well, this angle is going
to be 72 degrees. It's 2 times x. 72 degrees. And then this angle and this
angle are opposite angles. And you could do the angle game
module on Khan Academy, if that doesn't ring a bell,
but that should ring a bell from geometry. And there's another way
you could do it. You could say that this angle
plus this angle have to equal 180, either way. You could do it either way. But the easiest way is to say
that this angle and this angle are equal, because they're
opposite angles. So we know that y plus
30 has to equal this angle, equals 72. Subtract 30 from both sides,
you get y is equal to 42 degrees, which is choice E. Next problem. Let me make it a different
color now. 52. Kelly and Chris packed several
boxes with books. If Chris packed 60% of the total
number of boxes, what was the ratio of the number of
boxes Kelly packed to the number of boxes Chris packed? So they want to know the ratio
of Kelly to Chris, right? Well, if Chris packed 60% of the
total, we could say, let C be the number that Chris packed,
so that'll be equal to 0.6 of the total. Well, then that means that
Kelly packed the rest of them, right? So, I'm assuming it's a she,
Kelly would have packed the remainder, which is
40% of the total. So the ratio of the number
that Chris-- what do they want to know? What was the ratio of the number
of boxes Kelly packed to the number of boxes
Chris packed. So the want to know the
ratio of K to C. Well, K is 0.4T and C is 0.6T. T's cancel out. You get, essentially, 4/6,
which is 2/3, right? If you multiply the top and the
bottom by 10, it becomes 4/6, so you get 2:3, and
that is choice E. Problem 53. Of the following, which is the
closest approximation of 50.2 times 0.49 over 199.8? So I haven't looked at the
choices yet, but if I had to approximate what this is, I
would say, well, that's close to 50, right? 50.2 is really close to 50
times-- 0.49 is really close to 0.5, all of that over--
199.8 is really close to 200, right? So you could view this
as being equal to -- let's see, 25/200. And 25/200, you could divide the
top and the bottom by 25. You get 1 over-- 25 goes into
100 four times, goes into 200-- eight times. And that is one of our choices,
so I'll go with that. B. 1/8. Problem 54. The average of 10, 30, and 50. So the average is going to
be 10 plus 30 plus 50. So the average of those three
is that, divided by 3. First of all, what is that? Well, it looks like it
should be 30, right? Because you get 60 plus
30/3, so that's 90. So the average of 10, 30, and 50
is 5 more than the average of 20, 40, and one of
the choices, and x. So to write this, we say, OK,
we figured out that the average-- oh, sorry, the average
here isn't-- sorry, let me redo this for you. So they say the average of 10,
30, and 50, and we already figured out 10 plus
30 plus 50. If you average that, divided by
3, you get 90 divided by 3 is equal to 30. And you actually didn't even
have to do the math. You could have said, oh, we'll
have 30 in the middle. 50 is 20 more than 30. 10 is 20 less than 30. So the average is
going to be 30. But this didn't take
you much time. So the average is 30. And they say that that is 5 more
than the average of 20, 40, and another number. So 30 is equal to 5
plus the average of those three numbers. So the average of those three
numbers is 20 plus 40 plus x, over 3, right? So let's just simplify this. Let's subtract 5 from
both sides. You get 25 is equal to 20
plus 40 plus x, over 3. So you multiply both
sides by 3. You get 75 is equal
to 60 plus x. And then you subtract
60 from both sides. You get x is equal to 15,
and that is choice A. And I'm almost out of
time, so I'll see you in the next video. See you soon.