<?xml version="1.0" encoding="UTF-8"?>
<urlset xmlns="http://www.sitemaps.org/schemas/sitemap/0.9"
        xmlns:xhtml="http://www.w3.org/1999/xhtml"
        xmlns:video="http://www.google.com/schemas/sitemap-video/1.1"
        xmlns:image="http://www.google.com/schemas/sitemap-image/1.1">
    
    <url>
        <loc>https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:equilibrium/x2eef969c74e0d802:solubility-equilibria/v/solubility-product-constant-from-the-solubility</loc>
        
        <xhtml:link rel="alternate" hreflang="bg"
                    href="https://bg.khanacademy.org/science/chemistry/acid-base-equilibrium/copy-of-solubility-equilibria-mcat/v/solubility-product-constant-from-the-solubility" />
        
        <xhtml:link rel="alternate" hreflang="en"
                    href="https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:equilibrium/x2eef969c74e0d802:solubility-equilibria/v/solubility-product-constant-from-the-solubility" />
        
        <xhtml:link rel="alternate" hreflang="es"
                    href="https://es.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:equilibrium/x2eef969c74e0d802:solubility-equilibria/v/solubility-product-constant-from-the-solubility" />
        
        <xhtml:link rel="alternate" hreflang="fr"
                    href="https://fr.khanacademy.org/science/chemistry/acid-base-equilibrium/copy-of-solubility-equilibria-mcat/v/solubility-product-constant-from-the-solubility" />
        
        <xhtml:link rel="alternate" hreflang="gu"
                    href="https://gu.khanacademy.org/science/chemistry/acid-base-equilibrium/copy-of-solubility-equilibria-mcat/v/solubility-product-constant-from-the-solubility" />
        
        <xhtml:link rel="alternate" hreflang="hi"
                    href="https://hi.khanacademy.org/science/up-class-11-chemistry/xa8e73391a9c6d31a:equilibrium/xa8e73391a9c6d31a:solubility-equilibria/v/solubility-product-constant-from-the-solubility" />
        
        <xhtml:link rel="alternate" hreflang="ka"
                    href="https://ka.khanacademy.org/science/chemistry/acid-base-equilibrium/copy-of-solubility-equilibria-mcat/v/solubility-product-constant-from-the-solubility" />
        
        <xhtml:link rel="alternate" hreflang="pl"
                    href="https://pl.khanacademy.org/science/ap-chemistry/buffers-titrations-solubility-equilibria-ap/solubility-equilibria-tutorial-ap/v/solubility-product-constant-from-the-solubility" />
        
        <xhtml:link rel="alternate" hreflang="pt"
                    href="https://pt.khanacademy.org/science/chemistry/acid-base-equilibrium/copy-of-solubility-equilibria-mcat/v/solubility-product-constant-from-the-solubility" />
        
        <xhtml:link rel="alternate" hreflang="ru"
                    href="https://ru.khanacademy.org/science/chemistry/acid-base-equilibrium/copy-of-solubility-equilibria-mcat/v/solubility-product-constant-from-the-solubility" />
        
        <xhtml:link rel="alternate" hreflang="tr"
                    href="https://tr.khanacademy.org/science/10-sinif-kimya/xad8986e3a9b791b4:kimyanin-temel-kanunlari-ve-kimyasal-hesaplamalar/xad8986e3a9b791b4:untitled-14/v/solubility-product-constant-from-the-solubility" />
        
        <xhtml:link rel="alternate" hreflang="uz"
                    href="https://uz.khanacademy.org/science/chemistry/acid-base-equilibrium/copy-of-solubility-equilibria-mcat/v/solubility-product-constant-from-the-solubility" />
        
        <lastmod>2022-09-05T08:18:59.810508578Z</lastmod>
        
        <PageMap xmlns="http://www.google.com/schemas/sitemap-pagemap/1.0">
            <DataObject type="document" id="solubility-product-constant-from-the-solubility">
            <Attribute name="title">Introduction to solubility equilibria</Attribute>
            <Attribute name="description">The solubility product constant, Kₛₚ, is an equilibrium constant that reflects the extent to which an ionic compound dissolves in water. For compounds that dissolve to produce the same number of ions, we can directly compare their Kₛₚ values to determine their relative solubilities. If we know the solubility of a salt, we can use this information to calculate the Kₛₚ value for the compound.</Attribute>
            <Attribute name="author">Jay</Attribute>
            <Attribute name="type">video</Attribute>
            
            </DataObject>
        </PageMap>
        
        <video:video>
            <video:thumbnail_loc>https://cdn.kastatic.org/ka_thumbnails_cache/72314172-3787-4009-a8d6-f99d45cb6b90_1280_720_base.png</video:thumbnail_loc>
            <video:title>Introduction to solubility equilibria</video:title>
            <video:description>The solubility product constant, Kₛₚ, is an equilibrium constant that reflects the extent to which an ionic compound dissolves in water. For compounds that dissolve to produce the same number of ions, we can directly compare their Kₛₚ values to determine their relative solubilities. If we know the solubility of a salt, we can use this information to calculate the Kₛₚ value for the compound.</video:description>
            <video:player_loc>https://cdn.kastatic.org/ka-youtube-converted/N9a2r01ToZk.mp4/N9a2r01ToZk.mp4</video:player_loc>
            <video:duration>497</video:duration>
            <video:category>Solubility equilibria</video:category>
        </video:video>
        
    </url>
    
    <url>
        <loc>https://www.khanacademy.org/science/chemistry/chemical-equilibrium/equilibrium-constant/a/the-equilibrium-constant-k</loc>
        
        <xhtml:link rel="alternate" hreflang="bg"
                    href="https://bg.khanacademy.org/science/chemistry/chemical-equilibrium/equilibrium-constant/a/the-equilibrium-constant-k" />
        
        <xhtml:link rel="alternate" hreflang="cs"
                    href="https://cs.khanacademy.org/science/fyzikalni-chemie/xecb1a3ac274b46c2:chemical-equilibrium/xecb1a3ac274b46c2:rovnovazna-konstanta/a/the-equilibrium-constant-k" />
        
        <xhtml:link rel="alternate" hreflang="en"
                    href="https://www.khanacademy.org/science/chemistry/chemical-equilibrium/equilibrium-constant/a/the-equilibrium-constant-k" />
        
        <xhtml:link rel="alternate" hreflang="es"
                    href="https://es.khanacademy.org/science/ap-chemistry/chemical-equilibrium-ap/equilibrium-constant-ap/a/the-equilibrium-constant-k" />
        
        <xhtml:link rel="alternate" hreflang="fr"
                    href="https://fr.khanacademy.org/science/chemistry/chemical-equilibrium/equilibrium-constant/a/the-equilibrium-constant-k" />
        
        <xhtml:link rel="alternate" hreflang="gu"
                    href="https://gu.khanacademy.org/science/chemistry/chemical-equilibrium/equilibrium-constant/a/the-equilibrium-constant-k" />
        
        <xhtml:link rel="alternate" hreflang="hu"
                    href="https://hu.khanacademy.org/science/kemia/x5722077306300ce8:chemical-equilibrium/x5722077306300ce8:equilibrium-constant/a/the-equilibrium-constant-k" />
        
        <xhtml:link rel="alternate" hreflang="hy"
                    href="https://hy.khanacademy.org/science/10th-grade-chemistry/x02e7d56aaf3c1c65:kinetic-ev-havasarakshrutyun/x02e7d56aaf3c1c65:qimiakan-havasarakshrutyun/a/the-equilibrium-constant-k" />
        
        <xhtml:link rel="alternate" hreflang="ka"
                    href="https://ka.khanacademy.org/science/chemistry/chemical-equilibrium/equilibrium-constant/a/the-equilibrium-constant-k" />
        
        <xhtml:link rel="alternate" hreflang="pl"
                    href="https://pl.khanacademy.org/science/ap-chemistry/chemical-equilibrium-ap/equilibrium-constant-ap/a/the-equilibrium-constant-k" />
        
        <xhtml:link rel="alternate" hreflang="pt"
                    href="https://pt.khanacademy.org/science/chemistry/chemical-equilibrium/equilibrium-constant/a/the-equilibrium-constant-k" />
        
        <xhtml:link rel="alternate" hreflang="tr"
                    href="https://tr.khanacademy.org/science/chemistry/chemical-equilibrium/equilibrium-constant/a/the-equilibrium-constant-k" />
        
        <xhtml:link rel="alternate" hreflang="uz"
                    href="https://uz.khanacademy.org/science/chemistry/chemical-equilibrium/equilibrium-constant/a/the-equilibrium-constant-k" />
        
        <xhtml:link rel="alternate" hreflang="zh-hans"
                    href="https://zh.khanacademy.org/science/chemistry/chemical-equilibrium/equilibrium-constant/a/the-equilibrium-constant-k" />
        
        <lastmod>2021-04-29T07:49:22Z</lastmod>
        
        <PageMap xmlns="http://www.google.com/schemas/sitemap-pagemap/1.0">
            <DataObject type="document" id="the-equilibrium-constant-k">
            <Attribute name="title">The equilibrium constant K</Attribute>
            <Attribute name="description">Reversible reactions, equilibrium, and the equilibrium constant K. How to calculate K, and how to use K to determine if a reaction strongly favors products or reactants at equilibrium. </Attribute>
            
            <Attribute name="type">article</Attribute>
            
            </DataObject>
        </PageMap>
        
    </url>
    
    <url>
        <loc>https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:equilibrium/x2eef969c74e0d802:calculating-the-equilibrium-constant/v/worked-examples-calculating-equilibrium-constants-from-equilibrium-concentrations-or-partial-pressures</loc>
        
        <xhtml:link rel="alternate" hreflang="en"
                    href="https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:equilibrium/x2eef969c74e0d802:calculating-the-equilibrium-constant/v/worked-examples-calculating-equilibrium-constants-from-equilibrium-concentrations-or-partial-pressures" />
        
        <xhtml:link rel="alternate" hreflang="hi"
                    href="https://hi.khanacademy.org/science/up-class-11-chemistry/xa8e73391a9c6d31a:equilibrium/xa8e73391a9c6d31a:law-of-chemical-equilibrium/v/worked-examples-calculating-equilibrium-constants-from-equilibrium-concentrations-or-partial-pressures" />
        
        <xhtml:link rel="alternate" hreflang="pt"
                    href="https://pt.khanacademy.org/science/quimica-ensino-medio/x57f96b935ba57f4b:equilibrio-quimico/x57f96b935ba57f4b:constante-de-equilibrio/v/worked-examples-calculating-equilibrium-constants-from-equilibrium-concentrations-or-partial-pressures" />
        
        <lastmod>2022-10-05T02:43:18.611402953Z</lastmod>
        
        <PageMap xmlns="http://www.google.com/schemas/sitemap-pagemap/1.0">
            <DataObject type="document" id="worked-examples-calculating-equilibrium-constants-from-equilibrium-concentrations-or-partial-pressures">
            <Attribute name="title">Worked examples: Calculating equilibrium constants</Attribute>
            <Attribute name="description">In this video, we&#39;ll calculate equilibrium constants using measurements of concentration and partial pressures at equilibrium. First, we&#39;ll find Kc for an equilibrium system using equilibrium concentrations. Then, we&#39;ll find Kp for a different system using equilibrium partial pressures.</Attribute>
            <Attribute name="author">Jay</Attribute>
            <Attribute name="type">video</Attribute>
            
            </DataObject>
        </PageMap>
        
        <video:video>
            <video:thumbnail_loc>https://cdn.kastatic.org/ka_thumbnails_cache/974389d9-063b-4465-8725-7a1dffa31ecd_1280_720_base.png</video:thumbnail_loc>
            <video:title>Worked examples: Calculating equilibrium constants</video:title>
            <video:description>In this video, we&#39;ll calculate equilibrium constants using measurements of concentration and partial pressures at equilibrium. First, we&#39;ll find Kc for an equilibrium system using equilibrium concentrations. Then, we&#39;ll find Kp for a different system using equilibrium partial pressures.</video:description>
            <video:player_loc>https://cdn.kastatic.org/ka-youtube-converted/5HZbCNg9mIw.mp4/5HZbCNg9mIw.mp4</video:player_loc>
            <video:duration>492</video:duration>
            <video:category>Solubility equilibria</video:category>
        </video:video>
        
    </url>
    
    <url>
        <loc>https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:equilibrium/x2eef969c74e0d802:solubility-equilibria/v/solubility-from-the-solubility-product-constant</loc>
        
        <xhtml:link rel="alternate" hreflang="bg"
                    href="https://bg.khanacademy.org/science/chemistry/acid-base-equilibrium/copy-of-solubility-equilibria-mcat/v/solubility-from-the-solubility-product-constant" />
        
        <xhtml:link rel="alternate" hreflang="en"
                    href="https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:equilibrium/x2eef969c74e0d802:solubility-equilibria/v/solubility-from-the-solubility-product-constant" />
        
        <xhtml:link rel="alternate" hreflang="es"
                    href="https://es.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:equilibrium/x2eef969c74e0d802:solubility-equilibria/v/solubility-from-the-solubility-product-constant" />
        
        <xhtml:link rel="alternate" hreflang="fr"
                    href="https://fr.khanacademy.org/science/chemistry/acid-base-equilibrium/copy-of-solubility-equilibria-mcat/v/solubility-from-the-solubility-product-constant" />
        
        <xhtml:link rel="alternate" hreflang="gu"
                    href="https://gu.khanacademy.org/science/chemistry/acid-base-equilibrium/copy-of-solubility-equilibria-mcat/v/solubility-from-the-solubility-product-constant" />
        
        <xhtml:link rel="alternate" hreflang="ka"
                    href="https://ka.khanacademy.org/science/chemistry/acid-base-equilibrium/copy-of-solubility-equilibria-mcat/v/solubility-from-the-solubility-product-constant" />
        
        <xhtml:link rel="alternate" hreflang="pl"
                    href="https://pl.khanacademy.org/science/ap-chemistry/buffers-titrations-solubility-equilibria-ap/solubility-equilibria-tutorial-ap/v/solubility-from-the-solubility-product-constant" />
        
        <xhtml:link rel="alternate" hreflang="pt"
                    href="https://pt.khanacademy.org/science/chemistry/acid-base-equilibrium/copy-of-solubility-equilibria-mcat/v/solubility-from-the-solubility-product-constant" />
        
        <xhtml:link rel="alternate" hreflang="ru"
                    href="https://ru.khanacademy.org/science/chemistry/acid-base-equilibrium/copy-of-solubility-equilibria-mcat/v/solubility-from-the-solubility-product-constant" />
        
        <xhtml:link rel="alternate" hreflang="tr"
                    href="https://tr.khanacademy.org/science/11-sinif-kimya/xa3301547a59054a3:3-unite-sivi-cozeltiler-ve-cozunurluk/xa3301547a59054a3:koligatif-ozellikler/v/solubility-from-the-solubility-product-constant" />
        
        <xhtml:link rel="alternate" hreflang="uz"
                    href="https://uz.khanacademy.org/science/chemistry/acid-base-equilibrium/copy-of-solubility-equilibria-mcat/v/solubility-from-the-solubility-product-constant" />
        
        <lastmod>2023-01-06T23:41:11.341040227Z</lastmod>
        
        <PageMap xmlns="http://www.google.com/schemas/sitemap-pagemap/1.0">
            <DataObject type="document" id="solubility-from-the-solubility-product-constant">
            <Attribute name="title">Worked example: Calculating solubility from Kₛₚ</Attribute>
            <Attribute name="description">A compound&#39;s molar solubility in water can be calculated from its Kₛₚ value at 25°C. To do so, first prepare an ICE (Initial, Change, and Equilibrium) table showing the equilibrium concentrations of the ions in terms of x, the molar solubility of the compound. Then, plug these expressions into the solubility-product expression for the compound and solve for the value of x.</Attribute>
            <Attribute name="author">Jay</Attribute>
            <Attribute name="type">video</Attribute>
            
            </DataObject>
        </PageMap>
        
        <video:video>
            <video:thumbnail_loc>https://cdn.kastatic.org/ka_thumbnails_cache/ce13b7aa-49dd-43e4-b643-798d5f69ee9b_1280_720_base.png</video:thumbnail_loc>
            <video:title>Worked example: Calculating solubility from Kₛₚ</video:title>
            <video:description>A compound&#39;s molar solubility in water can be calculated from its Kₛₚ value at 25°C. To do so, first prepare an ICE (Initial, Change, and Equilibrium) table showing the equilibrium concentrations of the ions in terms of x, the molar solubility of the compound. Then, plug these expressions into the solubility-product expression for the compound and solve for the value of x.</video:description>
            <video:player_loc>https://cdn.kastatic.org/ka-youtube-converted/Ywvw32DaxUk.mp4/Ywvw32DaxUk.mp4</video:player_loc>
            <video:duration>292</video:duration>
            <video:category>Solubility equilibria</video:category>
        </video:video>
        
    </url>
    
    <url>
        <loc>https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:equilibrium/x2eef969c74e0d802:solubility-equilibria/v/worked-example-predicting-whether-a-precipitate-forms-by-comparing-q-and-k</loc>
        
        <xhtml:link rel="alternate" hreflang="en"
                    href="https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:equilibrium/x2eef969c74e0d802:solubility-equilibria/v/worked-example-predicting-whether-a-precipitate-forms-by-comparing-q-and-k" />
        
        <xhtml:link rel="alternate" hreflang="es"
                    href="https://es.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:equilibrium/x2eef969c74e0d802:solubility-equilibria/v/worked-example-predicting-whether-a-precipitate-forms-by-comparing-q-and-k" />
        
        <lastmod>2022-10-05T02:43:18.611402953Z</lastmod>
        
        <PageMap xmlns="http://www.google.com/schemas/sitemap-pagemap/1.0">
            <DataObject type="document" id="worked-example-predicting-whether-a-precipitate-forms-by-comparing-q-and-k">
            <Attribute name="title">Worked example: Predicting whether a precipitate forms by comparing Q and Kₛₚ</Attribute>
            <Attribute name="description">We can use the reaction quotient to predict whether a precipitate will form when two solutions containing dissolved ionic compounds are mixed. If Q &lt; Kₛₚ, the newly mixed solution is undersaturated and no precipitate will form. If Q &gt; Kₛₚ, the solution is oversaturated and a precipitate will form until Q = Kₛₚ.</Attribute>
            <Attribute name="author">Jay</Attribute>
            <Attribute name="type">video</Attribute>
            
            </DataObject>
        </PageMap>
        
        <video:video>
            <video:thumbnail_loc>https://cdn.kastatic.org/ka_thumbnails_cache/6b0cd6d9-be24-4705-95d4-0289078a3a08_1280_720_base.png</video:thumbnail_loc>
            <video:title>Worked example: Predicting whether a precipitate forms by comparing Q and Kₛₚ</video:title>
            <video:description>We can use the reaction quotient to predict whether a precipitate will form when two solutions containing dissolved ionic compounds are mixed. If Q &lt; Kₛₚ, the newly mixed solution is undersaturated and no precipitate will form. If Q &gt; Kₛₚ, the solution is oversaturated and a precipitate will form until Q = Kₛₚ.</video:description>
            <video:player_loc>https://cdn.kastatic.org/ka-youtube-converted/vyENVkttVtw.mp4/vyENVkttVtw.mp4</video:player_loc>
            <video:duration>496</video:duration>
            <video:category>Solubility equilibria</video:category>
        </video:video>
        
    </url>
    
    <url>
        <loc>https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:equilibrium/x2eef969c74e0d802:solubility-equilibria/v/solubility-and-the-ph-of-the-solution</loc>
        
        <xhtml:link rel="alternate" hreflang="bg"
                    href="https://bg.khanacademy.org/science/chemistry/acid-base-equilibrium/copy-of-solubility-equilibria-mcat/v/solubility-and-the-ph-of-the-solution" />
        
        <xhtml:link rel="alternate" hreflang="en"
                    href="https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:equilibrium/x2eef969c74e0d802:solubility-equilibria/v/solubility-and-the-ph-of-the-solution" />
        
        <xhtml:link rel="alternate" hreflang="es"
                    href="https://es.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:equilibrium/x2eef969c74e0d802:solubility-equilibria/v/solubility-and-the-ph-of-the-solution" />
        
        <xhtml:link rel="alternate" hreflang="gu"
                    href="https://gu.khanacademy.org/science/chemistry/acid-base-equilibrium/copy-of-solubility-equilibria-mcat/v/solubility-and-the-ph-of-the-solution" />
        
        <xhtml:link rel="alternate" hreflang="ka"
                    href="https://ka.khanacademy.org/science/chemistry/acid-base-equilibrium/copy-of-solubility-equilibria-mcat/v/solubility-and-the-ph-of-the-solution" />
        
        <xhtml:link rel="alternate" hreflang="pl"
                    href="https://pl.khanacademy.org/science/ap-chemistry/buffers-titrations-solubility-equilibria-ap/solubility-equilibria-tutorial-ap/v/solubility-and-the-ph-of-the-solution" />
        
        <xhtml:link rel="alternate" hreflang="pt"
                    href="https://pt.khanacademy.org/science/chemistry/acid-base-equilibrium/copy-of-solubility-equilibria-mcat/v/solubility-and-the-ph-of-the-solution" />
        
        <xhtml:link rel="alternate" hreflang="ru"
                    href="https://ru.khanacademy.org/science/chemistry/acid-base-equilibrium/copy-of-solubility-equilibria-mcat/v/solubility-and-the-ph-of-the-solution" />
        
        <xhtml:link rel="alternate" hreflang="tr"
                    href="https://tr.khanacademy.org/science/11-sinif-kimya/xa3301547a59054a3:3-unite-sivi-cozeltiler-ve-cozunurluk/xa3301547a59054a3:koligatif-ozellikler/v/solubility-and-the-ph-of-the-solution" />
        
        <xhtml:link rel="alternate" hreflang="uz"
                    href="https://uz.khanacademy.org/science/chemistry/acid-base-equilibrium/copy-of-solubility-equilibria-mcat/v/solubility-and-the-ph-of-the-solution" />
        
        <lastmod>2022-09-05T08:18:59.810508578Z</lastmod>
        
        <PageMap xmlns="http://www.google.com/schemas/sitemap-pagemap/1.0">
            <DataObject type="document" id="solubility-and-the-ph-of-the-solution">
            <Attribute name="title">pH and solubility</Attribute>
            <Attribute name="description">For ionic compounds containing basic anions, solubility increases as the pH of the solution is decreased. For ionic compounds containing anions of negligible basicity (such as the conjugate bases of strong acids), solubility is unaffected by changes in pH. </Attribute>
            <Attribute name="author">Jay</Attribute>
            <Attribute name="type">video</Attribute>
            
            </DataObject>
        </PageMap>
        
        <video:video>
            <video:thumbnail_loc>https://cdn.kastatic.org/ka_thumbnails_cache/6c96e0dd-87b6-4b4f-a3f4-1878e085103b_1280_720_base.png</video:thumbnail_loc>
            <video:title>pH and solubility</video:title>
            <video:description>For ionic compounds containing basic anions, solubility increases as the pH of the solution is decreased. For ionic compounds containing anions of negligible basicity (such as the conjugate bases of strong acids), solubility is unaffected by changes in pH. </video:description>
            <video:player_loc>https://cdn.kastatic.org/ka-youtube-converted/Z2bDnvDGQHQ.mp4/Z2bDnvDGQHQ.mp4</video:player_loc>
            <video:duration>314</video:duration>
            <video:category>Solubility equilibria</video:category>
        </video:video>
        
    </url>
    
    <url>
        <loc>https://www.khanacademy.org/science/grade-11-chemistry-snc-aligned/x203b0fc81a964b2d:acid-base-chemistry/x203b0fc81a964b2d:solubility-equilibria/e/effect-of-dilution-of-acids-and-bases</loc>
        
        <xhtml:link rel="alternate" hreflang="en"
                    href="https://www.khanacademy.org/science/grade-11-chemistry-snc-aligned/x203b0fc81a964b2d:acid-base-chemistry/x203b0fc81a964b2d:solubility-equilibria/e/effect-of-dilution-of-acids-and-bases" />
        
        <xhtml:link rel="alternate" hreflang="gu"
                    href="https://gu.khanacademy.org/science/in-in-class-10-chemistry-india/x87dd2847d57ee419:in-in-acids-bases-and-salts/x87dd2847d57ee419:in-in-common-features-of-acid-and-base/e/effect-of-dilution-of-acids-and-bases" />
        
        <xhtml:link rel="alternate" hreflang="hi"
                    href="https://hi.khanacademy.org/science/up-class-10th-science/x5d08d26681869997:acids-bases-and-salts/x5d08d26681869997:strength-of-acid-and-base/e/effect-of-dilution-of-acids-and-bases" />
        
        <xhtml:link rel="alternate" hreflang="mr"
                    href="https://mr.khanacademy.org/science/mh-grade-9-science/x9d5f2b8ba380a1e4:acids-bases-and-salts/x9d5f2b8ba380a1e4:acids/e/effect-of-dilution-of-acids-and-bases" />
        
        <xhtml:link rel="alternate" hreflang="or"
                    href="https://or.khanacademy.org/science/odia-class-10-physical-sciences/x28e877d8a7566183:acids-bases-and-salts/x28e877d8a7566183:common-features-of-acid-and-base/e/effect-of-dilution-of-acids-and-bases" />
        
        <lastmod>2021-04-29T08:02:23Z</lastmod>
        
        <PageMap xmlns="http://www.google.com/schemas/sitemap-pagemap/1.0">
            <DataObject type="document" id="effect-of-dilution-of-acids-and-bases">
            <Attribute name="title">Effect of dilution of acids and bases</Attribute>
            <Attribute name="description">Let&#39;s practice to check the effect of hydronium and hydroxide ions on dilution acids and bases.</Attribute>
            
            <Attribute name="type">exercise</Attribute>
            
            </DataObject>
        </PageMap>
        
    </url>
    
    <url>
        <loc>https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:equilibrium/x2eef969c74e0d802:calculating-equilibrium-concentrations/v/worked-example-calculating-equilibrium-concentrations-from-initial-concentrations-and-the-equilibrium-constant</loc>
        
        <xhtml:link rel="alternate" hreflang="en"
                    href="https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:equilibrium/x2eef969c74e0d802:calculating-equilibrium-concentrations/v/worked-example-calculating-equilibrium-concentrations-from-initial-concentrations-and-the-equilibrium-constant" />
        
        <xhtml:link rel="alternate" hreflang="hi"
                    href="https://hi.khanacademy.org/science/up-class-11-chemistry/xa8e73391a9c6d31a:equilibrium/xa8e73391a9c6d31a:calculating-equilibrium-concentrations/v/worked-example-calculating-equilibrium-concentrations-from-initial-concentrations-and-the-equilibrium-constant" />
        
        <xhtml:link rel="alternate" hreflang="tr"
                    href="https://tr.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:equilibrium/x2eef969c74e0d802:calculating-equilibrium-concentrations/v/worked-example-calculating-equilibrium-concentrations-from-initial-concentrations-and-the-equilibrium-constant" />
        
        <lastmod>2022-10-05T02:43:18.611402953Z</lastmod>
        
        <PageMap xmlns="http://www.google.com/schemas/sitemap-pagemap/1.0">
            <DataObject type="document" id="worked-example-calculating-equilibrium-concentrations-from-initial-concentrations-and-the-equilibrium-constant">
            <Attribute name="title">Worked example: Calculating equilibrium concentrations from initial concentrations</Attribute>
            <Attribute name="description">In this video, we&#39;ll learn how to use initial concentrations along with the equilibrium constant to calculate the concentrations of reaction species at equilibrium.</Attribute>
            <Attribute name="author">Jay</Attribute>
            <Attribute name="type">video</Attribute>
            
            </DataObject>
        </PageMap>
        
        <video:video>
            <video:thumbnail_loc>https://cdn.kastatic.org/ka_thumbnails_cache/fb51c53d-94e3-4809-b533-f6bda44d6378_1280_720_base.png</video:thumbnail_loc>
            <video:title>Worked example: Calculating equilibrium concentrations from initial concentrations</video:title>
            <video:description>In this video, we&#39;ll learn how to use initial concentrations along with the equilibrium constant to calculate the concentrations of reaction species at equilibrium.</video:description>
            <video:player_loc>https://cdn.kastatic.org/ka-youtube-converted/l81swfmUaek.mp4/l81swfmUaek.mp4</video:player_loc>
            <video:duration>329</video:duration>
            <video:category>Solubility equilibria</video:category>
        </video:video>
        
    </url>
    
    <url>
        <loc>https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:equilibrium/x2eef969c74e0d802:solubility-equilibria/e/solubility-equilibria</loc>
        
        <xhtml:link rel="alternate" hreflang="en"
                    href="https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:equilibrium/x2eef969c74e0d802:solubility-equilibria/e/solubility-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="es"
                    href="https://es.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:equilibrium/x2eef969c74e0d802:solubility-equilibria/e/solubility-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="hi"
                    href="https://hi.khanacademy.org/science/up-class-11-chemistry/xa8e73391a9c6d31a:equilibrium/xa8e73391a9c6d31a:solubility-equilibria/e/solubility-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="pt"
                    href="https://pt.khanacademy.org/science/quimica-ensino-medio/x57f96b935ba57f4b:interacoes-moleculares/x57f96b935ba57f4b:polaridade-e-solubilidade/e/solubility-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="tr"
                    href="https://tr.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:equilibrium/x2eef969c74e0d802:solubility-equilibria/e/solubility-equilibria" />
        
        <lastmod>2021-08-19T23:56:28.151270963Z</lastmod>
        
        <PageMap xmlns="http://www.google.com/schemas/sitemap-pagemap/1.0">
            <DataObject type="document" id="solubility-equilibria">
            <Attribute name="title">Solubility equilibria</Attribute>
            <Attribute name="description">Check your understanding of solubility equilibria in this set of free practice questions designed for AP Chemistry students.</Attribute>
            
            <Attribute name="type">exercise</Attribute>
            
            </DataObject>
        </PageMap>
        
    </url>
    
    <url>
        <loc>https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:acids-and-bases/x2eef969c74e0d802:weak-acid-and-base-equilibria/v/weak-acid-equilibria</loc>
        
        <xhtml:link rel="alternate" hreflang="en"
                    href="https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:acids-and-bases/x2eef969c74e0d802:weak-acid-and-base-equilibria/v/weak-acid-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="tr"
                    href="https://tr.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:acids-and-bases/x2eef969c74e0d802:weak-acid-and-base-equilibria/v/weak-acid-equilibria" />
        
        <lastmod>2022-10-05T02:43:18.611402953Z</lastmod>
        
        <PageMap xmlns="http://www.google.com/schemas/sitemap-pagemap/1.0">
            <DataObject type="document" id="weak-acid-equilibria">
            <Attribute name="title">Weak acid equilibria</Attribute>
            <Attribute name="description">Unlike strong acids, weak acids only partially ionize in aqueous solution. As a result, the concentration of H₃O⁺ in a weak acid solution is typically much less than the initial acid concentration. The relative strength of a weak acid is described by the acid ionization constant, Kₐ, which is the equilibrium constant for the reaction of the weak acid with water.</Attribute>
            <Attribute name="author">Jay</Attribute>
            <Attribute name="type">video</Attribute>
            
            </DataObject>
        </PageMap>
        
        <video:video>
            <video:thumbnail_loc>https://cdn.kastatic.org/ka_thumbnails_cache/bae31433-023c-4c59-a7c1-360d5c111365_1280_720_base.png</video:thumbnail_loc>
            <video:title>Weak acid equilibria</video:title>
            <video:description>Unlike strong acids, weak acids only partially ionize in aqueous solution. As a result, the concentration of H₃O⁺ in a weak acid solution is typically much less than the initial acid concentration. The relative strength of a weak acid is described by the acid ionization constant, Kₐ, which is the equilibrium constant for the reaction of the weak acid with water.</video:description>
            <video:player_loc>https://cdn.kastatic.org/ka-youtube-converted/nJLNlB-7Rhk.mp4/nJLNlB-7Rhk.mp4</video:player_loc>
            <video:duration>670</video:duration>
            <video:category>Solubility equilibria</video:category>
        </video:video>
        
    </url>
    
    <url>
        <loc>https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:acids-and-bases/x2eef969c74e0d802:weak-acid-and-base-equilibria/v/worked-example-finding-the-percent-ionization-of-a-weak-acid</loc>
        
        <xhtml:link rel="alternate" hreflang="en"
                    href="https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:acids-and-bases/x2eef969c74e0d802:weak-acid-and-base-equilibria/v/worked-example-finding-the-percent-ionization-of-a-weak-acid" />
        
        <xhtml:link rel="alternate" hreflang="tr"
                    href="https://tr.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:acids-and-bases/x2eef969c74e0d802:weak-acid-and-base-equilibria/v/worked-example-finding-the-percent-ionization-of-a-weak-acid" />
        
        <lastmod>2021-07-31T00:23:16.684903809Z</lastmod>
        
        <PageMap xmlns="http://www.google.com/schemas/sitemap-pagemap/1.0">
            <DataObject type="document" id="worked-example-finding-the-percent-ionization-of-a-weak-acid">
            <Attribute name="title">Worked example: Finding the percent ionization of a weak acid</Attribute>
            <Attribute name="description">The percent ionization of a weak acid, HA, is defined as the ratio of the equilibrium H₃O⁺ concentration to the initial HA concentration, multiplied by 100%. In this video, we&#39;ll use this relationship to find the percent ionization of acetic acid in a 0.20 M solution.</Attribute>
            <Attribute name="author">Jay</Attribute>
            <Attribute name="type">video</Attribute>
            
            </DataObject>
        </PageMap>
        
        <video:video>
            <video:thumbnail_loc>https://cdn.kastatic.org/googleusercontent/ZCdwTudJg6e6n-P2gsaUborP4izvMsGo71pvEVlX9dNYWcLXcP7VHkWpn2grt4TUP1KoJLQP9NswyHBuBLSFTBw</video:thumbnail_loc>
            <video:title>Worked example: Finding the percent ionization of a weak acid</video:title>
            <video:description>The percent ionization of a weak acid, HA, is defined as the ratio of the equilibrium H₃O⁺ concentration to the initial HA concentration, multiplied by 100%. In this video, we&#39;ll use this relationship to find the percent ionization of acetic acid in a 0.20 M solution.</video:description>
            <video:player_loc>https://cdn.kastatic.org/ka-youtube-converted/_jEe0Tkyn3w.mp4/_jEe0Tkyn3w.mp4</video:player_loc>
            <video:duration>410</video:duration>
            <video:category>Solubility equilibria</video:category>
        </video:video>
        
    </url>
    
    <url>
        <loc>https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:acids-and-bases/x2eef969c74e0d802:weak-acid-and-base-equilibria/v/weak-base-equilibria</loc>
        
        <xhtml:link rel="alternate" hreflang="en"
                    href="https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:acids-and-bases/x2eef969c74e0d802:weak-acid-and-base-equilibria/v/weak-base-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="tr"
                    href="https://tr.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:acids-and-bases/x2eef969c74e0d802:weak-acid-and-base-equilibria/v/weak-base-equilibria" />
        
        <lastmod>2022-10-05T02:43:18.611402953Z</lastmod>
        
        <PageMap xmlns="http://www.google.com/schemas/sitemap-pagemap/1.0">
            <DataObject type="document" id="weak-base-equilibria">
            <Attribute name="title">Weak base equilibria</Attribute>
            <Attribute name="description">Weak bases partially ionize in water to produce hydroxide ions. Because the ionization is not complete, the concentration of OH⁻ in a weak base solution is typically much less than the initial base concentration. The relative strength of a weak base is described by the base ionization constant, Kb, which is the equilibrium constant for the reaction of the weak base with water.</Attribute>
            <Attribute name="author">Jay</Attribute>
            <Attribute name="type">video</Attribute>
            
            </DataObject>
        </PageMap>
        
        <video:video>
            <video:thumbnail_loc>https://cdn.kastatic.org/ka_thumbnails_cache/8fe22b44-8464-4a1b-a336-2aa8c81c7b80_1280_720_base.png</video:thumbnail_loc>
            <video:title>Weak base equilibria</video:title>
            <video:description>Weak bases partially ionize in water to produce hydroxide ions. Because the ionization is not complete, the concentration of OH⁻ in a weak base solution is typically much less than the initial base concentration. The relative strength of a weak base is described by the base ionization constant, Kb, which is the equilibrium constant for the reaction of the weak base with water.</video:description>
            <video:player_loc>https://cdn.kastatic.org/ka-youtube-converted/cvcgH3ohcNg.mp4/cvcgH3ohcNg.mp4</video:player_loc>
            <video:duration>570</video:duration>
            <video:category>Solubility equilibria</video:category>
        </video:video>
        
    </url>
    
    <url>
        <loc>https://www.khanacademy.org/science/grade-11-chemistry-snc-aligned/x203b0fc81a964b2d:acid-base-chemistry/x203b0fc81a964b2d:solubility-equilibria/a/weak-acid-base-equilibria</loc>
        
        <xhtml:link rel="alternate" hreflang="bg"
                    href="https://bg.khanacademy.org/science/chemistry/acids-and-bases-topic/copy-of-acid-base-equilibria/a/weak-acid-base-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="cs"
                    href="https://cs.khanacademy.org/science/fyzikalni-chemie/xecb1a3ac274b46c2:acids-and-bases/xecb1a3ac274b46c2:acid-base-equilibria/a/weak-acid-base-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="en"
                    href="https://www.khanacademy.org/science/grade-11-chemistry-snc-aligned/x203b0fc81a964b2d:acid-base-chemistry/x203b0fc81a964b2d:solubility-equilibria/a/weak-acid-base-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="es"
                    href="https://es.khanacademy.org/science/ap-chemistry/acids-and-bases-ap/acid-base-equilibria-tutorial-ap/a/weak-acid-base-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="fr"
                    href="https://fr.khanacademy.org/science/chemistry/acids-and-bases-topic/copy-of-acid-base-equilibria/a/weak-acid-base-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="gu"
                    href="https://gu.khanacademy.org/science/chemistry/acids-and-bases-topic/copy-of-acid-base-equilibria/a/weak-acid-base-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="hu"
                    href="https://hu.khanacademy.org/science/kemia/x5722077306300ce8:acids-and-bases-topic/x5722077306300ce8:copy-of-acid-base-equilibria/a/weak-acid-base-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="hy"
                    href="https://hy.khanacademy.org/science/10th-grade-chemistry/x02e7d56aaf3c1c65:ttuner-ev-himqer/x02e7d56aaf3c1c65:ttvayin-himnayin-havasarakshrutyun/a/weak-acid-base-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="ka"
                    href="https://ka.khanacademy.org/science/chemistry/acids-and-bases-topic/copy-of-acid-base-equilibria/a/weak-acid-base-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="pl"
                    href="https://pl.khanacademy.org/science/ap-chemistry/acids-and-bases-ap/acid-base-equilibria-tutorial-ap/a/weak-acid-base-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="pt"
                    href="https://pt.khanacademy.org/science/chemistry/acids-and-bases-topic/copy-of-acid-base-equilibria/a/weak-acid-base-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="tr"
                    href="https://tr.khanacademy.org/science/chemistry/acids-and-bases-topic/copy-of-acid-base-equilibria/a/weak-acid-base-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="uz"
                    href="https://uz.khanacademy.org/science/chemistry/acids-and-bases-topic/copy-of-acid-base-equilibria/a/weak-acid-base-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="zh-hans"
                    href="https://zh.khanacademy.org/science/chemistry/acids-and-bases-topic/copy-of-acid-base-equilibria/a/weak-acid-base-equilibria" />
        
        <lastmod>2021-04-29T07:49:41Z</lastmod>
        
        <PageMap xmlns="http://www.google.com/schemas/sitemap-pagemap/1.0">
            <DataObject type="document" id="weak-acid-base-equilibria">
            <Attribute name="title">Weak acid-base equilibria</Attribute>
            <Attribute name="description">Weak acid and base ionization reactions and the related equilibrium constants,  Ka and Kb. Relating Ka and Kb to pH, and calculating percent dissociation. </Attribute>
            
            <Attribute name="type">article</Attribute>
            
            </DataObject>
        </PageMap>
        
    </url>
    
    <url>
        <loc>https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:acids-and-bases/x2eef969c74e0d802:weak-acid-and-base-equilibria/e/weak-acid-and-base-equilibria</loc>
        
        <xhtml:link rel="alternate" hreflang="cs"
                    href="https://cs.khanacademy.org/science/fyzikalni-chemie/xecb1a3ac274b46c2:acids-and-bases/xecb1a3ac274b46c2:acid-base-equilibria/e/weak-acid-and-base-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="en"
                    href="https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:acids-and-bases/x2eef969c74e0d802:weak-acid-and-base-equilibria/e/weak-acid-and-base-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="es"
                    href="https://es.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:acids-and-bases/x2eef969c74e0d802:weak-acid-and-base-equilibria/e/weak-acid-and-base-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="hi"
                    href="https://hi.khanacademy.org/science/up-class-11-chemistry/xa8e73391a9c6d31a:equilibrium/xa8e73391a9c6d31a:acids-bases-and-salts/e/weak-acid-and-base-equilibria" />
        
        <xhtml:link rel="alternate" hreflang="tr"
                    href="https://tr.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:acids-and-bases/x2eef969c74e0d802:weak-acid-and-base-equilibria/e/weak-acid-and-base-equilibria" />
        
        <lastmod>2025-04-25T17:33:59.347925776Z</lastmod>
        
        <PageMap xmlns="http://www.google.com/schemas/sitemap-pagemap/1.0">
            <DataObject type="document" id="weak-acid-and-base-equilibria">
            <Attribute name="title">Weak acid and base equilibria</Attribute>
            <Attribute name="description">Practice calculations involving solutions of weak acids and bases in this set of free practice questions designed for AP Chemistry students.</Attribute>
            
            <Attribute name="type">exercise</Attribute>
            
            </DataObject>
        </PageMap>
        
    </url>
    
    <url>
        <loc>https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:acids-and-bases/x2eef969c74e0d802:introduction-to-acids-and-bases/v/worked-examples-calculating-hydronium-ion-concentration-and-ph</loc>
        
        <xhtml:link rel="alternate" hreflang="en"
                    href="https://www.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:acids-and-bases/x2eef969c74e0d802:introduction-to-acids-and-bases/v/worked-examples-calculating-hydronium-ion-concentration-and-ph" />
        
        <xhtml:link rel="alternate" hreflang="pt"
                    href="https://pt.khanacademy.org/science/quimica-ensino-medio/x57f96b935ba57f4b:untitled-48/x57f96b935ba57f4b:escala-de-ph/v/worked-examples-calculating-hydronium-ion-concentration-and-ph" />
        
        <lastmod>2022-10-05T02:43:18.611402953Z</lastmod>
        
        <PageMap xmlns="http://www.google.com/schemas/sitemap-pagemap/1.0">
            <DataObject type="document" id="worked-examples-calculating-hydronium-ion-concentration-and-ph">
            <Attribute name="title">Worked examples: Calculating [H₃O⁺] and pH</Attribute>
            <Attribute name="description">In this video, we&#39;ll solve for [H₃O⁺] and pH in two different worked examples. First, we&#39;ll walk through the possible approaches for calculating [H₃O⁺] from pOH. Then, we&#39;ll find the pH of pure water at 50°C from the value of the autoionization constant at 50°C.</Attribute>
            <Attribute name="author">Jay</Attribute>
            <Attribute name="type">video</Attribute>
            
            </DataObject>
        </PageMap>
        
        <video:video>
            <video:thumbnail_loc>https://cdn.kastatic.org/ka_thumbnails_cache/e67920d2-30a0-40ef-bcfb-a7761c9673f6_1280_720_base.png</video:thumbnail_loc>
            <video:title>Worked examples: Calculating [H₃O⁺] and pH</video:title>
            <video:description>In this video, we&#39;ll solve for [H₃O⁺] and pH in two different worked examples. First, we&#39;ll walk through the possible approaches for calculating [H₃O⁺] from pOH. Then, we&#39;ll find the pH of pure water at 50°C from the value of the autoionization constant at 50°C.</video:description>
            <video:player_loc>https://cdn.kastatic.org/ka-youtube-converted/qK_YVKAat1w.mp4/qK_YVKAat1w.mp4</video:player_loc>
            <video:duration>425</video:duration>
            <video:category>Solubility equilibria</video:category>
        </video:video>
        
    </url>
    
</urlset>
