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            <video:description>Lets prove that if a radius in a circle is drawn so it bisects a chord, then the radius is also perpendicular to that chord. The proof uses SSS congruence.</video:description>
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            <video:description>Simple proof using right triangle-side-hypotenuse (RSH) congruence criterion to show that a radius perpendicular to a chord bisects it</video:description>
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            <Attribute name="description">This video explains why chords equidistant from the centre of a circle are equal in length, using the concept of congruency. By drawing perpendiculars from the centre to each chord, we form two right triangles. Since the perpendiculars are equal and the radii are equal, the triangles are congruent. From this congruency, it follows that the corresponding chord segments are equal, proving that the chords themselves are equal in length.</Attribute>
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            <video:description>This video explains why chords equidistant from the centre of a circle are equal in length, using the concept of congruency. By drawing perpendiculars from the centre to each chord, we form two right triangles. Since the perpendiculars are equal and the radii are equal, the triangles are congruent. From this congruency, it follows that the corresponding chord segments are equal, proving that the chords themselves are equal in length.</video:description>
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