<?xml version="1.0" encoding="UTF-8"?>
<urlset xmlns="http://www.sitemaps.org/schemas/sitemap/0.9"
        xmlns:xhtml="http://www.w3.org/1999/xhtml"
        xmlns:video="http://www.google.com/schemas/sitemap-video/1.1"
        xmlns:image="http://www.google.com/schemas/sitemap-image/1.1">
    
    <url>
        <loc>https://www.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/v/foci-of-a-hyperbola</loc>
        
        <xhtml:link rel="alternate" hreflang="bg"
                    href="https://bg.khanacademy.org/math/11-klas-bg-profil-modul-1/x5cca5b843e924713:kanonichni-uravnenia-i-konichni-sechenia/x5cca5b843e924713:kanonichno-uravnenie-hiperbola/v/foci-of-a-hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="cs"
                    href="https://cs.khanacademy.org/math/analyticka-geometrie/xf4420fbd93bc9fcb:uvod-do-kuzelosecek/xf4420fbd93bc9fcb:foci-of-a-hyperbola/v/foci-of-a-hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="en"
                    href="https://www.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/v/foci-of-a-hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="es"
                    href="https://es.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/v/foci-of-a-hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="fr"
                    href="https://fr.khanacademy.org/math/be-6eme-secondaire6h2/x4c2539af63a9a0cb:les-coniques/x4c2539af63a9a0cb:l-hyperbole-son-centre-ses-foyers-et-ses-asymptotes/v/foci-of-a-hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="hi"
                    href="https://hi.khanacademy.org/math/up-math-class-11/x808831787a7b08a2:conic-sections-ncert-new/x808831787a7b08a2:hyperbola/v/foci-of-a-hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="hy"
                    href="https://hy.khanacademy.org/math/precalculus/conics-precalc/foci-of-a-hyperbola/v/foci-of-a-hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="ka"
                    href="https://ka.khanacademy.org/math/precalculus/conics-precalc/foci-of-a-hyperbola/v/foci-of-a-hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="ko"
                    href="https://ko.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/v/foci-of-a-hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="pl"
                    href="https://pl.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/v/foci-of-a-hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="pt"
                    href="https://pt.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/v/foci-of-a-hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="tr"
                    href="https://tr.khanacademy.org/math/precalculus/conics-precalc/foci-of-a-hyperbola/v/foci-of-a-hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="uk"
                    href="https://uk.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/v/foci-of-a-hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="uz"
                    href="https://uz.khanacademy.org/math/precalculus/conics-precalc/foci-of-a-hyperbola/v/foci-of-a-hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="zh-hans"
                    href="https://zh.khanacademy.org/math/precalculus/conics-precalc/foci-of-a-hyperbola/v/foci-of-a-hyperbola" />
        
        <lastmod>2021-03-19T16:21:24Z</lastmod>
        
        <PageMap xmlns="http://www.google.com/schemas/sitemap-pagemap/1.0">
            <DataObject type="document" id="foci-of-a-hyperbola">
            <Attribute name="title">Foci of a hyperbola from equation</Attribute>
            <Attribute name="description">Sal discusses the foci of hyperbolas and shows how they relate to hyperbola equations.</Attribute>
            <Attribute name="author">Sal Khan</Attribute>
            <Attribute name="type">video</Attribute>
            
            </DataObject>
        </PageMap>
        
        <video:video>
            <video:thumbnail_loc>https://cdn.kastatic.org/googleusercontent/fN5xNEwDo7pABBo-PQVKZcs8fLgu9rFMFTSrHmvDyAHXKycHCAM8e5YS5-tCZmXF6JtwrXfVQ8WaMIHLa9rtgoo</video:thumbnail_loc>
            <video:title>Foci of a hyperbola from equation</video:title>
            <video:description>Sal discusses the foci of hyperbolas and shows how they relate to hyperbola equations.</video:description>
            <video:player_loc>https://cdn.kastatic.org/ka-youtube-converted/S0Fd2Tg2v7M.mp4/S0Fd2Tg2v7M.mp4</video:player_loc>
            <video:duration>924</video:duration>
            <video:category>Foci of a hyperbola</video:category>
        </video:video>
        
    </url>
    
    <url>
        <loc>https://www.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/e/foci-of-hyperbola-from-equation</loc>
        
        <xhtml:link rel="alternate" hreflang="bg"
                    href="https://bg.khanacademy.org/math/11-klas-bg-profil-modul-1/x5cca5b843e924713:kanonichni-uravnenia-i-konichni-sechenia/x5cca5b843e924713:kanonichno-uravnenie-hiperbola/e/foci-of-hyperbola-from-equation" />
        
        <xhtml:link rel="alternate" hreflang="cs"
                    href="https://cs.khanacademy.org/math/analyticka-geometrie/xf4420fbd93bc9fcb:uvod-do-kuzelosecek/xf4420fbd93bc9fcb:foci-of-a-hyperbola/e/foci-of-hyperbola-from-equation" />
        
        <xhtml:link rel="alternate" hreflang="da"
                    href="https://da.khanacademy.org/math/algebra-home/alg-conic-sections/alg-foci-of-a-hyperbola/e/foci-of-hyperbola-from-equation" />
        
        <xhtml:link rel="alternate" hreflang="en"
                    href="https://www.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/e/foci-of-hyperbola-from-equation" />
        
        <xhtml:link rel="alternate" hreflang="es"
                    href="https://es.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/e/foci-of-hyperbola-from-equation" />
        
        <xhtml:link rel="alternate" hreflang="fr"
                    href="https://fr.khanacademy.org/math/be-6eme-secondaire6h2/x4c2539af63a9a0cb:les-coniques/x4c2539af63a9a0cb:l-hyperbole-son-centre-ses-foyers-et-ses-asymptotes/e/foci-of-hyperbola-from-equation" />
        
        <xhtml:link rel="alternate" hreflang="hi"
                    href="https://hi.khanacademy.org/math/up-math-class-11/x808831787a7b08a2:conic-sections-ncert-new/x808831787a7b08a2:hyperbola/e/foci-of-hyperbola-from-equation" />
        
        <xhtml:link rel="alternate" hreflang="hy"
                    href="https://hy.khanacademy.org/math/precalculus/conics-precalc/foci-of-a-hyperbola/e/foci-of-hyperbola-from-equation" />
        
        <xhtml:link rel="alternate" hreflang="ka"
                    href="https://ka.khanacademy.org/math/precalculus/conics-precalc/foci-of-a-hyperbola/e/foci-of-hyperbola-from-equation" />
        
        <xhtml:link rel="alternate" hreflang="ko"
                    href="https://ko.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/e/foci-of-hyperbola-from-equation" />
        
        <xhtml:link rel="alternate" hreflang="pl"
                    href="https://pl.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/e/foci-of-hyperbola-from-equation" />
        
        <xhtml:link rel="alternate" hreflang="pt"
                    href="https://pt.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/e/foci-of-hyperbola-from-equation" />
        
        <xhtml:link rel="alternate" hreflang="te"
                    href="https://te.khanacademy.org/math/class-12-tg/x6469e28db15923ec:hyperbola/x6469e28db15923ec:equation-of-hyperbola-in-standard-form-parametric-equations/e/foci-of-hyperbola-from-equation" />
        
        <xhtml:link rel="alternate" hreflang="uk"
                    href="https://uk.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/e/foci-of-hyperbola-from-equation" />
        
        <xhtml:link rel="alternate" hreflang="uz"
                    href="https://uz.khanacademy.org/math/precalculus/conics-precalc/foci-of-a-hyperbola/e/foci-of-hyperbola-from-equation" />
        
        <xhtml:link rel="alternate" hreflang="zh-hans"
                    href="https://zh.khanacademy.org/math/precalculus/conics-precalc/foci-of-a-hyperbola/e/foci-of-hyperbola-from-equation" />
        
        <lastmod>2026-04-08T00:36:09.500768563Z</lastmod>
        
        <PageMap xmlns="http://www.google.com/schemas/sitemap-pagemap/1.0">
            <DataObject type="document" id="foci-of-hyperbola-from-equation">
            <Attribute name="title">Foci of a hyperbola from equation</Attribute>
            <Attribute name="description">Given the equation of a hyperbola, find its foci.</Attribute>
            <Attribute name="author">Sid Patel</Attribute>
            <Attribute name="type">exercise</Attribute>
            
            </DataObject>
        </PageMap>
        
    </url>
    
    <url>
        <loc>https://www.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/e/equation_of_a_hyperbola</loc>
        
        <xhtml:link rel="alternate" hreflang="bg"
                    href="https://bg.khanacademy.org/math/11-klas-bg-profil-modul-1/x5cca5b843e924713:kanonichni-uravnenia-i-konichni-sechenia/x5cca5b843e924713:kanonichno-uravnenie-hiperbola/e/equation_of_a_hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="cs"
                    href="https://cs.khanacademy.org/math/analyticka-geometrie/xf4420fbd93bc9fcb:uvod-do-kuzelosecek/xf4420fbd93bc9fcb:foci-of-a-hyperbola/e/equation_of_a_hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="da"
                    href="https://da.khanacademy.org/math/algebra-home/alg-conic-sections/alg-foci-of-a-hyperbola/e/equation_of_a_hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="en"
                    href="https://www.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/e/equation_of_a_hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="es"
                    href="https://es.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/e/equation_of_a_hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="fr"
                    href="https://fr.khanacademy.org/math/be-6eme-secondaire6h2/x4c2539af63a9a0cb:les-coniques/x4c2539af63a9a0cb:l-hyperbole-son-centre-ses-foyers-et-ses-asymptotes/e/equation_of_a_hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="hi"
                    href="https://hi.khanacademy.org/math/up-math-class-11/x808831787a7b08a2:conic-sections-ncert-new/x808831787a7b08a2:hyperbola/e/equation_of_a_hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="hy"
                    href="https://hy.khanacademy.org/math/precalculus/conics-precalc/foci-of-a-hyperbola/e/equation_of_a_hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="ka"
                    href="https://ka.khanacademy.org/math/precalculus/conics-precalc/foci-of-a-hyperbola/e/equation_of_a_hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="ko"
                    href="https://ko.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/e/equation_of_a_hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="pl"
                    href="https://pl.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/e/equation_of_a_hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="pt"
                    href="https://pt.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/e/equation_of_a_hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="te"
                    href="https://te.khanacademy.org/math/class-12-tg/x6469e28db15923ec:hyperbola/x6469e28db15923ec:equation-of-hyperbola-in-standard-form-parametric-equations/e/equation_of_a_hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="uk"
                    href="https://uk.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/e/equation_of_a_hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="uz"
                    href="https://uz.khanacademy.org/math/precalculus/conics-precalc/foci-of-a-hyperbola/e/equation_of_a_hyperbola" />
        
        <xhtml:link rel="alternate" hreflang="zh-hans"
                    href="https://zh.khanacademy.org/math/precalculus/conics-precalc/foci-of-a-hyperbola/e/equation_of_a_hyperbola" />
        
        <lastmod>2026-05-05T18:10:50.367167117Z</lastmod>
        
        <PageMap xmlns="http://www.google.com/schemas/sitemap-pagemap/1.0">
            <DataObject type="document" id="equation_of_a_hyperbola">
            <Attribute name="title">Equation of a hyperbola from features</Attribute>
            <Attribute name="description">Given some features of a hyperbola, find its equation.</Attribute>
            <Attribute name="author">Sid Patel</Attribute>
            <Attribute name="type">exercise</Attribute>
            
            </DataObject>
        </PageMap>
        
    </url>
    
    <url>
        <loc>https://www.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/v/proof-hyperbola-foci</loc>
        
        <xhtml:link rel="alternate" hreflang="bg"
                    href="https://bg.khanacademy.org/math/11-klas-bg-profil-modul-1/x5cca5b843e924713:kanonichni-uravnenia-i-konichni-sechenia/x5cca5b843e924713:kanonichno-uravnenie-hiperbola/v/proof-hyperbola-foci" />
        
        <xhtml:link rel="alternate" hreflang="cs"
                    href="https://cs.khanacademy.org/math/analyticka-geometrie/xf4420fbd93bc9fcb:uvod-do-kuzelosecek/xf4420fbd93bc9fcb:foci-of-a-hyperbola/v/proof-hyperbola-foci" />
        
        <xhtml:link rel="alternate" hreflang="en"
                    href="https://www.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/v/proof-hyperbola-foci" />
        
        <xhtml:link rel="alternate" hreflang="es"
                    href="https://es.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/v/proof-hyperbola-foci" />
        
        <xhtml:link rel="alternate" hreflang="fr"
                    href="https://fr.khanacademy.org/math/be-6eme-secondaire6h2/x4c2539af63a9a0cb:les-coniques/x4c2539af63a9a0cb:l-hyperbole-son-centre-ses-foyers-et-ses-asymptotes/v/proof-hyperbola-foci" />
        
        <xhtml:link rel="alternate" hreflang="hy"
                    href="https://hy.khanacademy.org/math/precalculus/conics-precalc/foci-of-a-hyperbola/v/proof-hyperbola-foci" />
        
        <xhtml:link rel="alternate" hreflang="ka"
                    href="https://ka.khanacademy.org/math/precalculus/conics-precalc/foci-of-a-hyperbola/v/proof-hyperbola-foci" />
        
        <xhtml:link rel="alternate" hreflang="ko"
                    href="https://ko.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/v/proof-hyperbola-foci" />
        
        <xhtml:link rel="alternate" hreflang="pl"
                    href="https://pl.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/v/proof-hyperbola-foci" />
        
        <xhtml:link rel="alternate" hreflang="pt"
                    href="https://pt.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/v/proof-hyperbola-foci" />
        
        <xhtml:link rel="alternate" hreflang="tr"
                    href="https://tr.khanacademy.org/math/precalculus/conics-precalc/foci-of-a-hyperbola/v/proof-hyperbola-foci" />
        
        <xhtml:link rel="alternate" hreflang="uk"
                    href="https://uk.khanacademy.org/math/precalculus/x9e81a4f98389efdf:conics/x9e81a4f98389efdf:hyperb-foci/v/proof-hyperbola-foci" />
        
        <xhtml:link rel="alternate" hreflang="uz"
                    href="https://uz.khanacademy.org/math/precalculus/conics-precalc/foci-of-a-hyperbola/v/proof-hyperbola-foci" />
        
        <xhtml:link rel="alternate" hreflang="zh-hans"
                    href="https://zh.khanacademy.org/math/precalculus/conics-precalc/foci-of-a-hyperbola/v/proof-hyperbola-foci" />
        
        <lastmod>2021-03-19T16:21:24Z</lastmod>
        
        <PageMap xmlns="http://www.google.com/schemas/sitemap-pagemap/1.0">
            <DataObject type="document" id="proof-hyperbola-foci">
            <Attribute name="title">Proof of the hyperbola foci formula</Attribute>
            <Attribute name="description">Sal proves why, for the general hyperbola equation x^2/a^2-y^2/b^2=1, the focal length f forms the equation f^2=a^2+b^2 with the parameters a and b.</Attribute>
            <Attribute name="author">Sal Khan</Attribute>
            <Attribute name="type">video</Attribute>
            
            </DataObject>
        </PageMap>
        
        <video:video>
            <video:thumbnail_loc>https://cdn.kastatic.org/googleusercontent/PUjlqqxwBg_ErIeP7_FS0eivS2jrePh43deQ75n552tuS64s8ZH6OxXhM22pteNTUyNfklc4yXhIa1qmR0orTijarw</video:thumbnail_loc>
            <video:title>Proof of the hyperbola foci formula</video:title>
            <video:description>Sal proves why, for the general hyperbola equation x^2/a^2-y^2/b^2=1, the focal length f forms the equation f^2=a^2+b^2 with the parameters a and b.</video:description>
            <video:player_loc>https://cdn.kastatic.org/ka-youtube-converted/HPRFmu7JsKU.mp4/HPRFmu7JsKU.mp4</video:player_loc>
            <video:duration>890</video:duration>
            <video:category>Foci of a hyperbola</video:category>
        </video:video>
        
    </url>
    
</urlset>
