If you're seeing this message, it means we're having trouble loading external resources on our website.

If you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked.

# Calculating neutral velocity

Let's now do the math to calculate the equal speed at which both A and B could be traveling away from a "neutral" observer.

## Want to join the conversation?

• What if the movement was in a circular or spiral trajectory?
• That my friend, would be an accelerating reference frame, and would necessitate general relativity.
• I completely understand the mathematics.But what I'm confused about is when we found out the answer which was 0.5c, what did it meant?Does it mean that from C's frame of reference B was moving at a velocity of 0.5c while from A's frame of reference B was moving at a velocity of 0.8c.Please someone correct me if my conceptual understanding is wrong.
• Yes and from A's reference C is moving at 0.5c
(1 vote)
• at why is 1-0.64 equal to 0.36. wouldnt for that to work out it would be 0.64-0.36=0.36?
(1 vote)
• 0.64 - 0.36 = 0.28
(1 vote)
• So for C, the difference between the velocity of A and the velocity of B will actually look like the speed of light? Is this really possible to observe?
(1 vote)
• how can velocity of B with respect to C is v?