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Video transcript

I want to add one superfast addendum to the video on friedel-crafts isolation in the last step of the mechanism I had this chlorine swiped the electron or essentially that electron that was on with the aluminum it was given to the hydrogen proton so the hydrogen was nabbed away its electron was allowed to go back into the benzene ring so the aluminum lost the chlorine this benzene ring lost a proton I was able to take back that electron and I forgot to draw the hydrogen and the chlorine so then that results in hydrogen chloride so you have the hydrogen proton bonded it took this electron from the aluminum from the aluminum and it is bonded to the chlorine I didn't want to forget that in that last step of the friedel-crafts isolation we also get some hydrogen chloride