Find the current due to closing a switch using equivalent resistance and Ohm's law.
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- Is there a difference between the instant a switch is closed and a few minutes after a switch is closed for the current if say there was no break in the wire giving the current another path and placing the switch elsewhere?(1 vote)
- Why would the current follow the path of least resistance? Wouldn't it get divided?(1 vote)
- Well, here is how I like to think about it, the electrons would want to travel through a wire with the least resistance the exact same way any of us would want to take the easiest route back home. We wouldn't want to do the extra work would we? and the same way the electrons too would not want to do the extra work.
For example: Imagine you have a simple circuit, with a single wire connecting a resistor and a battery while forming a closed loop. Now, if you connect a second wire (that has way less resistance as compared to the first) to the circuit, let's say from a random point A on the first wire before the resistor to a random point B on the first wire after the resistor. This offers the electrons the choice to not pass through the resistor they had initially travelled through (this is actually called a short circuit). The electrons (most of them, we can't just suspend ohms law) then would take the wire with lesser resistance, ie the second wire .(1 vote)
- If I remove the R1 in both case then if I close the switch then I create a short circuit and fry everything?(0 votes)
- There's no resistance through the switch when it is closed?(0 votes)
- [Instructor] We are asked, "How does the current "going through R1," so, this resistor, "when the switch is open," this switch, "compare to the current through R1 "when the switch is closed?" Pause this video and see if you can figure that out. Alright, so let's just think about the two scenarios. So, we can view the current as this, right over here, this current that we care about. We could either measure it there or you could measure it right over there, and let's first think about the scenario where the switch is open. So, our current when our switch is open is going to be equal to the voltage across the resistors, and that's going to be our 12 volts, 12 volts, divided by the equivalent resistance of these resistors. When the switch is open, essentially, we just have R1 and R2 in series, and so this is just gonna be R1+R2. If you have two resistors in a series, their equivalent resistance is just the sum of the resistances. Fair enough. Now, let's think about the situation where the switch is closed. Closed. So here, our current at this point of our circuit, or the current going through R1, so I sub closed, is, once again, it's going to be equal to 12 volts, the voltage across the resistors, but what are we gonna divide by now? When we close the switch, what happens? Well, these lines where we see no resistors in circuit diagrams, that's assumed to be resistance-less, so all of the current will actually flow that way. So, by closing this switch, you're essentially removing R2 from the circuit. The current will just go through R1, and then follow the path of least resistance, literally. And so, in this situation, our current is going to be 12 volt divided by, you essentially just have one resistance, divided by R1. So, when you closed the circuit, you've essentially taken a resistor out, and so if you took a resistor out, you're going to increase the current, so you could just write it as, the current when the switch is open is going to be less than, is going to be less than the current when the switch is closed. Once again, why is that? Well, just look at the denominators here. When the switch is open, you're dividing by a larger number than when the switch is closed. Or, another way of thinking about it, when the switch is open, the R2 resistance is factored in. When the switch is closed, the R2 resistance essentially becomes a non-factor and you have less resistance, which would mean you would have higher current.