a plane is travelling with twice the horizontal velocity that is, with a velocity 230 m/s. if all other factors remain the same, determine the time required for the package to hit the ground.

it's going be the same time for the package to hit the ground, but the horizontal displacement is twice as before

how does increasing/decreasing the height of a horizontal projectile impact the time and horizontal displacement?

If you increase the initial height of the projectile, it will take longer to fall to the ground, so the impact time will be larger. If the projectile is in the air longer, it will have more time to travel horizontally. So, the horizontal displacement will be larger.

how will this affect the trout population?

It depends on how tough they are.

Main content

High school physics

Course: High school physics > Unit 3

Lesson 4: Horizontally launched projectiles

Horizontally launched projectile review

Google Classroom

Review the key concepts, equations, and skills for analyzing horizontally launched projectiles, including how to solve motion problems in two-dimensions using the kinematic formulas.

Key terms

Term	Meaning
Range	The maximum horizontal distance a projectile travels.

Equations

We don't have any new equations, hooray! The equations are the same kinematic formulas as in one dimension, but we now have one set of variables and formulas for each dimension.

Simplifying the horizontal equations

For the horizontal direction, a, start subscript, x, end subscript is always zero because gravity does not act in this direction. Thus, the kinematic formulas with a, start subscript, x, end subscript terms simplify to:

\begin{aligned}x &= x_0 + v_xt \\\\ v_x &=v_{x0}\end{aligned}

How to solve motion problems in two-dimensions

List our known and unknown variables. Note: the only common variable between the motions is time t.
Break the motion into horizontal and vertical components parallel to the x- and y-axes. Motion in each dimension is independent of the other.
Solve for the unknowns in the two separate motions—one horizontal and one vertical. We do this using the same procedure as in 1D motion.

Common mistakes and misconceptions

Some students forget that motion in the x- and y-direction are independent. What happens in the x-direction does not affect the y-direction and vice versa.
Make sure to define the coordinate axes and pay attention to the sign of the acceleration constant g. If upward is positive and a ball falling down toward the Earth, a, start subscript, y, end subscript is minus, 9, point, 8, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction because the acceleration is in the negative direction.

Learn more

For deeper explanations, see our video on horizontally launched projectiles.

To check your understanding and work toward mastering these concepts, check out the exercise on solving kinematic equations for horizontal projectiles.

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Thandeka
Posted 4 years ago. Direct link to Thandeka's post “a plane is travelling wit...”
a plane is travelling with twice the horizontal velocity that is, with a velocity 230 m/s. if all other factors remain the same, determine the time required for the package to hit the ground.
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(4 votes)
Answer
- RDHMJJ
  Posted 4 years ago. Direct link to RDHMJJ's post “it's going be the same ti...”
  it's going be the same time for the package to hit the ground, but the horizontal displacement is twice as before
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  (7 votes)
Zabia Sotirakos
Posted 3 years ago. Direct link to Zabia Sotirakos's post “how does increasing/decre...”
how does increasing/decreasing the height of a horizontal projectile impact the time and horizontal displacement?
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(2 votes)
Answer
- KLaudano
  Posted 3 years ago. Direct link to KLaudano's post “If you increase the initi...”
  If you increase the initial height of the projectile, it will take longer to fall to the ground, so the impact time will be larger. If the projectile is in the air longer, it will have more time to travel horizontally. So, the horizontal displacement will be larger.
  Button navigates to signup page
  (4 votes)
nick.rinando2024
Posted 8 months ago. Direct link to nick.rinando2024's post “how will this affect the ...”
how will this affect the trout population?
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(2 votes)
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- rylan.wetsell
  Posted 4 months ago. Direct link to rylan.wetsell's post “It depends on how tough t...”
  It depends on how tough they are.
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  (2 votes)
350094991
Posted 3 years ago. Direct link to 350094991's post “Hi, how can you prove the...”
Hi, how can you prove the formula for the range of a projectile motion R=(v^2*sin2θ )/g ??
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(2 votes)
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Ah'mir White
Posted 10 months ago. Direct link to Ah'mir White's post “hi hi”
hi hi
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(2 votes)
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rosilesay6231
Posted 4 months ago. Direct link to rosilesay6231's post “This should've included t...”
This should've included the way that the variables were written and worked out in the "Horizontally launched projectile" video so that people know how to solve equations by writing their known and unknown variables.
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(1 vote)
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rafiaabdulsamad82
Posted 7 months ago. Direct link to rafiaabdulsamad82's post “in half projectile why in...”
in half projectile why initial vertical component is zero
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(1 vote)
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- rylan.wetsell
  Posted 4 months ago. Direct link to rylan.wetsell's post “The initial vertical velo...”
  The initial vertical velocity is 0 because at 0 seconds you are not moving down at all.
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  (1 vote)
zawarcheema10
Posted 5 years ago. Direct link to zawarcheema10's post “The mounting system for a...”
The mounting system for a reciprocating engine weighting 60kg can be considered to be a vertically mounted spring. the spring stiffness is 110kN/m and a maximum amplitude of the vibration when the engine is running is 14mm. The engine has a mass of 250 kg . assume that the vibration can be moddeled by Simple harmonic motion
1.Determine the angular velocity of the vibration spring
2. determine the maximum linear velocity of the vibration
3.calculate the linear velocity of the engine at 4mm from the maximum amplitude
4. Calculate the linear acceleration of the engine at 4mm from the maximum amplitude and the force produced.
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(1 vote)
Answer