AP®︎/College Physics 1
- Question 1a: 2015 AP Physics 1 free response
- Question 1b: 2015 AP Physics 1 free response
- Question 1c: 2015 AP Physics 1 free response
- Question 2ab: 2015 AP Physics 1 free response
- Question 2cd: 2015 AP Physics 1 free response
- Question 3a: 2015 AP Physics 1 free response
- Question 3b: 2015 AP Physics 1 free response
- Question 3c: 2015 AP Physics 1 free response
- Question 3d: 2015 AP Physics 1 free response
- Question 4: 2015 AP Physics 1 free response
- Question 5: 2015 AP Physics 1 free response
How doubling spring compression impacts stopping distance.
Want to join the conversation?
- Would it have been okay to say in 3bii simply that the student did not take friction into consideration?(3 votes)
- No – the student did not mention friction because it was already taken into account in question 3a. Friction is definitely still being considered, since it is the force making the block decelerate and come to a stop in the first place!(1 vote)
- At5:19, why does Sal say that 4 times energy will result in 4 times the stopping distance? I think the final stopping distance depends on (4E-Wf),which is the differnce between 4 times the initial energy and the work done by friction.The work done by friction remains the same as in part a), so the final stopping distance should not be as simple as 4 times the initial distance.Thank you very much who see my question and point out the answer.(2 votes)
Sal gives a mathematical idea of why it's 4 times the initial distance in this video(0 votes)
- What was Sal's explanation for his response for b) i. ?(1 vote)
- Essentially, Sal was acknowledging that compressing a spring further results in an increase in potential energy in the system, which is transformed into a increased amount of kinetic energy when the block is released. The part the student got wrong was the proportionality between the compression distance and the energy in the system (and thus the distance the block slid).(1 vote)
- 5: 29 what about velocity? energy gets quadrupled but velocity is squared in KE. Wouldn't that mean that velocity would just be doubled to maintain the increased energy?(0 votes)
- [Voiceover] The spring is now compressed twice as much, to delta x equals 2D. A student is asked to predict whether the final position of the block will be twice as far at x equals 6D. The student reasons that since the spring will be compressed twice as much as before, the block will have more energy when it leaves the spring, so it will slide farther along the track before stopping at position x equals 6D. So, let's just think about what the student is saying or what's being proposed here. So, in the first version, the first scenario, we compressed the block, we compressed the spring by D. And then, the spring accelerates the block. And then, right when we get back to x equals zero, all of that potential energy has been turned into kinetic energy. And then, the friction is acting against the motion of the block, so you can view it as it's providing negative work. The direction of the force is opposite to the change in x. And the negative work eventually causes the block to stop. And all of that kinetic energy has now turned into heat. And so, the block goes 3D. Now, this new scenario, we could call that scenario two, we are going to compress the spring twice as far. So, now we're gonna compress the spring twice as far. So, we're gonna compress it by 2D. So, this is x equals negative 2D here. And what's being said, or what's being proposed, by the student is alright, if we compress it twice as far, all of this potential energy is then going to be, we're definitely going to have more potential energy here because it takes more work to compress the spring that far. And then, all of that more potential energy is gonna be converted to more kinetic energy once we get back to x equals zero. And so, not only will it go further, but they're saying it'll go exactly twice as far. So, we are going to go, instead of going to 3D, we are now going to go to 6D. Now, let's read. Let's see what the questions are here. And actually, I'm gonna put a question mark here since I'm not sure if that is exactly right. So, part (b) i., let me do this. So, we're in part (b) i. It says which aspects of the student's reasoning, if any, are correct. Explain how you arrived at your answer. And then, part two says which aspects of the student's reasoning, if any, are incorrect. Explain how you arrived at your answer. So, the student is correct that two times, so compressing more, compressing spring more, spring more, will result in more energy when the block leaves the spring, result in more energy when block leaves the spring, block leaves spring, which will result in the block going further, which will result, or the block going farther I should say, which will result in longer stopping distance, which will result in longer stopping stopping distance. Now, part two. Part two, here. Which aspect of the student's reasoning, if any, are incorrect. Explain how you arrive at your answer. Well, two times I could say, let me say compressing, compressing twice as much, twice as much, does not result in exactly twice the stopping distance, does not result in twice the stopping distance, the stopping distance. And we can explain more if we like. We know that potential energy is equal to 1/2 times the spring constant times how much we compress, squared. So, we could say that energy, energy grows with the square, with the square, of compression of how much we compress it. of how much we compress. So, two times the compression. I'm gonna say two times. I'll write it out, two times compression will result in four times the energy. Energy. And this will result in four times the stopping distance, four times stopping distance, four times stopping, stopping, distance. I think that it does a decent job of explaining where the student is correct, where their reasoning is correct, and where it is incorrect.