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what's Newton's first law say Newton's first law states that objects don't change their velocity unless there's an unbalanced force so if there is no force on an object or the forces are balanced then the object will continue moving with a constant velocity or if it was at rest it'll continue sitting at rest in other words there doesn't have to be a net force for something to have motion there only has to be a net force for something to have acceleration and it's really important to note that Newton's first law does not only apply to single objects it applies to systems of objects as well in other words if you consider a system of objects and look at the center of mass of that system the center of mass of the system will remain at rest or remain in constant motion as long as there's no external unbalanced forces on the system so these objects may be exerting forces on each other but the center of mass will remain at rest or with constant velocity unless there's an unbalanced external force on this system of particles so what's an example problem involving Newton's first law look like say you were told that a heavy elevator is lifted upward by a cable exerting a force F C and the elevator moves up with a constant velocity of five meters per second we want to know how the force from the cable compares to the force of gravity the mistake many people make is they think that since the object was moving upward the upward force must be larger but that's not true since this is moving upward with constant velocity the forces actually have to balance since Newton's first law states that when the net force is zero the object maintains a constant velocity and for the net force to be zero these forces have to cancel so even though it's non-intuitive this cable force has to equal the force of gravity so that the elevator can move with constant velocity what's Newton's second law mean Newton's second law states that the acceleration of an object is proportional to the net force and inversely proportional to the mass which written in equation form states that the acceleration of an object is equal to the net force on that object divided by the mass of the object and this equation works for any single direction as well in other words the acceleration in the X Direction is equal to the net force in the X Direction divided by the mass and the acceleration in the Y direction equal to the net force in the Y Direction divided by the mass so what's an example of Newton's second law look like let's say a 5 kilogram space rock had the forces acting on it shown in this diagram and we wanted to determine the acceleration in the horizontal direction since horizontal is the X direction we're only going to use forces in the X direction to determine the acceleration in the X direction that means the 15 Newton force and the 5 Newton force don't contribute at all to the acceleration in the X direction the only components that contribute are the horizontal component of the 10 Newton force which would be 10 cosine of 30 and the 40 Newton force so the acceleration in the X Direction would equal the net force in the X direction which would be 10 cosine 30 that would be a positive contribution since it points to the right minus 40 since that's a negative contribution pointing to the left and finally we divide by 5 kilograms which gives us the correct acceleration in the X direction what's Newton's third law mean Newton's third law states that if an object a is exerting a force on object B then object B must be exerting an equal and opposite force back on object a and this is true even if the objects have different sizes or there's acceleration in other words let's say the earth is pulling on an asteroid even though the earth is much larger than the asteroid the asteroid is going to exert an equal and opposite force back on the earth and this is true whether the asteroid is moving with constant velocity or whether it's accelerating so what's an example problem involving Newton's third law look like let's say a metal sphere is sitting on a cardboard box and we want to determine which of these choices constitute a Newton's third law force pair the first option says that there's an upward force on the sphere from the box so to find the third law pair just reverse the order of the objects which means the partner to this force would be the force on the Box by the sphere which is not what this says so it's not option a option B refers to an upward force on the Box from the table which we know if we reverse the labels should have a partner force that would be the force on the table by the box which is not what this says so it's not option B option C talks about an upward force on the sphere from the box which reversing the labels gives us a partner force of box by sphere which is not what this says so it's not option C and D refers to an upward force on the box from the table which if we reverse the labels gives us a partner force on the table by the box which is what this says and so the force is in D constitute a Newton's third law force pair which means they must always be equal and opposite other pairs might be equal and opposite but no matter what happens these two forces have to be equal and opposite how do you find the force of gravity on objects near the earth the force of gravity on all objects near the earth is down toward the center of the earth and it's equal to the mass times the acceleration due to gravity another word for the force of gravity is the weight of an object but be careful the weight is not the mass weight is the force of gravity which means weight is M times G not just M the force of gravity is a vector and it has units of Newton's so what's an example problem involving the force of gravity look like let's say you knew the mass and weight of a watermelon to be 5 kilograms and 49 Newtons when you measure them on the earth what might the values for mass and weight of that watermelon be when it's brought to the moon the value of the mass isn't going to change here since it's a measure of the total amount of substance in that object but the weight of the watermelon on the moon is going to be less since the gravitational pull is going to be weaker on the moon so the only choice consistent with those two conditions is a since the mass stays the same and the weight decreases what's the normal force the normal forces the outward force exerted by and perpendicular to a surface there's no formula specifically to find the normal force you simply have to use Newton's second law let normal force be one of the unknowns and then solve for it now if you've just got a mass sitting on a horizontal surface and there's no extra forces involved the normal force is just going to counter the force of gravity which means the normal force will just be mg but if there's extra forces or there's acceleration in the direction of the normal force then the normal force is not going to equal mg and you'd have to use Newton's second law for that direction to solve for it the word normal and normal force refers to the fact that the force is always perpendicular to the surface exerting that force and it's good to remember that for a mass on an incline that normal force is not going to equal to mg it's going to be mg times cosine of theta the normal force is a vector since it's a force and it also has units of Newton's so what's an example problem involving normal force look like let's say a person is pushing on a stationery box of mass M against the ceiling with a force F P and they do so at an angle theta we want to know what's the magnitude of the normal force exerted on the box from the ceiling so we'll draw a force diagram there's the force F P from the person the force mg from gravity if the box is stationary there'd have to be a force preventing it from sliding across the ceiling which is most likely static friction and there's also going to be a normal force but that normal force will not point upward the normal force from the ceiling cannot pull up on the box the normal force from the ceiling will only push out on the box which will be downward since our normal forces in the vertical direction will analyze the forces in the vertical direction and we can see that the forces must be balanced vertically since this box has no motion vertically in other words the normal force plus the gravitational force is going to have to equal the vertical component of the force FP which since that's the opposite side from this angle we can write as FP sine of theta and now we can solve for the normal force which gives us FP sine theta minus mg note that we did not have to use the force of friction or the horizontal component since our normal force was in the vertical direction what's the force of tension mean the force of tension is any force exerted by a string rope cable cord or any other rope like object and unlike the normal force that can only push tension can only pull in other words ropes can't push on an object but similar to the normal force there's no formula for tension to find the tension you'd insert the tension as an unknown variable into Newton's second law and then solve for it since the force of tension is always pulling on objects when you draw your force diagram make sure you always draw those tension forces directed away from the object the string is exerting the tension on tensions a vector since it's a force and it has units of Newton's so it's an example problem involving tension look like let's say two ropes are holding up a stationary box and we want to know how the magnitudes of the tensions in both ropes compare drawing our force diagram there'll be a downward force of gravity a force of tension to the left and also a diagonal force of tension up and to the right since the boxes stay canary the forces have to be balanced in every direction that means the vertical component of t2 has to equal the magnitude of the force of gravity and the horizontal component of t2 has to equal the magnitude of the force t1 but if a component of t2 equals the entire t1 then the total tension t2 has to be bigger than t1 in other words if part of t2 is equal to t1 then all of t2 is greater than t1 what's the force of kinetic friction mean the force of kinetic friction is the force exerted between two surfaces that are sliding across each other and this force always resists the sliding motion of those two surfaces the force of kinetic friction is proportional to the normal force between the two surfaces and it's proportional to the coefficient of kinetic friction between the two surfaces note that the force of kinetic friction does not depend on the velocity of the object in other words if the normal force and coefficients stay the same then no matter how fast or slow the object moves no matter how hard or soft you poll the force of kinetic friction is going to maintain the same value since kinetic friction is a force it is a vector and it has units of Newton's so what's an example problem involving kinetic friction look like so you've got this question about a car traveling at cruising speed slamming on the brakes and skidding to a stop we want to know what two changes could be made that would increase the distance required for the car to skid to a stop get some intuition about what would cause this car to skid farther we could use a kinematic formula since the car skids to a stop the final velocity would be zero if we solve for the distance we get negative V naught squared over two times the acceleration so in order to get the car to skid further we could increase the initial speed of the car or reduce the deceleration to figure out what reduces the magnitude of the acceleration we'll use Newton's second law the force slowing the skidding car is the force of kinetic friction and since there's no extra vertical forces the normal force is just M times G since the mass is cancelled the acceleration won't depend on the mass of the car but reducing the coefficient of friction will reduce the deceleration and reducing the deceleration will increase the distance the car skids to a stop the force of static friction tries to prevent the two surfaces from slipping in the first place and that for of static friction will match whatever force is trying to budge the object until that budging force matches the maximum possible static frictional force which is proportional to the normal force and the coefficient of static friction so if the maximum value of the static frictional force is a hundred Newtons and you try to budge the object with eighty Newtons the static frictional force will just oppose you with eighty Newtons preventing the object from slipping if you exert 90 Newtons the static frictional force will increase to 90 Newtons preventing the object from slipping but if you exert a hundred and ten Newtons since this exceeds the maximum possible static frictional force the object will budge and there will only be a kinetic frictional force now that the object is sliding so it's an example problem involving the force of static friction look like let's say you push on a refrigerator that's 180 kilograms and the coefficient of static friction between the floor and the fridge is 0.8 if you exert 50 Newtons on the refrigerator what's the magnitude of the static friction force exerted on the refrigerator will first find the maximum possible static frictional force using Miu s times FN since there's no extra vertical forces the normal force will just be mg plugging in values we get a maximum possible static frictional force of fourteen hundred and eleven Newtons but this will not be the value of the static frictional force this is just the maximum value of the static frictional force so if we exert 50 Newtons to the right since that does not exceed this maximum possible static frictional force static friction will just oppose us with an equal 50 Newtons to the left and it will continue to match whatever force we exert until we exceed the maximum possible static frictional force how do you deal with inclines inclines are just angled surfaces that objects can slide up or down and since the object can't move into the incline or off of the incline the motion will only be taking place parallel to the surface of the incline there will be no acceleration perpendicular to the surface of the incline so instead of breaking our forces into x and y we break them into forces perpendicular to the surface and parallel to the surface the component of gravity that's parallel to the surface is going to equal mg sine theta where theta is the angle between the horizontal floor and the ink lined surface and the component of gravity perpendicular to the surface is going to be mg cosine theta where again theta is the angle measured between the horizontal floor and the angled surface since there's no acceleration perpendicular to the surface the net force in the perpendicular Direction has to be zero and that means this perpendicular component of gravity has to be exactly canceled by the normal force which is why the value for the normal force is the same as the perpendicular component of gravity and since those perpendicular components cancel the total net force on an object on an incline is just going to equal the component of the net force that's parallel to the surface of the incline which if there's no friction would simply be mg sine theta and if there was friction it would be mg sine theta minus the force of friction but be careful when you're finding the force of friction on an incline the normal force will not be M times G the normal force is going to be mg cosine theta so what's an example problem involving inclines look like let's say a box started with a huge speed at the bottom of a frictionless ramp and then it slides up the ramp and through these points shown W XY and Z we want to rank the magnitudes of the net force on the box for these points that are indicated when the box is flying through the air we know the net force is simply the force of gravity straight down which is M times G so then that force at y&z are equal and on an incline the net force is the force component that's parallel to the surface of the incline which is going to be mg sine theta note that the net force on the incline points down the incline even though the mass moves up the incline that just means the mass is slowing down but since mg is greater than mg sine theta Z and y are greater than the net force at XM w what is treating systems as a single object mean this is a trick you can use when two or more objects are required to move with the same speed and acceleration which will allow us to avoid having to use multiple equations to find the acceleration and instead use one equation to get the acceleration when you treat a system of objects as a single object you get to ignore internal forces since the internal forces will always cancel this means you can find the acceleration of the system by looking at only the external forces on that system and then dividing by the total mass of that system so what's an example of treating systems as a single object look like let's say a mass m1 is pulled across a rough horizontal table by a rope connected to mass m2 if the coefficient of kinetic friction between m1 in the table is mu K then what's an expression for the magnitude of the acceleration of the masses so instead of analyzing the forces on each mass individually which would give us multiple equations and multiple unknowns we'll use 1 equation of Newton's second law but we'll treat this system as if it were a single object which means we're basically just going to ask what external forces are going to make this system go and what external forces are going to make this system stop the external force that makes the system go is the force of gravity on m2 it's an external force since it's exerted by the earth which is not part of our system and it's making the system go so we'll call that for is positive and we'll call forces that try to make our system stop negative like this force of kinetic friction on M 1 which is also external because the table is not part of the mass of our system but we will not include the force of tension since this is an internal force and these forces will cancel now since we're treating this system as a single mass will divided by the total mass of our system and then if we write the force of kinetic friction in terms of the coefficient we get Miu K times the normal force and the normal force on M 1 is going to be M 1 times G which with a single equation gives us an expression for the acceleration of our system without having to solve multiple equations with multiple unknowns you

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