Voiceover: In this video,
we're going to look at the SP three hybridization present in methane and ethane;
let's start with methane. So that's CH four, if I
want to draw a dot structure for methane, I would
start with carbon, and its four valence electrons,
and then we would put hydrogen around that; each hydrogen has one valence electron,
so we go ahead and draw in our hydrogens with
one valence electron, and that gives us the Lewis Dot structure. Usually you see it drawn
like this, with carbon with its four bonds to hydrogen around it, like that, and in methane,
all of these bonds are equivalent, in terms of things like bond length and energy. And so the four valence electrons that carbon brought to
the table over here, let me go ahead and highlight those four valence electrons, those should be equivalent, and if
we look at the electron configuration for carbon, let's go ahead and do that right now. It's one S two, so go ahead
and put in two electrons in the one S orbital, two S two, go ahead and put in two electrons
in the two S orbital, and then two P two, and so, I'm assuming you already know your
electron configuration, so it would look something like that. If we look at those four valence electrons on our orbital notation
here, that would be these four electrons here,
the valence electrons in the outer shell. And if we look at this,
this implies that carbon would only form two bonds,
because I have these unpaired electrons right
here, and everything's of different energies, and so, what we see from the dot structure and experimentally, doesn't quite match up with
the electron configuration here, and so to explain this difference, Linus Pauling came up with
the idea of hybridization. And so, the first thing
that he said was, you could go ahead and take out
one of these electrons in the two S, and promote
it up to the P orbital here, so let me go ahead and
show that, so we've moved one of those electrons
up to the two P orbital, so we're in the excited state now. And now we have the
opportunity for carbon to form four bonds, however,
those electrons are not of equivalent energy, and
so Linus Pauling said, "Let's do something else here: "Let's go ahead and
promote the two S orbital," so we're gonna take this S orbital, and we're gonna promote it in energy, and we're going to take these P orbitals and
demote them in energy, so we're gonna lower those
P orbitals, like that, so we have our P orbitals here. And these had one
electron in each of them, but we're gonna hybridize
them, so this is no longer going to be an S orbital; it's going to be an SP three hybrid
orbital; this is no longer going to be a P orbital; it's going to be a SP three hybrid orbital,
and same with these. So the idea is, you're taking
some of the S character, and some of the P character,
and you're hybridizing them together into brand new orbitals, and since you're taking
this from one S orbital and three P orbitals,
we're doing this using one S orbital and three P
orbitals, we call this SP three hybridization, so this is
SP three hybridization: We create four new, hybrid orbitals. And now we have what we're looking for, because now we have
four unpaired electrons, so carbon can form four
bonds now, and they're equal in energy, so that's
the idea of hybridization. All right, let's think
about the character, or the shape of this new hybrid orbital. Well, we know that an S orbital
is shaped like a sphere, so we're taking one of
those S orbitals here, so one S orbital, and
we know that a P orbital is shaped like a dumbbell, so we're taking three of these P orbitals here. So one of these S orbital,
and three of these P orbitals, and we're
going to hybridize them together, and when that
happens, in turns out the shape of the new
hybrid orbital you get, has this large frontal
lobe here, like this, and then a smaller back
lobe, back here like this; so we're gonna make four of these. All right, so once again
we have four SP three hybrid orbitals, and
each one of these hybrid orbitals is gonna have an electron in it, so we can see that each one of these SP three hybrid orbitals
has one electron in there, like that, and so the
final orbital, the final hybrid orbitals here contain
25 percent S character. Let me go ahead and write this down here: So 25 percent S character,
and 75 percent P character, in this new hybrid orbital. Once again, that's because
we started out with one S orbital and three P orbitals
for our hybridization. All right, let's go back
to methane, and let's go ahead and draw in a
picture, because now we know that this carbon is SP three hybridized, so let's go ahead and draw a picture of that hybridized carbon, here. So we're gonna go ahead
and draw in our carbon, and we know that it has four
SP three hybrid orbitals, and once again, when we draw the orbitals, we're gonna ignore the
smaller back lobe here, so it doesn't confuse us. So we go ahead and draw in,
here's one of our orbitals, for carbon, so that's an
SP three hybrid orbital. Here's another SP three hybrid orbital, here's another one, and
then, finally, a fourth one. So let's go back up here, to this picture, 'cause once again, we
need to show that each of these hybrid orbitals
has one valence electron in it, so I can go ahead and put in my one valence electron, in
each of my hybrid orbitals, like that, so here's our valence electron. If we're talking about
methane, so carbon is bonded to four hydrogens, each
hydrogen has an un-hybridized S orbital, and each
hydrogen has one electron in that, so I'm gonna go
ahead and sketch that in; let's go ahead and use blue here. So here's an un-hybridized
S orbital, I'm gonna go ahead and draw these
in, so an un-hybridized S orbital; each one of these
un-hybridized S orbitals for hydrogen has one valence
electron, so I'm gonna go ahead and put in those
one valence electrons, in here, like that, so same for here, and then, finally, for here. So this is just one picture
of the methane molecule, so this is hydrogen, these
are all the hydrogens right here, like that. All right, let's think about
this bond that we formed right here, so here we have
an overlap of orbitals, an overlap of an SP three
hybrid orbital form carbon, with a un-hybridized S
orbital from hydrogen here, and so this is a head-on overlap, so we're sharing electrons here,
in this head-on overlap. And a head-on overlap, in
chemistry, is called a sigma bond, so this is a sigma bond, sigma bond here, a head-on overlap, and this
happens three more times in the methane molecule. So here's a head-on overlap,
here's a head-on overlap, and here's a head-on overlap. And so we have a total of four sigma bonds in the methane molecule,
so a single-bond here, instead of saying a
single-bond now, we're saying it's also can be called, "a sigma bond," and so this head-on overlap. Let's look at the ethane
molecule now, so for ethane, we'll go ahead an draw
that in, so ethane would be C two H six, so we have
two carbons; let's go ahead and draw in those two carbons,
and then six hydrogens, so we put in our six hydrogens
around there, like that. All right, when we're
thinking about hybridization, we've just seen, with
methane, that a carbon atom with four single-bonds will
be SP three hybridized. So I go back up to here,
this carbon right here, four single-bonds; it's
SP three hybridized, we could use that same logic and apply it to ethane, here. Each of the carbons in
ethane has four single-bonds, so each carbon in ethane
is SP three hybridized, so let me go ahead and put
SP three hybridized here, so let's go ahead, and draw
the picture with the orbitals. So let's get some more room. If each carbon is SP three
hybridized, that means each carbon is gonna have
four SP three hybrid orbitals. So I can go ahead and
sketch in one carbon, once again, I'm ignoring the back lobe, one carbon with four SP
three hybrid orbitals, and we know the other carbon
is also SP three hybridized, so I can sketch in four
SP three hybrid orbitals for this one too, so
here's my four SP three hybrid orbitals for this carbon. All right, in terms of
electrons, let's go ahead and put in our electrons here. So, let's see, there's one
electron in this orbital, one electron in this orbital,
one electron in this orbital, one electron from this carbon. And then, for this other
carbon, so there's one electron in this orbital,
one electron in this orbital, one electron in this
orbital, and one electron in this orbital. And then we can go ahead
and put in our hydrogens, so we know each hydrogen
has an un-hybridized S orbital, with one valence electron, so I can go ahead and do that. And I'll draw in the
rest of our hydrogens, so that's four hydrogens, five hydrogens, and then six hydrogens, like that. All right, we just said that a sigma bond is a head-on overlap of orbitals. So, here we have a head-on
overlap of orbitals, the bond between the two carbons, and then, of course, all of these are too. So when we count all of
those up, that's four, five, six, and seven; so there are seven sigma bonds in the ethane molecule, so seven sigma bonds here. And we could go up here
to this dot structure, and look at them again,
so here's one, two, three, four, five, six, and then seven: Seven sigma bonds. Let's focus in on the bond
between the two carbons now, so this sigma bond,
right in here, so that's a sigma bond, and there's free rotation about this sigma bond,
so if you could imageine rotating around this
bond, so these carbons can rotate in space, and
that's gonna give different conformations, so you could
have different confirmations of the ethane molecule,
which is in later videos. So you have free rotation
about sigma bonds. Let me go ahead and write that, 'cause that's pretty important, so free rotation about sigma bonds. And then, the last thing
I wanted to point out, about the ethane molecule
here, is the bond length: So the length between this
carbon and this carbon, so this bond length, in
here, turns out to be approximately one point
five four angstroms, so you'll see slightly different values in different textbooks, but we'll say it's approximately this
value, and the reason we wanna know that, is we're gonna compare this carbon-carbon bond
length to the bond length in some other molecules,
in some later videos.