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## Multiplication rule for dependent events

# Dependent probability

## Video transcript

Voiceover:Suppose that
Erika simultaneously rolls a 6-sided die and a 4-sided die. Let A be the event that she rolls doubles, let me write this, A be the event that she rolls doubles and B be the event that
the 4-sided die is a 4. Use the sample space of
possible outcomes below to answer each of the following questions. Fair enough. What is probability of A, the probability that Erika rolls doubles? Over here, we have our sample
space of possible outcomes. Each of these are equally likely, and so let's see how
many of them there are. There are 1, 2, 3, 4 by 1, 2, 3, 4, 5, 6, so there are 24 possible outcomes, which makes sense. There's 4 possible outcomes
for the 4-sided die and 6 possible outcomes
for the 6-sided die, so you have a total of 24
equally likely outcomes, so probability of, let me write it here, so probability of A is
going to be the fraction of the 24 equally likely outcomes that involve event A, that she rolls doubles. Let's think about that. This is she has rolled doubles, 1 and a 1. They don't look the same
but they're both 1s. Let's see. We have a 2 and a 2. We have a 3 and a 3, and we have a 4 and a 4. And it's impossible to have a 5 and a 5 because the 4-sided die only goes up to 4. So there's 4 possibilities, 4 of the 24 equally likely possibilities involve rolling doubles. There is a 4/24 probability, or if we divide the numerator
to the denominator by 4, it is a 1/6 probability that Erika, a 1/6 probability that
Erika rolls doubles. What is probability of B, the probability that
the 4-sided die is a 4? The probability of B, well, once again, there's 24
equally likely possibilities, and how many of them involve
the 4-sided die being a 4? You have all of these right over here involve a 4-sided die being a 4. So this is 1, 2, 3, 4, 5, 6 of the 24 equally likely possibilities, or you could say 1/4 of the
equally likely possibilities or the probability is 1/4, which makes sense
because probability of B, it ignores the 6-sided die, and it just says what's the probability that the 4-sided die is 4? Well, that's 1 one of
the 4 possible outcomes for that 4-sided die. What is the probability of A given B, the probability that Erika rolls doubles given that the 4-sided die is a 4? Let's just think about this a little bit, probability of A given
that B has happened, given that B has happened. Essentially, we are restricting our equally likely possibilities now to the situation where B has happened. Given B means we're assuming
that B has happened. Now, we're restricting our sample space of possible outcomes where B has happened to this right over here. Now there are 1, 2, 3, 4, 5,
6 equally likely outcomes. How many of them involve A happening? This one right over here
that we had already circled, this is the one out of the
6 equally likely outcomes that involve doubles, so there is a 1/6 probability. Now that makes sense. Let me just write this down. This is 1 over 6. Why does this make sense? Because with a 4-sided
die we're assuming is a 4. So essentially, this
is analogous to saying when you roll a 6-sided die, what's the probability
that you get a 4 as well, because that's the only way
you're going to get doubles, given that the 4-sided die is 4. And we see that right over here. The 6-sided die has to be a 4 as well in order for this to be doubles because we're assuming it's given that B, we're given event B, we're restricting our
sample space with event B. What is the probability of B given A, the probability that the 4-sided die is 4 given that Erika rolls doubles? Let's just think about that a little bit. The probability of B given A, B given that A is true. So what's this going to be? This means we're going to
restrict our sample space to essentially 4 equally likely
outcomes that A has happened so where A is true, I guess I could say. So there's 1, 2, 4. And how many of them
involve event B being true? Well, the only one of these 4 that involve event B being true is
this one right over here, where we've got our doubles. So there is a 1/4 probability
that if we assume, given that we've gotten doubles, the probability that
the 4-sided die is a 4. This is a 1/4 probability, and that makes sense. If we've got doubles and one
of them is a 4-sided die, we either have doubles at 1, doubles at 2, doubles at 3, or doubles at 4. You see that here, doubles 1, doubles 2, doubles 3, doubles 4. Well, given that, what's the probability that the 4-sided die is 4? Well, that means that's
one out of these 4 outcomes where it's a double 4 is right over here. All right. What is the probability of A and B, the probability that Erika rolls doubles and the second die is 4? This means both A and B happened. Let's look at this. Actually let me write it here. Let me do it in a new color. The probability of, and I'll write "and"
here in a neutral color, the probability of A and B. Probability of A and B is equal to. Well, now, we're looking at once again, we have 24 equally likely outcomes. We have 24 equally likely outcomes. How many of them involve A and B? To get A and B, you have to have doubles and the 4-sided die needs to be a 4. Essentially, you have to have doubles 4. Well, there's only one outcome out of the 24 equally likley outcomes that meets that situation, this one right over here, so there is a 1/24 probability, 1/24. What is probability of A times
probability of B given A? Here, we could just go back to
our numbers right over here. Probability of A, that's going to be 1/6. Let me do that in a magenta color. I like to keep my colors,
be careful about my colors. That's 1/6 times the
probability of B given A. So the probability of B given
A is 1/4 right over here, times 1/4, which is, curious enough, 1/24, 1/24. What is probability of B times
probability of A given B? Probability of B, we figured out, is 1/4, 1/4, and the probability of A given B is 1/6, times 1/6, which is equal to 1/24. Now does it make sense that the probability of A and B is 1/24, the probability of A times
probability of B given A is 1/24, and the probability of B times
probability of A given B, they're all 1/24? Is this always going to be the case? Well, sure. Think about what probability
of A and B means. What I mean is that they both happened. But that's the same way as saying what's the probability of, let's just say A is happening. Well now, for B and A to happen, it's just going to be
that times the probability that B is true given that A is true, because you could say, well,
are you constraining it. We're already multiplying by the probability of A being true, and now we're multiplying
by the probability that B is true given A is true. I actually often like to swap these around just so it gets a little
bit clearer in my head. This one, let's just write it like this, the probability of B given A times the probability of A. This is the probability
that event A is true, and this is the probability
that event B is true given that we know that A is true. It completely makes sense that this is going to be the same thing as the probability of A and B. Clearly, this is a
probability of both of these, both A and B happening. You can go the other way around. The probability of A given B times the probability of B, that would also be, so B ... We're saying B needs to be true, and that given that B is true, that A needs to be true as well, so it makes complete sense that this is going to be the probability of A and B as well.