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## Precalculus

### Course: Precalculus > Unit 3

Lesson 6: Polar form of complex numbers# Polar & rectangular forms of complex numbers

CCSS.Math:

Sal rewrites the complex number -3+2i (which is given in rectangular form) in its polar form. Created by Sal Khan.

## Want to join the conversation?

- In the video he just rounds when finding the polar form, but in the problems you have to find exact answers. In the hints, they just jump from from arctan(b/a) to the answer in radians in exact form so I have no idea how to do it.(26 votes)
- We know that...
`+------+---------+---------+---------+`

|α |π/6 |π/4 |π/3 |

+------+---------+---------+---------+

|sin(α)|1/2 |sqrt(2)/2|sqrt(3)/2|

|cos(α)|sqrt(3)/2|sqrt(2)/2|1/2 |

|tan(α)|sqrt(3)/3|1 |sqrt(3) |

+------+---------+---------+---------+

These numbers and angles should be remembered. One easy way to remember them is that, in the sin row, the number given to sqrt gets incremented with each column, and that on the cos row it decrements with every column. With tan, you can remember that that tan(α) = sin(α)/cos(α).

We can use those values to help us get the exact answer to a problem. For example, let's say that we have 3 - 3i and want to know the angle (α) of this complex number. We know that tan(α) = -3/3 = -1. We can say that α = arctan(tan(α)) but how do we find the exact value of arctan(-1)? We know that an angle of π/4 has a tangent of 1. Therefore, arctan(1) = π/4. Which allows us to conclude that arctan(-1) = -π/4. So, α = arctan(-3/3) = -π/4. Some calculators might do the job for you.

Hope I helped. :)(32 votes)

- Hello

How do I convert the results into exact values?

It´s not clear in the exercises, do I use the trignometric table?

e.g. How do I convert 6*cos(135) to −3√2 ?

It must be simple, but for the life of me I don´t get it ::::::(14 votes)- Ah, you must familiarize yourself with the unit circle and special triangles, 45-45-90 and 30-60-90.

Because 135 is 90+45, then it would make a 45-45-90 triangle on the II quadrant. From the unit circle we would know cos(45) is √(2)/2 and it is in II quadrant so it's negative. So -√(2)/2*6 = -3√(2).

Sal has videos covered on all these. You can search for it.(17 votes)

- at10:20why does he rewrite the expression in terms of rcostheta+sinthetai? isn't the polar form just (r,theta)?

Why not just write (sqrt13,2.55)? I'm so confused.(3 votes)- The rectangular representation of a complex number is in the form
`z = a + bi`

.

If you were to represent a complex number according to its Cartesian Coordinates, it would be in the form:`(a, b)`

; where`a`

, the real part, lies along the x axis and the imaginary part,`b`

, along the y axis.

The**Polar Coordinates**of a a complex number is in the form`(r, θ)`

.

If you want to go from Polar Coordinates to**Cartesian Coordinates**, that is just:`(r*cos(θ), r*sin(θ))`

.

Since we saw that the**Cartesian Coordinates**are`(a, b)`

, then:`a = r*cos(θ)`

`b = r*sin(θ)`

And since the rectangular form of a Complex Number is`a + bi`

, just replace the letters:`a + bi = r*cos(θ) + r*sin(θ)`

← The right-hand side is a Complex Number in**i****Polar Form**.

Take a look at the difference between a Polar Form and a Polar Coordinate.(21 votes)

- I didnt really get it.. What are radians? And why is he not measuring it in terms of the angles?(0 votes)
- Radians are special units that relate to the unit circle.
`https://en.wikipedia.org/wiki/Unit_circle`

Wikipedia has a fantastic .gif showing the derivation of a Radian`https://en.wikipedia.org/wiki/Radian`

`https://en.wikipedia.org/wiki/File:Circle_radians.gif`

Radians are helpful when encountering sin/cos functions and a variety of other physics applications where pi shows up.(16 votes)

- Why does the current video come
**after**this much more complicated video that is earlier in the series: https://www.khanacademy.org/math/precalculus/imaginary_complex_precalc/complex_analysis/v/polar-form-complex-number ? Seems like the current video is a review of that earlier video, but without the way more complicated part regarding exponential form.(7 votes) - I think I get going from rectangular to polar, but when converting from polar to rectangular, how do you get the exact values of the trig calculations? I always get a decimal, which I don't know how to express precisely.(5 votes)
- if you want to express the rectangular coordinates exactly, you'll have to write in terms of sin and cos unless you have a special angle.(2 votes)

- Is there a video on rectangular to polar form and/or vice versa without it being on the complex plane? For convert point (4, -3) to polar coordinates, or convert 5 angle 170 to rectangular form?(3 votes)
- you would essentially do the same thing without the i being the multiplier(what you are multiplying by) of r sin Θ

alt code for theta: alt 233(5 votes)

- Hello

How do I convert the results into exact values?

It´s not clear in the exercises, do I use the trigonometric table?

e.g. How do I convert 6*cos(135) to −3√2?

PS: I just copied and pasted this but we have a similar question tho and also I want to ask about how to calculate this expression manually (step by step pls)

-√(2)/2*6 = -3√(2)

lastly, what do you mean by "^" when eg. 2^2*5^3=?(4 votes)- You would use a calculator to do the conversion. Or, it is quite common for teachers to give you a copy of the unit circle and have you memorize the cosine and sine values of common angles. 135 degrees is one of those common angles. You can find diagrams of the unit circle if you do a websearch and use that as a reference.

The carat symbol ^ is used to denote an exponent since exponents are not easily typed.

2^2 * 5^3 means 2-square times 5-cubed.

Hope this helps.(1 vote)

- In the Practice problems Polar and Rectangular forms of complex numbers, Express z1=3-3i in polar form, how do you get the answer arctan of (-3/3) = pi over 4? Is there a calculator that will display the answer as this? My calculator displays arctan (-3/3) as -0.785(3 votes)
- If I remember correctly, I think Casio calculators tend to give the answers to inverse trig calculations as fractions of pi rather than as decimals.

You could also divide the answer you got (−0.785...) by pi.

That should give you −0.25, which converts to −1∕4,

and thus the angle is −1∕4⋅𝜋, or −𝜋∕4

Or calculate the angle in degrees, and then convert that to radians:

arctan(−3∕3) = −45° = −45∕180⋅𝜋 = −𝜋∕4(2 votes)

- Is there a formula for finding theta without drawing the graph?(2 votes)
- its arctan(opp/adj)(2 votes)

## Video transcript

Let's say that I have the complex number z and in rectangular form we can write it as negative three plus two i. So first let's think about where this is on the complex plane. So, this is our imaginary axis
and that is our real axis. And let's see, the real
part is negative three, so we could go one, two, three
to the left of the origin. Let me space that out a
little bit more evenly. So one, two, three to
the left of the origin. So negative three. And then we have two i's. We're going to go up two. So up two in the imaginary direction. So one, two just like that. So z is real part negative three, imaginary part two. z would be right over
here in the complex plane. So that is z right over there. Now what I want to think
about are other ways to essentially specify the location of z. And in particular, instead of giving the
real and imaginary parts, essentially the coordinates here, let's think about giving a direction and a distance to get to z. So for example we could give the distance from the origin to z, so let's call this distance r, but that distance by itself
isn't enough to say where z is. You have to say in what
direction do you have to go a distance of r to get to z. and so to specify the direction, we will have this angle,
theta, in radians, this angle between the positive real axis and this line right over here, this line or the segment that
connects the origin and z. So if someone gave you this
angle and this distance, then you could get to z. Now what I want you to do right now is pause this video and see
if you can find a relationship between r theta and
negative three and two. In fact, given this complex
number in rectangular form, can you figure out what r and theta are? Well let's think through
this a little bit, and to help us let's remind ourselves of the unit circle
definition of trig functions because we are going to
use some trig functions to relate r, theta, and
two, and negative three. So I'm going to construct
a unit circle here. So construct a unit circle. So this right here's a unit circle, a circle of radius one. So construct a unit circle. That's a unit circle. So by definition what are the horizontal and vertical coordinates of
this point right over here where this line intersects
the unit circle? Well, this is forming an angle of theta with a positive real axis and so the horizontal coordinate over here by definition is going
to be cosine of theta. Cosine of theta. That's the unit circle
definition of cosine of theta, and the vertical coordinate
is going to be sine of theta. Sine of theta. And so what would the horizontal and vertical coordinates of this point be? We obviously know they're
negative three and two, but what would they be in terms of cosine theta and sine theta? Well look, this point right over here is a radius of one away from the origin. So this distance right over here is one, but now we are r away from the origin. We're r times as far. So if we're r times as
far in that direction, then we're going to be r times as far in the vertical direction and r times as far in the horizontal direction. We're going to scale everything by r. So the horizontal coordinate
of this point right here instead of being cosine of theta is going to be r times cosine of theta. So this point right over here, which we know is negative three, is going to be equal to r cosine of theta, and by the same logic,
this point over here, the vertical coordinate, we're going to scale up sine
theta by r, we're r times as far. So this point right over here is going to be r sine theta and we already know that that's equal to two. r sine theta. So given that, can we now
figure out what r and theta are? So let's first think about
figuring out what theta is. So to do that, let's think about
some of our trig functions. So one trig function that involves sine theta and cosine
theta is tangent theta. So for example we could say tangent theta, tangent of our angle, tangent of theta, is equal to sine of theta
over cosine of theta. We could also multiply the numerator and denominator here by r. That won't change the value. So that's the same thing as r
sine theta over r cosine theta and we know r sine theta
is going to be equal to two and we know that r cosine
theta is negative three. So this whole thing is
going to be negative 2/3. Another way of thinking
about it is the tangent of theta is going to be the same thing as the slope of this line right over here. And what is the slope of that line? Well if you start at z and
you want to go to the origin you're going to go positive
three in the x direction and then you're going to go negative two, or I should say positive three
in the horizontal direction, and then you go negative two
in the vertical direction. So the slope is your change in vertical over change in horizontal. It's negative two over three. But now we can use this
to solve for theta. To solve for theta, we just
take the inverse tangent of both sides and we get theta is equal to inverse tangent of negative 2/3, of this thing right over here. So we copy and paste that and we can get our calculator out to figure
out what this actually is. So let's turn it on. Let me make sure that I am in radian mode. I am. and so I can take the inverse tangent of negative two divided by three, which gets us negative point
five eight eight zero zero, on and on and on. So if we round to the nearest
hundredth of a radian, it would be negative point five nine. So this is approximately
negative zero point five nine. Now is this the right angle? Is this the theta that we are looking for? Well this theta, negative
zero point five nine, that's going to get us over here. That's this angle right over here. That's what the inverse tangent gave us, and it makes sense because this ray is a continuation of this
ray right over here. Together they would form a line. It has the same slope. But that's not the theta
that we are looking for. The theta that we are looking for is going in the opposite direction. It's half way around the circle. So if we think in terms of radians, it's going to be this
angle plus pi radians. So the theta that we're looking for isn't going to be what our
calculator gives us for this. It's going to be this value plus pi. So theta, the theta that we care about, is going to be negative zero
point five nine, roughly, plus pi. I'm going to say approximately just because I have rounded right over here. So let's get the calculator out. So let's take our previous response, and that's just the previous answer, plus pi because we're going to
go in the opposite direction. So that gives us roughly
two point five five radians. So this is approximately
two point five five radians is our claim for what theta is. Now does that make sense, that this angle is two
point five five radians? Well, this angle if we go straight up, that's pi over two radians, and pi is three point one four, so that's going to be
one point five seven, something like that, and this is pi radians, so that's three point
one four one five nine, keep going on and on and on. So two point five nine is
indeed in the right quadrant. So that is right. This is going to be an angle
of two point five five radians. Now we just have to figure
out the length, what r is. And that we can just use
the Pythagorean theorem for. We can set up a right triangle. We know that this distance
right over here is two because this distance
right over here is two, and we know that this distance is, the coordinate here is negative three, but the distance here is just three. So we know from the Pythagorean theorem that r squared is equal to two squared plus three squared or that r is equal to the square root of
four plus nine, which is 13. And so there we have it. We have negative three, so we know r is equal
to the square root of 13 and theta is two point five five radians. So using that information, we can now rewrite z in
terms of r and and our theta. So now we can say that z is equal to, instead of negative 3, we can
write it as r cosine theta, so we can write it as the square root of thirteen times the cosine of theta, which is, we're saying theta
is roughly two point five five if we round to the nearest
hundredth, plus two, we already know is r sine of theta is the square root of thirteen, and then sine of theta,
two point five five, and then all of this is going to be multiplied times i, and if we like to
simplify it a little bit, or kind of really make
clear what the r is here, we could factor it out. So we could say that z is
equal to the square root of 13 times cosine of two point five five, and once again two point five
five is an approximation, so maybe I should say
approximately equal to, cosine of two point five five plus i times sine of two point five five. And so when I rewrote z in
this format right over here, it makes it much clearer what the direction I have to go in is, the direction is two
point five five radians counterclockwise from
the positive real axis. It also says how far I need to go, I need to go square root of 13. This essentially makes the polar, it makes it clearer how we
get there in kind of a more, I guess you could say, polar mindset, and that's why this form
of the complex number, writing it this way is
called rectangular form, while writing it this
way is called polar form.