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### Course: Pre-algebra > Unit 11

Lesson 7: Arithmetic with numbers in scientific notation- Multiplying & dividing in scientific notation
- Multiplying three numbers in scientific notation
- Multiplying & dividing in scientific notation
- Subtracting in scientific notation
- Adding & subtracting in scientific notation
- Simplifying in scientific notation challenge

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# Multiplying three numbers in scientific notation

Multiplying really big or really small numbers is much easier when using scientific notation. When we multiply numbers in scientific notation, we can commute and associate the factors. That lets us multiply the decimal factors first. Then we can use exponent properties to multiply the powers of 10. Created by Sal Khan and Monterey Institute for Technology and Education.

## Want to join the conversation?

- Why do we need scientific notation in chemistry?(37 votes)
- As an example, think of Avogadro's number. It's a huge number, and it would be tedious to write it out in calculations and etc. Sal actually discusses it in his 'Intro to Scientific Notation' video, I believe.

I hope this helped!(47 votes)

- My eighth grade teacher is making us doing this...how do i get rid of the exponent? Or can i not do that?(7 votes)
- You can get rid of the exponent by converting the number and turning it into a decimal.

You do this by taking the exponent and listing that number of zeros behind the first part of the number

So the number 3 x 10^4 would be 30000

If the first part of the number has multiple digits then you subtract however many digits there are from the zeroes.

So 3.12 x 10^4 would be 31200(17 votes)

- why do we need to use scientific notation at all?(6 votes)
**Scientific notation**is really useful when you are dealing with really*big*numbers (like the distance between stars and planets in astronomy) and really*small*numbers (like the mass of atoms and molecules in chemistry).

Using scientific notation allows you to do calculations without having to deal with all the pesky zeros.

Hope this helps!(15 votes)

- In the earlier videos, Sal went through each step of multiplying by decimals. The video "Scientific Notation Example 2" shows how to do that, and then how to adjust the result to be real scientific notation. By the time you get to this video, he figures that you have learned those basics.(12 votes)
- When do you know if you have to use scientific notation or just rounding"

e.g IN 119.5

Is it the same 1.19x10(2) as 120?(6 votes)- You use scientific notation a lot in chemistry or physics along with significant figures (a type of rounding, sort of). Usually, in math, you only round as told.

Scientific notation is helpful when you need to use significant figures because it makes it easy to tell how many there are. For instance, 6.00x10^3 has 3, but 6000 has 1. If you haven't learned about significant figures, it's a way to measure how precise your answer can be given how precise the given numbers are. It's assumed that 6000 is rounded to the nearest thousand, but the 0s in 6.00 mean it's accurate to that position, so 6.00x10^3 is rounded to the nearest 10.

In general, in math or science, if the number is so big (or small) that you find yourself getting confused by all the 0s, you should use scientific notation. In science, use significant figures for rounding (unless your class doesn't use them, in which case you probably just round to two or three decimal places). In math, only round if they tell you to, otherwise try to use exact answers whenever possible. And never, ever round until the end of the problem, no matter what.(12 votes)

- Is ((7^3*2)+(4)^3-(1489*10^500)*(2652+16/2)/(23164+156))^2 relavent?(4 votes)
- Ok, so after like 30 minutes,(because I'm obsessed with math & solving weird problems XP) I found the approximate answer. BTW I'm showing my steps.

((7^3*2)+4^3-(1489*10^500)*(2652+16/2)/23164+156))^2

((686)+(64)-(1489*10^500)*2660)/23320))^2

(750-(1489*10^500)*0.1140651)^2

562500-(1489*10^500)*0.013108

562500-(1.489e+503)*0.013108

-1.489e+503*0.013108*EQUALS*

-19517812e+501

Finally, I realize now that the expression was over complicated and got easy*really*quickly.

*Thanks for the challenge!!*(8 votes)

- the fun of reading ?'s from 10 years ago instead of doing your math work🤣(7 votes)
- my brain is going to die because of math 😭(7 votes)
- Wouldn't it be 10 to the power -10 on the first problem bc if you move to the left its dividing (negative exponent) but at4:07he added 10 to the first power to 10 to the -9th power(3 votes)
- The 10^(-9) comes from multiplying:

10^8 * 10^(-12) * 10^(-5)

When we multiply a common base, we add the exponents.

8+(-12)+(-5) = -4+(-5) = -9

So, the new result is 10^(-9).

After multiplying the constants, he has:

40.1534 x 10^(-9)

Since the constant term is too large to be in proper scientific notation, it needs to be fixed. The number 40 is larger than 10. The decimal point needs to be moved 1 unit to the left, which creates:

4.01534 x 10^1 x 10^(-9)

It needs to be 10^1 because you would need to multiply 4.01534 by 10 to get back to 40.1534.

Then, again Sal adds the exponents on the 10s to get:

4.01534 x 10^(-8)

Hope this helps.(6 votes)

- I am lost in the brain(6 votes)
- Find your schema(1 vote)

## Video transcript

We're asked to
multiply 1.45 times 10 to the eighth times 9.2 times
10 to the negative 12th times 3.01 times 10 to
the negative fifth and express the product in
both decimal and scientific notation. So this is 1.45 times 10
to the eighth power times-- and I could just write the
parentheses again like this, but I'm just going to write
it as another multiplication-- times 9.2 times 10
to the negative 12th and then times 3.01 times
10 to the negative fifth. All this meant, when I wrote
these parentheses times next to each other, I'm
just going to multiply this expression
times this expression times this expression. And since everything is
involved multiplication, it actually doesn't matter
what order I multiply in. And so with that in mind,
I can swap the order here. This is going to be the
same thing as 1.45-- that's that right there-- times
9.2 times 3.01 times 10 to the eighth--
let me do that in that purple color-- times
10 to the eighth times 10 to the negative 12th power times
10 to the negative fifth power. And this is useful
because now I have all of my powers of
10 right over here. I could put parentheses
around that. And I have all my non-powers
of 10 right over there. And so I can simplify it. If I have the same base
10 right over here, so I can add the exponents. This is going to be 10 to
the 8 minus 12 minus 5 power. And then all of this
on the left-hand side-- let me get a calculator
out-- I have 1.45. You could do it by hand, but
this is a little bit faster and less likely to make a
careless mistake-- times 9.2 times 3.01, which
is equal to 40.1534. So this is equal to 40.1534. And of course, this is going
to be multiplied times 10 to this thing. And so if we simplify
this exponent, you get 40.1534 times
10 to the 8 minus 12 is negative 4, minus
5 is negative 9. 10 to the negative 9 power. Now you might be tempted
to say that this is already in scientific notation because
I have some number here times some power of 10. But this is not quite
official scientific notation. And that's because
in order for it to be in scientific notation,
this number right over here has to be greater than or
equal to 1 and less than 10. And this is, obviously,
not less than 10. Essentially, for it to be
in scientific notation, you want a non-zero
digit right over here. And then you want
your decimal and then the rest of everything else. So here-- and you want
a non-zero single digit over here. Here we obviously
have two digits. This is larger than 10-- or this
is greater than or equal to 10. You want this thing
to be less than 10 and greater than or equal to 1. So the best way to do that
is to write this thing right over here in
scientific notation. This is the same thing
as 4.01534 times 10. And one way to think about
it is to go from 40 to 4, we have to move this
decimal over to the left. Moving a decimal over to
the left to go from 40 to 4 you're dividing by 10. So you have to multiply by
10 so it all equals out. Divide by 10 and
then multiply by 10. Or another way to write it, or
another way to think about it, is 4.0 and all this stuff times
10 is going to be 40.1534. And so you're going to have
4-- all of this times 10 to the first power, that's
the same thing as 10-- times this thing-- times 10 to
the negative ninth power. And then once
again, powers of 10, so it's 10 to the first
times 10 to the negative 9 is going to be 10 to the
negative eighth power. And we still have this 4.01534
times 10 to the negative 8. And now we have written
it in scientific notation. Now, they wanted
us to express it in both decimal and
scientific notation. And when they're asking us to
write it in decimal notation, they essentially want us to
multiply this out, expand this out. And so the way to think about
it-- write these digits out. So I have 4, 0, 1, 5, 3, 4. And if I'm just
looking at this number, I start with the
decimal right over here. Now, every time I divide by
10, or if I multiply by 10 to the negative 1, I'm moving
this over to the left one spot. So 10 to the negative
1-- if I multiply by 10 to the negative 1, that's the
same thing as dividing by 10. And so I'm moving the
decimal over to the left one. Here I'm multiplying by
10 to the negative 8. Or you could say I'm dividing
by 10 to the eighth power. So I'm going to want to move
the decimal to the left eight times. And one way to
remember it-- look, this is a very, very,
very, very small number. If I multiply this, I
should get a smaller number. So I should be moving
the decimal to the left. If this was a
positive 8, then this would be a very large number. And so if I multiply
by a large power of 10, I'm going to be moving
the decimal to the right. So this whole thing
should evaluate to being smaller than 4.01534. So I move the decimal
eight times to the left. I move it one time to the left
to get it right over here. And then the next seven times,
I'm just going to add 0's. So one, two, three, four,
five, six, seven 0's. And I'll put a 0 in front of
the decimal just to clarify it. So now I notice, if you include
this digit right over here, I have a total of eight digits. I have seven 0's, and
this digit gives us eight. So again, one, two, three,
four, five, six, seven, eight. The best way to
think about it is, I started with the
decimal right here. I moved once, twice, three,
four, five, six, seven, eight times. That's what multiplying times
10 to the negative 8 did for us. And I get this number
right over here. And when you see a
number like this, you start to appreciate
why we rewrite things in scientific notation. This is much easier to-- it
takes less space to write and you immediately know
roughly how big this number is. This is much harder to write. You might even
forget a 0 when you write it or you might add a 0. And now the person has to sit
and count the 0's to figure out essentially how large--or get
a rough sense of how large this thing is. It's one, two, three, four,
five, six, seven 0's, and you have this digit right here. That's what gets
us to that eight. But this is a much, much more
complicated-looking number than the one in
scientific notation.