Intuition of why the derivative of sin(x) is cos(x) and the derivative of cos(x) is -sin(x).
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- Regarding the unit circle, when sin is 0 cos is 1 or -1. But sin's slope will be 0/ infinity or 0/ - infinity. Both undefined and not cos. Not sure what im doing wrong here.(3 votes)
- Remember, a derivative involves instantaneous slope, but that doesn't mean that you're dividing by zero - if so, then we couldn't take the derivative of any function! You should try reviewing the videos on derivatives to get a feel for the intuition of what instantaneous slope really means.(12 votes)
- At which points are the tangents of cos x and sin x parallel ? What makes them important ?(4 votes)
- Their tangent lines are parallel when their derivatives are equal, that is, -sin(x) = cos(x), which occurs at 3pi / 4 and 7pi / 4.
Important? I'm honestly not sure what the application might be, except for that it's useful in general for trigonometry.(3 votes)
- [Instructor] What I'd like to do in this video is get an intuitive sense for what the derivative with respect to x of sine of x is and what the derivative with respect to x of cosine of x is. And I've graphed y is equal to cosine of x in blue and y is equal to sine of x in red. We're not going to prove what the derivatives are, but we're gonna know what they are, get an intuitive sense and in future videos we'll actually do a proof. So let's start with sine of x. So the derivative can be viewed as the slope of the tangent line. So for example at this point right over here, it looks like the slope of our tangent line should be zero. So our derivative function should be zero at that x value. Similarly, over here, it looks like the derivative is zero. Slope of the tangent line would be zero. So whatever our derivative function is at that x value, it should be equal to zero. If we look right over here on sine of x, it looks like the slope of the tangent line would be pretty close to one. If that is the case, then in our derivative function when x is equal to zero that derivative function should be equal to one. Similarly, over here, it looks like the slope of the tangent line is negative one, which tells us that the derivative function should be hitting the value of negative one at that x value. So you're probably seeing something interesting emerge. Everywhere, while we're trying to plot the slope of the tangent line, it seems to coincide with y is equal to cosine of x. And it is indeed the case that the derivative of sine of x is equal to cosine of x. And you can see that it makes sense, not just at the points we tried, but even in the trends. If you look at sine of x here, the slope is one, but then it becomes less and less and less positive all the way until it becomes zero. Cosine of x, the value of the function is one and it becomes less and less positive all the way until it equals zero. And you could keep doing that type of analysis to feel good about it. In another video we're going to prove this more rigorously. So now let's think about cosine of x. So cosine of x, right over here, the slope of the tangent line looks like it is zero. And so it's derivative function needs to be zero at that point. So, hey, maybe it's sine of x. Let's keep trying this. So over here, cosine of x, it looks like the slope of the tangent line is negative one and so we would want the derivative to go through that point right over there. All right this is starting to seem, it doesn't seem like the derivative of cosine of x could be sine of x. In fact, this is the opposite of what sine of x is doing. Sine of x is at one, not negative one at that point. But that's an interesting theory, maybe the derivative of cosine of x is negative sine of x. So let's plot that. So this does seem to coincide. The derivative of cosine of x here looks like negative one, the slope of a tangent line and negative sign of this x value is negative one. Over here the derivative of cosine of x looks like it is zero and negative sine of x is indeed zero. So it actually turns out that it is the case, that the derivative of cosine of x is negative sine of x. So these are really good to know. These are kind of fundamental trigonometric derivatives to know. We'll be able to derive other things for them. And hopefully this video gives you a good intuitive sense of why this is true. And in future videos, we will prove it rigorously.