If cross products measure how much the vectors are far apart, shouldn't it continue to increase after 90 degrees all the way to 180 degrees since the latter is when both vectors point in completely opposite directions?

The cross product of two vectors a and b gives a third vector c that is perpendicular to both a and b. The magnitude of the cross product is equal to the area of the parallelogram formed by a and b. The base of this parallelogram has length |a|, and the height has length |b| sin (theta). That means the area of the parallelogram in total is precisely the magnitude of the cross product1. So, if you imagine vector a and b being the walls of a parallelogram, then as the angle 90 approaches (as the height of the parallelogram will increase), the area of the parallelogram will keep on increasing. And you can imagine as the vector goes in the other direction, over ninety, the height of the parallelogram will begin to decrease again. Since the magnitude of the cross product is dependent on the area of the parallelogram, as the parallelogram’s area will decrease, so will the magnitude of the cross vector1.

at the problem 1, are we sure the 2nd value of the answer is -8? because it seems wrong, (I did a1*b3-(a3*b1) to find it)

The 2nd value should be (a3*b1)-(a1*b3); you subtracted in the wrong order. A useful way to think of the cross product <a1, a2, a3> x <b1, b2, b3> is the determinant of the 3 by 3 matrix i j k a1 a2 a3 b1 b2 b3 Note that the coefficient on j is -1 times the determinant of the 2 by 2 matrix a1 a3 b1 b3 So the 2nd value is -[(a1*b3)-(a3*b1)] = (a3*b1)-(a1*b3). Note: a good way to check your answer for a cross product of two vectors is to verify that the dot product of each original vector and your answer is zero. This is because the cross product of two vectors must be perpendicular to each of the original vectors. If both dot products are zero, this does not guarantee your answer is correct but makes your answer likely correct. If at least one dot product is nonzero, then something is definitely wrong with your answer or with the way you calculated the dot products when you checked your answer. Have a blessed, wonderful day!

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Multivariable calculus

Course: Multivariable calculus > Unit 1

Lesson 2: Vectors and matrices

Cross products

Google Classroom

Learn about what the cross product means geometrically, along with the right-hand rule and how to compute a cross product.

Like the dot product, the cross product is an operation between two vectors. Before getting to a formula for the cross product, let's talk about some of its properties.

Properties of the cross product

We write the cross product between two vectors as a, with, vector, on top, times, b, with, vector, on top (pronounced "a cross b"). Unlike the dot product, which returns a number, the result of a cross product is another vector. Let's say that a, with, vector, on top, times, b, with, vector, on top, equals, c, with, vector, on top. This new vector c, with, vector, on top has a two special properties.

First, it is perpendicular to both a, with, vector, on top and b, with, vector, on top. Phrasing this in terms of the dot product, we could say that c, with, vector, on top, dot, a, with, vector, on top, equals, c, with, vector, on top, dot, b, with, vector, on top, equals, 0. This property alone makes the cross product quite useful. This is also why the cross product only works in three dimensions. In 2D, there isn't always a vector perpendicular to any pair of other vectors. In four and more dimensions, there are infinitely many vectors perpendicular to a given pair of other vectors.

Second, the length of c, with, vector, on top is a measure of how far apart a, with, vector, on top and b, with, vector, on top are pointing, augmented by their magnitudes.

It's similar to the dot product, but instead of cosine, left parenthesis, theta, right parenthesis the cross product uses sine, left parenthesis, theta, right parenthesis, where theta is the angle between a, with, vector, on top and b, with, vector, on top. That way, when the angle is 90 degrees, the cross product is at its largest. In this sense, the dot product and the cross product complement each other.

There's one interpretation of the length of c, with, vector, on top that is particularly useful. Think of the parallelogram formed by a, with, vector, on top and b, with, vector, on top. The base of this parallelogram has length \|, a, with, vector, on top, \|, and the height has length \|, b, with, vector, on top, \|, sine, left parenthesis, theta, right parenthesis. That means the area of the parallelogram in total is precisely the magnitude of the cross product.

The right-hand rule

Notice that in the image above the cross product is perpendicular to a, with, vector, on top and b, with, vector, on top, as expected. But there are actually two vectors that could be perpendicular to a, with, vector, on top and b, with, vector, on top. If c, with, vector, on top, equals, a, with, vector, on top, times, b, with, vector, on top, then these two choices are c, with, vector, on top and minus, c, with, vector, on top. How do we decide which of the two perfectly valid choices is the cross product?

We have a convention called the right-hand rule to resolve this ambiguity. If you hold up your right hand, point your index finger in the direction of a, with, vector, on top, and point your middle finger in the direction of b, with, vector, on top, then your thumb will point in the direction of a, with, vector, on top, times, b, with, vector, on top.

It's arbitrary that we define the cross product with the right-hand rule instead of a left-hand rule, but by using this convention the cross product no longer has any ambiguity.

The not so pretty formula

The most important takeaway from the cross product should be its properties, not its formula. But sometimes we do need to compute a cross product. Unfortunately, the formula for the cross product is not as nice as it was for the dot product. When we get to the article on determinants, we'll see a nicer way to remember the formula for the cross product. For now:

\begin{aligned} \vec{a} &= (a_1, a_2, a_3) \\ \\ \vec{b} &= (b_1, b_2, b_3) \\ \\ \vec{a} \times \vec{b} &= \begin{bmatrix} a_2b_3 - a_3b_2 \\ \\ a_3b_1 - a_1b_3 \\ \\ a_1b_2 - a_2b_1 \end{bmatrix} \end{aligned}

Let's try an example using the formula.

Problem 1

left parenthesis, 3, comma, 0, comma, 2, right parenthesis, times, left parenthesis, minus, 1, comma, 4, comma, 2, right parenthesis, equals
left parenthesis
Your answer should be
an integer, like 6
a simplified proper fraction, like 3, slash, 5
a simplified improper fraction, like 7, slash, 4
a mixed number, like 1, space, 3, slash, 4
an exact decimal, like 0, point, 75
a multiple of pi, like 12, space, start text, p, i, end text or 2, slash, 3, space, start text, p, i, end text
comma
Your answer should be
an integer, like 6
a simplified proper fraction, like 3, slash, 5
a simplified improper fraction, like 7, slash, 4
a mixed number, like 1, space, 3, slash, 4
an exact decimal, like 0, point, 75
a multiple of pi, like 12, space, start text, p, i, end text or 2, slash, 3, space, start text, p, i, end text
comma
Your answer should be
an integer, like 6
a simplified proper fraction, like 3, slash, 5
a simplified improper fraction, like 7, slash, 4
a mixed number, like 1, space, 3, slash, 4
an exact decimal, like 0, point, 75
a multiple of pi, like 12, space, start text, p, i, end text or 2, slash, 3, space, start text, p, i, end text
right parenthesis

Now let's see one of those properties we discussed in action.

Problem 2

One of the vectors we took the cross product of was a, with, vector, on top, equals, left parenthesis, 3, comma, 0, comma, 2, right parenthesis. Let c, with, vector, on top be the result of the cross product from above.

What is a, with, vector, on top, dot, c, with, vector, on top?

Cross product vs. dot product

When we compare the dot product and the cross product, there are three main differences.

The dot product returns a number, but the cross product returns a vector.
The dot product works in any number of dimensions, but the cross product only works in 3D.
The dot product measures how much two vectors point in the same direction, but the cross product measures how much two vectors point in different directions.

This is all we need to know about cross products for now. If you want to learn more, check out this video.

What's next

Now that we have a solid foundation in vectors and the ways we can combine them, the last topic we'll cover is matrices. The next three articles will describe what matrices are, how to visualize them, and a useful property they have called the determinant.

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shelbypup252
Posted 6 months ago. Direct link to shelbypup252's post “Example of cross product ...”
Example of cross product usage in physics:

A good example is that torque is the cross product of the force vector and the displacement vector from the point at which the axis is (the center of rotation) and the point and which force is applied.

Hope this helps!
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(9 votes)
Answer
Kaan Dalkıran
Posted 2 years ago. Direct link to Kaan Dalkıran's post “at the problem 1, are we ...”
at the problem 1, are we sure the 2nd value of the answer is -8? because it seems wrong, (I did a1*b3-(a3*b1) to find it)
Button navigates to signup pageComment on Kaan Dalkıran's post “at the problem 1, are we ...”
(3 votes)
Answer
- Ian Pulizzotto
  Posted 2 years ago. Direct link to Ian Pulizzotto's post “The 2nd value should be (...”
  The 2nd value should be (a3*b1)-(a1*b3); you subtracted in the wrong order.
  
  A useful way to think of the cross product <a1, a2, a3> x <b1, b2, b3> is the determinant of the 3 by 3 matrix
  
  i j k
  a1 a2 a3
  b1 b2 b3
  
  Note that the coefficient on j is -1 times the determinant of the 2 by 2 matrix
  a1 a3
  b1 b3
  
  So the 2nd value is -[(a1*b3)-(a3*b1)] = (a3*b1)-(a1*b3).
  
  Note: a good way to check your answer for a cross product of two vectors is to verify that the dot product of each original vector and your answer is zero. This is because the cross product of two vectors must be perpendicular to each of the original vectors. If both dot products are zero, this does not guarantee your answer is correct but makes your answer likely correct. If at least one dot product is nonzero, then something is definitely wrong with your answer or with the way you calculated the dot products when you checked your answer.
  
  Have a blessed, wonderful day!
  Button navigates to signup page
  (13 votes)
Arjun Roy
Posted 3 months ago. Direct link to Arjun Roy's post “If cross products measure...”
If cross products measure how much the vectors are far apart, shouldn't it continue to increase after 90 degrees all the way to 180 degrees since the latter is when both vectors point in completely opposite directions?
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(4 votes)
Answer
- hashaam1217
  Posted 3 months ago. Direct link to hashaam1217's post “The cross product of two ...”
  The cross product of two vectors a and b gives a third vector c that is perpendicular to both a and b. The magnitude of the cross product is equal to the area of the parallelogram formed by a and b. The base of this parallelogram has length |a|, and the height has length |b| sin (theta). That means the area of the parallelogram in total is precisely the magnitude of the cross product1.
  
  So, if you imagine vector a and b being the walls of a parallelogram, then as the angle 90 approaches (as the height of the parallelogram will increase), the area of the parallelogram will keep on increasing. And you can imagine as the vector goes in the other direction, over ninety, the height of the parallelogram will begin to decrease again. Since the magnitude of the cross product is dependent on the area of the parallelogram, as the parallelogram’s area will decrease, so will the magnitude of the cross vector1.
  Button navigates to signup page
  (4 votes)