Integrated math 3
- Reducing rational expressions to lowest terms
- Intro to rational expressions
- Reducing rational expressions to lowest terms
- Simplifying rational expressions: common monomial factors
- Reduce rational expressions to lowest terms: Error analysis
- Simplifying rational expressions: common binomial factors
- Simplifying rational expressions: opposite common binomial factors
- Simplifying rational expressions (advanced)
- Reduce rational expressions to lowest terms
- Simplifying rational expressions: grouping
- Simplifying rational expressions: higher degree terms
- Simplifying rational expressions: two variables
- Simplify rational expressions (advanced)
Given a rectangle with length a²+6a+27 and width a²-9, Sal writes the ratio of the width to the length as a simplified rational expression. Created by Sal Khan.
Want to join the conversation?
- Is (x+3)/(x+9) our final answer?(19 votes)
- You're missing something important. When a = 3 (before you simplify), a is undefined. So the entire answer is "(a+3)/(a+9) when x does not equal 3"(6 votes)
- for the final answer at the end of the video a+3/a+9 couldn't you divide 3 and 9 so the final answer is a+1/a+3?(15 votes)
- No, it's a bit more complicated. Think about it this way:
You want to simplify the fraction. One way to do this would be dividing by 3. So you have:
( ( a + 3 ) / ( a + 9 ) ) / 3
You could then distribute the 3 over the numerator ( a + 3 ) and denominator ( a + 9 ):
( ( a + 3 ) / 3 ) / ( ( a + 9 ) / 3 )
Now you have to distribute the 3 across each of the terms ( a + 3 ) and (a + 9 ):
( ( a / 3 ) + ( 3 / 3 ) ) / ( ( a / 3 ) + ( 9 / 3 ) )
Simplifying, you get:
( ( a / 3 ) + 1 ) / ( ( a / 3 ) + 3 )
Of course, this isn't a very simple way to express ( a + 3 ) / ( a + 9 ).(19 votes)
- When is 3/X+4 undefined?(6 votes)
- The way you wrote it it would be when X=0; (3/x)+4
If written 3/(x+4) the fraction will be undefined when x=-4.(32 votes)
- I'm still kind of confused on the values that the variable cannot be equal to. For example a can't be 3 or -9. Could anybody answer that area for me? Thanks a lot!(4 votes)
If x=-9 then the denominator would be 0
and if x=3 then the denominator would also be 0
And if the denominator is 0 the answer is undefined.
So the domain cannot include -9 or 3.
After factoring and reducing the expression by making the (a-3)/(a-3) = 1
this left only (a+9) in the denominator.
But because the original equation did not allow a to be -9 or 3, the factored and reduced equation also cannot be equal to -9 or 3.
I hope that helps.(7 votes)
- Near the end It first was a not equal to -9 or 3. Then when only (a+3) / (a+9) was left, he wrote: a is not equal to -9 or 3. But if you fill in a=3. That would make a (3+3= )6 and not 0. Or am I missing something? I thought the answer at the final should be a -3 or -9.(2 votes)
- When you look at the domain of a simplified function, you always look at the original function. In this case, he had (x + 9)(x - 3) in the denominator before he simplified. Therefore, a cannot be -9 or 3.(5 votes)
- In the final expression a+3/a+9, i see that if a= 3 then that would result in a defined answer which is 6/12. That can be simplified to 3/4, too. So why "a" cannot be equal to 3 at the end of the video?(3 votes)
- It's because the original expression cannot have a = 3. In order to keep the original expression and the final expression the same, the restrictions in the original expression must be carried on to the final expression, or you don't really have the same expression.(2 votes)
- what if after i factor everything out, but nothing is able to be cancled out, would that mean that it is already in simplest form?(2 votes)
- If the width is over the length, does that always have to be the case? Can't you flip them, or is that illegal math?(2 votes)
A ratio of two things can be writtern either way. It is perfectly acceptable (and often necessary to flip them. The only reason it would be restricted is because the problem required an answer in a specific manner.
For instance, if you have a ratio of 12 miles to 1 hour, It could be written as
12miles/1 hour or
1 hour/12 miles.
And depending on the problem you would need to figure out which way to use the ratio.
For instance if you had a problem where you were give that a person traveled by bike at a ratio of 12 miles to 1 hour and he had traveled for 2 hours. You are asked how far he had traveled. You would use the equation.
2 hour * 12 miles/1hour = 24 miles
Notice the words (hours* miles/hours) results in hours in both the numerator and denominator whcih canel out giving you an answer in miles.
But is you were given a problem that the person needed to travel 36 miles and you were asked how long it would take, you would use the equation
36 miles * 1 hour/12 miles = 3 hours
And notice this time the words (miles*hour/miles) results in miles in both the numerator and denominator which cancel out giving you an answer in hours.
In one equation we used the ratio one way and in the other we flipped it over.
The trick to using ratios is to realize they work either way and you need to construct an equation so that the words cancel out the correct way to give you the correct words in your answer.(4 votes)
- How come we can't continue simplifying a+3/a+9? Couldn't we have crossed out the a's so we're left with 3/9 which is 1/3?(1 vote)
- No, for example if you put in a number instead of a lets take 1 for instance = 1+3/1+9 it does not equal to 1/3. So you just leave the equation as it is unless the value of a is given(3 votes)
Given a rectangle with length a-squared plus 6a minus 27 and a width a-squared minus 9, Write the ratio of the width of the rectangle to its length as a simplified rational expression. So we want the ratio of the width to the length to the length of the rectangle, and they give us the expressions for each of these. The width—the expression for the width of the rectangle—is a-squared minus 9. So, the width —let me do it in this pink—is a-squared minus 9, and we want the ratio of that to the length; the ratio of the width of the rectangle to its length. The length is given right over there; it is a-squared plus 6a minus 27, they want us to simplify this. And so the best way to simplify this, whether we're dealing with expressions in the numerator or denominator, or just numbers, is we want to factor them and see if they have common factors and if they do we might be able to cancel them out. So if we factor this top expression over here—which was the expression for the width—this is of the form a-squared minus b-squared, where b-squared is 9. So this is going to be the same thing as a plus the square root of 9 times a minus the square root of 9. So this is a plus 3 times a minus 3 and I just recognized that from just the pattern; if you ever see something a-squared minus b-squared, it's a plus b times a minus b and you can verify that for yourself; multiply this out, you'll get a-squared minus b-squared. So, the width can be factored into a plus 3 times a minus 3. Let's see if we can do something for the denominator. So here, if we want to factor this out, we have to think of two numbers that when we add them, I get positive 6, and when I take their product, I get negative 27. Let's see, if I have positive 9 and negative 3, that would work. So, this could be factored as a plus 9 and a minus 3. 9 times a is 9a, a times negative 3 is negative 3a, when you add those two middle terms together, you'll get 6a, just like that and then, 9 times negative 3 is negative 27—of course the a times a is a squared. So I've factored the two expressions and let's see if we can simplify it. And before we simplify it, because when we simplify it we lose information, let's just remember what are allowable a's here, so we don't lose that information. Are there any a values here that will make this expression undefined? Well, any a value that makes the denominator zero will make this undefined. So a cannot be equal to negative 9 or 3, 'cause if a was negative 9 or 3, then the denominator would be zero; this expression would be undefined. So we have to remember this, this is part of the expression; we don't want to change this domain; we don't want to allow things that weren't allowable to begin with, so let's just remember this right over here. Now with that said, now that we've made this constraint, we can simplify it more; we can say, look we have an a minus 3 in the numerator and we have an a minus 3 in the denominator and we're assuming that a is not going to be equal to 3, so it's not like we're dividing zero over zero. So a will not be equal to 3, any other number; this will be an actual number, you divide the numerator and denominator by that same value, and we are left with a plus 3 over a plus 9 and the constraint here—we don't want to forget the constraints on our domain— a cannot equal negative 9 or 3. And it's important that we write this here, because over here we lost the information that a could not be equal to 3, but in order for this to really be the same thing as this thing over here, when a was equal to 3 it wasn't defined so in order for this to be the same thing, we have to constrain the domain right over there; a cannot be equal to 3. Hopefully you found that useful.