Created by Sal Khan.
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- I find it interesting that the equation:
When started by multiplying both sides by three
and then subtracting both sides by 2 will give a result of:
However, when solving it by subtracting both sides by two and then multiplying both sides by three the result will be X=15.
I will always keep this in mind when solving equations from now on.(2 votes)
- Which number is <197 and >97?(2 votes)
- Any number that is less than 197 and greater than 97. For example 100, 148, 179, etc. It can also be a fraction or decimal such as 97.0000001, 196.9999, 105.5, 105/1000, etc.(0 votes)
- How do you solve the equation (39/3)+n?(1 vote)
- You don't have an equation. So, you can't solve for "n". You have an algebraic expression. All you can do is reduce your fraction to simplify the expression.(1 vote)
- Why do you distribute the 3 to only one side?(1 vote)
- When it comes down to getting the x by itself, how do you know whether to add, subtract, multiply or divide the number next to the x?? I am a little confused.(1 vote)
- how would u solve an equation like this 5b+b=12(1 vote)
- Combine like terms. 5b+(1)b is equal to 6b. Now you have 6b=12. In order to have the variable "b" by itself, divide both sides by 6, and you should get b=2. :)(1 vote)
- how do u answer a question with 6x+7=5b how would u solve a problem like that(1 vote)
- When I took college math I was told, "To find two unknowns you need two equations." So if you have only one equation with two variables, you can only find the value of one variable in terms of the other. You can divide both sides by 6 which will give you
x + 7 / 6 = 5b / 6 and then subtract 7 / 6 from both sides giving
x = (5b -7) / 6
or divide both sides by 5 which will give you
b = (6x + 7) / 5.
b = (6x + 7) / 5.(1 vote)
Voiceover:Below are the steps that Steven used to correctly solve the equation six X is equal to three times X plus four, four X. Step one is missing. What could Steven have written for step one? So let's see, so this is the original equation, they give us a blank for step one, and then we see that he eventually gets to three X equals 12. That he divides both sides by three and he gets to X equals four. So the best way I could think about doing this is to think, what would I do? Well if I saw something like this, my extinct would be to distribute this three so that I could start separating the parts of this expression that have a variable, that have the X, and the parts that are constant. So let's try to distribute this three and see what we get. and see if that's a reasonable step for the direction that Steven went in. So if we do that, we'd get six X is equal to, we haven't changed the left-hand side, and the right-hand side three times X is three X. Then three times four is 12. So you get six X is equal to three X plus 12. Now if I don't even look at what Steven's doing right over here, if I'm trying to solve for X, what would be the next thing that I would do? Well, I'd try to isolate all of the X's on one side, and if I want all the X's on the left-hand side I would subtract three X from both sides. So if you subtract three X from both sides you would then get Steven's second step right over here. So this looks like a completely reasonable first step for Steven. The first step is he distributes the three to get this expression, then he subtracts three X from both sides to get three X is equal to 12, and then he divides both sides by three to get X is equal to four.