When base and height is same, area for triangle will be half of parallelogram.

Triangles having common base and between the same parallels are equal in the area.

Solve it to find the answer:

Just use the properties of shapes on the same base.

Area of quadrilateral \\(=\\frac{1}{2}\\times height\\times (sum of both sides)\\)

Just use the property of relationship between parallel sides of a trapezium.

When the parallelogram are on same base and with same height the area's will be same.

Recall that the quadrilateral so formed after joining the mid points of a parallelogram is also a parallelogram.Also recall its relation to that of the external parallelograms.

Recall the concept and theorems of parallelogram.

Since O is not on AB, so we can not establish a relation between them.