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CCSS.Math:

construct a line perpendicular to the given line so if I can pick two arbitrary points on this line and if I can make a line that is always equidistant from those two points then that line will be perpendicular and actually it'll be a perpendicular bisector of the segment formed by those two points now they don't care that whether we're bisecting anything but they do care about it being perpendicular so let's do this so I'm going to add I'm gonna draw a circle with my compass and so let's just pick that point right over there I could adjust the radius if I like but I might as well I'll just leave it right over there now let me draw another circle and this time I'm gonna Center it where the first circle intersects intersects with my line and then I'm gonna adjust the radius to overlap with the second with the second with the first dot I should say and now where these two circles intersect those are points that are equidistant from both of these from both of these these these centers that I just constructed so let me draw a line that connects those two and that line is going to be perpendicular to our original to our original line