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Finding arc measures with equations
Sal solves a few items where arc measures are given in equations, we have to find a variable, then use it to find an arc measure.
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At1:19, Sal says that (4k+159) is vertical to (2k+153). How can we tell if they are vertical if we are not given any diameter? Did we assume it was vertical since they are directly across from each other ("eye-balling it")?(20 votes)
It's given by the definition of a diameter. A segment that touches both sides of a circle, passing through the center. The center, also by definition, is what names the circle - in this case circle P. Hence, BD and AC are diameters. When two or more lines intersect, they form angle relationships (in this case they are vertical)(18 votes)
In the second problem, why is it okay to assume that arc BC Is the minor arc? Isn't the minor arc supposed to be explicitly stated as BAC?(16 votes)
A minor arc is always denoted by two letters while a major arc is represented by three. BC would be the name of the minor arc. If you wanted to describe the major arc, you would have to add a another point on the circle because all major arc have three pointts. All major arcs are greater than 180 degrees, semicircles are 180 degrees, and minor arcs are less than 180 degrees.(14 votes)
im confused if the minor arc in the first example only goes through 2 points on the circle why is the arc in the second exsmple go from b through a, then to c??(6 votes)- Even though I'm a couple of years late, I'll do this for other people that may need the help, because I've seen this question pop up a couple of times.
Whenever two points are mentioned, then NO MATTER what, it will always be the minor arc. If there is a point in between the minor arc but isn't mentioned, nothing changes. Sometimes questions may show that to throw you off. Whenever three points are mentioned, then I'm pretty sure it's always the major arc. Whenever a circle is split in half, and you are asked about two points, that would just be a semi/half - circle. Hope this helped!(16 votes)
At3:38Sal says we assume minor arc, but it looks like the minor arc would be identified BAC. BC would be the path with no other letters, which happens to be the long way around. *Are we always to assume the short path with a two letter arc description?*(4 votes)
Good question. I'm probably really late, so you might know this already, but BC has an angle measure of less than 180. We can assume this, but there is a long hard proof. Because the angle measure is less than 180, that makes it a minor arc. And for a minor arc, you would list the 2 endpoints, nothing in between. And yes, most of the time, we can assume the short path with a 2 letter arc description.(3 votes)
- For the second question, it should be measure of BC. However, he got the answer for the measure of BAC. It should be the opposite angle.??(5 votes)
- The measure of BC is the same as the measure of BAC.(since it's the same angle)(1 vote)
this does not prepare you for the practice questions at all(4 votes)- Aren't you able to just add all the angles together, Put it equal to 360 and solve for the variable?(2 votes)
In the first example, no, because we don't have expressions for all of the angles, just two of them.
In the second example, yes, and that's exactly what Sal did.(3 votes)
- At1:19, Sal says that (4k+159) is vertical to (2k+153). How can we tell if they are vertical if we are not given any diameter? Did we assume it was vertical since they are directly across from each other ("eye-balling it")?(3 votes)
- I can't do it can someone please explain? I get close to the answers but not correct.(2 votes)
When you say get close, is that just a matter of how to round numbers or is off more than just rounding, or is it getting the math wrong and happening to get close? These mostly go back to our Algebra I skills of solving problems.(1 vote)
At0:36, Sal says to us "but since they gave us just B and C, we can assume this is going to be the minor arc..." (He also does this again at3:36.)
If there's one thing I've learned from taking geometry in 7th grade, its that it's never safe to assume.*
So [this might sound a little weird]... unless geometry is assumptions, how do we know this is right?
[By the way, I understand how this is correct, but is the answer always an assumption or is there a *TRUE answer?](0 votes)
The assumption made is due to the question being ambiguously phrased, which has nothing to do with geometry or mathematical laws.(4 votes)
1:19
Video transcript
- So we're told Circle P is below, this is Circle P right over here. What is the arc measure
of arc BC in degrees? So this is point B, this is point C, let me pick a different
color so you can see the arc. And since they only gave us two letters, we really wanna find the minor arc, so we want to find the
shorter arc between B and C. So the major arc would
be the long way around, and if they wanted to
specify the major arc they would've had to give us three letters to force us to go the long way around, so if they said arc BAC or BDC, that would go the long way around, but since they just gave us just B and C we assume it's going to be the minor arc, so we wanna find that arc
measure right over there. Now, the arc measure is going to be the exact same measure in degrees as the measure of the
angle, the central angle, that intercepts that
arc, so it's going to be the same thing as the measure
of this central angle, which is 4k + 159 degrees. So if we can figure out what
K is, we're gonna know what this central angle measure
is, and then that's going to be the same thing as this arc measure. So how do we figure that out? Well, what might jump out
at you is that this angle, angle BPC that we care about, is vertical to angle APD. These are vertical angles,
and vertical angles are going to have the same measure, they are, they're going to be congruent. So let's set these two
measures equal to each other. So we know that 4k + 159 is going to be equal to 2k + 153, so let's get all of our K
terms on the left-hand side, and all of the non-K terms
on the right-hand side. So let's subtract 2k from both sides, so we can subtract 2k from both sides. And let's subtract, well
let me just do that first, I don't want to skip steps. And so I got rid of the
K's on the right-hand side so it's just gonna be left with the 153. And on the left-hand side, 4k - 2k is 2k, and I still have + 159. Now let's get rid of this
159 on the left-hand side so let's subtract it. But if I do it on the left-hand side I need to do it on the
right-hand side as well, so subtract 159 from both sides. And I'm left with 2k is equal to 153 - 159 is negative 6, so K is equal to, just
divide both sides by 2, K is going to be equal to negative 3. Now you might be tempted
to say oh, negative 3, but we're not just trying to solve for K, we're trying to figure
out this angle measure which is going to be the
same as the arc measure that we care about. And that's just expressed in terms of K, so it's 4 times K + 159, so
that's going to be 4 times - 3 + 159 well what's that going
to be? 4 times -3 is -12. Plus 159 is going to be 147. So this angle right over here
has a measure of 147 degrees and you can calculate, that's
the same thing as over here. 2 times -3 is -6, plus 153 is 147 degrees, these two are the same,
and so 147 degrees. This angle measures the same
as the measure of arc BC. Let's do one more of these. Circle P is below. What is the arc measure of BC in degrees? Now since once again they
only gave us two letters, we can assume it is the minor arc. So we care about BC, we care about this right over here. And so what is the measure of this arc is going to be the same
thing as the measure of the central angle
that intercepts that arc, and that measure is going to
be the sum of these two angles so it's going to be 4y + 6 + 7y - 7. 4y + 7y, we can combine the
y terms, is going to be 11y. And then 6 - 7 is going to be negative 1. So it's going to be 11y - 1,
and how do we figure that out? Or how do we figure out what Y is? We need to figure out what Y is in order to figure out what 11y - 1 is. Well, we know, let me write this down. So the angle that we care about is 11y - 1, 11y - 1. We know that that angle,
plus this big angle that I'm going to show in blue,
that if we add them together that it's going to be 360 degrees, 'cause we would've gone all
the way around the circle. So we know that 11y - 1 + 20y - 11 is going to be equal to 360 degrees. And so now we can just solve for Y. What is, let me get some
new colors involved, what is 11y + 20y? Well that's going to be
31y, and then if I have - 1 and -11 that's going to be negative, let me do this in a different
color, so that's going to be, - 1 and -11, that's -12, and that's going to be
equal to 360 degrees, 360. So let's see, we can add 12 to
both sides to get rid of that - 12 right over there, and
that's going to leave us with 31y 31y is equal to 372 and so if we divide both sides by 31, it looks like 12, yep,
it'll go exactly 12 times so Y is equal to 12, which is equal to 12. And remember, we weren't
trying to solve for Y, we were trying to solve for 11y - 1, so what is 11 times 12?
We know that Y is 12. 11 times 12 - 1, let's see. 11 times 12 is 121. And then 121 - 1 is going to be, oh sorry no, my multiplication tables are off, it's been a long day. 11 times 12 is going to be 132, 132 - 1 is going to be 131, and it's going to be in degrees. So 131 degrees, that's
the measure of this angle which is going to be the
measure of minor arc BC.