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### Course: Geometry (FL B.E.S.T.) > Unit 4

Lesson 2: Triangle congruence from transformations- Proving the SSS triangle congruence criterion using transformations
- Proving the SAS triangle congruence criterion using transformations
- Proving the ASA and AAS triangle congruence criteria using transformations
- Why SSA isn't a congruence postulate/criterion
- Justify triangle congruence

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# Proving the SAS triangle congruence criterion using transformations

We can prove the side-angle-side (SAS) triangle congruence criterion using the rigid transformation definition of congruence. Created by Sal Khan.

## Want to join the conversation?

- So high school geometry is grade 10 math right?(14 votes)
- It would be 10th grade if you don't have pre-ap or ap classes. So if you do have gate geometry you will do it in 9th grade and do Algebra 2 next year. If you don't have a gate then you do it in 10th grade and have Algebra 2 next year.(3 votes)

- BROO his hand writing is so good(8 votes)
- its normal handwriting(1 vote)

- I wish I had Sal as a teacher in 8th grade for algebra I failed algebra that year and I thought I wasn't doing good enough but when I retook algebra in 9th I got all A's on the test. Maybe I was just my 8th-grade algebra teacher I don't know(7 votes)
- So there's this little apostrophe-looking thing that keeps appearing on certain letters (around the triangles) and I'm a little confused as to what that is. If anyone can tell me what that stands for, I would really appreciate it! :)

(It's throughout the video when those symbols show up.)(0 votes)- that is the prime mark (think of transformers and optimus prime) which is an indication that a transformation has been performed on a point or shape. So the pre-image (starting point) would have points such as ABC, but after it is transformed (through translation, rotation, or reflection), the new figure would be A'B'C' which would be congruent, but not necessarily the same orientation. The video talks about A going to A', B going to B', and C going to C'.(10 votes)

- Hi, Sal

Could you tell me which compass you think is the best (most durable) as mine keeps moving (out of the circle) and breaking?(3 votes)- a compass with stiff arms and a adjustable nut(1 vote)

- Wouldn't c' be mapped to F anyway without this extra stuff?(2 votes)
- The way that Sal showed it, yes it would be. However it would not have been if a reflection was already used. Say a was translated to d then the triangle was rotated about point a however many degrees it was needed to make b on the opposite side of a' from e, then reflected on a vertical line through point a', c' would be on the opposite side of f on line a', b'. If this was the case then it would need to be reflected.(2 votes)

- Video won't play. Help?(2 votes)
- Try going on youtube.com. All of the videos are found there. Check your internet connection also.(2 votes)

- Around3:40Sal says that the angle "looks something like this" and then he draws it using a straightedge. Is there a more precise way to construct the angle for the proof using a compass and then the straightedge?

For example, can something like this be done? We know F=C' and E=B'. We can draw a line between them. So, line FE = line C'B'. Can we use line FE as a radius around point E to create a circle that will intersect with a circle around point D with line DF as a radius and then connect the points and reflect over line CE?(2 votes)- Use a protractor. You can measure the angle and draw a mark on the other side. Then, you can use a straightedge to draw the angle.(1 vote)

- How do you prove triangles congruent with attitude?(2 votes)
- What is the exact criterion/rule?(1 vote)

## Video transcript

- [Instructor] What we're
going to do in this video is see that if we have
two different triangles, and we have two sets
of corresponding sides that have the same length, for example this blue
side has the same length as this blue side here, and this orange side
has the same length side as this orange side here. And the angle that is
formed between those sides, so we have two corresponding
angles right over here, that they also have the equal measure. So we could think about
we have a side, an angle, a side, a side, an angle and a side. If those have the same
lengths or measures, then we can deduce that these two triangles must be congruent by the rigid motion
definition of congruency. Or the short hand is, if we have side, angle, side in common, and the angle is between the two sides, then the two triangles will be congruent. So to be able to prove this, in order to make this deduction, we just have to say that there's always a rigid transformation if we have a side, angle, side in common that will allow us to map
one triangle onto the other. Because if there is a series of rigid transformations
that allow us to do it, then by the rigid
transformation definition the two triangles are congruent. So the first thing that we could do is we could reference back to where we saw that if we have two segments
that have the same length, like segment AB and segment DE. If we have two segments
with the same length that they are congruent. You can always map one
segment onto the other with a series of rigid transformations. The way that we could do that in this case is we could map point B onto point E. So this would be now I'll
put B prime right over here. And if we just did a
transformation to do that, if we just translated like that, then side, woops, then side B A would, that orange side would
be something like that. But then we could do
another rigid transformation that rotates about point E, or B prime, that rotates that orange side, and the whole triangle with it, onto DE. In which case, once we do that
second rigid transformation, point A will now coincide with D. Or we could say A prime is equal to D. But the question is,
where would C now sit? Well, we can see the
distance between A and C. In fact, we can use our compass for it. The distance between A
and C is just like that. And so since all of these rigid transformations
preserve distance, we know that C prime, the
point that C gets mapped to after those first two transformations. C prime it's distance is going to stay the same from A prime. So C prime is going to be some place, some place along this
curve right over here. We also know that the rigid transformations
preserve angle measures. And so we also know that
as we do the mapping, the angle will be preserved. So either side AC will be mapped to this side right over
here, and if that's the case then F would be equal to C prime, and we would have found
our rigid transformation based on SAS, and so therefore the two triangles would be congruent. But there's another possibility that the angle gets conserved, but side AC is mapped down here. So there's another
possibility that side AC, due to our rigid transformations, or after our first set
of rigid transformations, looks something like this. It looks something like that. In which case, C prime would
be mapped right over there. And in that case, we can just do one more
rigid transformation. We can just do a reflection about DE, or A prime B prime, to
reflect point C prime over that to get right over there. How do we know that C prime
would then be mapped to F? Well, this angle would be preserved due to the rigid transformation. So as we flip it over, as we
do the reflection over DE, the angle will be preserved. And A prime C prime will then map to DF. And then we'd be done. We have just shown that
there's always a series of rigid transformations, as long as you meet this SAS criteria, that can map one triangle onto the other. And therefore, they are congruent.