Algebra 1 (Eureka Math/EngageNY)
- Difference of squares intro
- Factoring quadratics: Difference of squares
- Difference of squares intro
- Perfect square factorization intro
- Factoring quadratics: Perfect squares
- Perfect squares intro
- Factoring quadratics as (x+a)(x+b)
- Factoring quadratics: leading coefficient = 1
- Factoring quadratics as (x+a)(x+b) (example 2)
- More examples of factoring quadratics as (x+a)(x+b)
- Warmup: factoring quadratics intro
- Factoring quadratics intro
Learn how to factor quadratics that have the "difference of squares" form. For example, write x²-16 as (x+4)(x-4).
Factoring a polynomial involves writing it as a product of two or more polynomials. It reverses the process of polynomial multiplication.
In this article, we'll learn how to use the difference of squares pattern to factor certain polynomials. If you don't know the difference of squares pattern, please check out our video before proceeding.
Intro: Difference of squares pattern
Every polynomial that is a difference of squares can be factored by applying the following formula:
Note that and in the pattern can be any algebraic expression. For example, for and , we get the following:
The polynomial is now expressed in factored form, . We can expand the right-hand side of this equation to justify the factorization:
Now that we understand the pattern, let's use it to factor a few more polynomials.
Example 1: Factoring
Both and are perfect squares, since and . In other words:
Since the two squares are being subtracted, we can see that this polynomial represents a difference of squares. We can use the difference of squares pattern to factor this expression:
In our case, and . Therefore, our polynomial factors as follows:
We can check our work by ensuring the product of these two factors is .
Check your understanding
1) Factor .
2) Factor .
3) Can we use the difference of squares pattern to factor ?
Example 2: Factoring
The leading coefficient does not have to equal to in order to use the difference of squares pattern. In fact, the difference of squares pattern can be used here!
This is because and are perfect squares, since and . We can use this information to factor the polynomial using the difference of squares pattern:
A quick multiplication check verifies our answer.
Check your understanding
4) Factor .
5) Factor .
6) Factor .
7*) Factor .
8*) Factor .
Want to join the conversation?
- If the question is x^2 + 25 its not factorable? Why?(5 votes)
- The difference of squares: (a+b)(a-b). x^2 + 25 is not factorable since you're adding 25, not subtracting. A positive multiplied by a negative is always a negative. If you were to factor it, you would have to use imaginary numbers such as i5. The factors of 25 are 5 and 5 besides 1 and itself. Since the formula: (a-b)(a+b), it uses a positive and negative sign, making the last term always a negative.(14 votes)
- Does the order of the signs matter? I have gotten it right when I do (x+y)(x-y). If I did it (x-y)(x+y) would it be wrong?(6 votes)
- i really don't understand factoring AT ALL even after watching the videos so can someone help me because i really suck at math! thank you in advance!(6 votes)
- Are you talking about just this video (difference of squares) or about any factoring at all? If it is factoring in general, you have to go through a sequence of factoring to support your learning. So just reaching out says that you are not as bad as you think. If you say all factoring, then we will start with a=1 and go one step at a time.(2 votes)
- in the video how did he know what number to divide by ?(5 votes)
- I think he looked for their square roots. Like when he had 25 5*5 = 25 so that's how he figured it out. Unless that's not what you're talking about then I feel embarrassed(3 votes)
- So when you have 25x-4 you have to make the 4 into a 2(3 votes)
- Yes, because the square root of 4 is 2. You should also notice the 25x^2. The square root of 25x^2 is 5x.(3 votes)
- Why can't we use the difference of squares pattern to factor x^2 + 25?(2 votes)
- First, let's write 𝑥² + 25 as a difference of squares.
𝑥² + 25 = 𝑥² − (−25) = 𝑥² − (√(−25))²
This would then factorize to (𝑥 − √(−25))(𝑥 + √(−25))
The problem is that there exists no real number 𝑎, such that 𝑎 = √(−25)
because squaring both sides gives us 𝑎² = −25 and the square of a real number cannot be negative.
– – –
The square roots of negative numbers are called imaginary numbers.
In and of themselves, imaginary numbers are quite pointless, but there are situations where they can prove useful.
For example, there is a formula for solving third-degree polynomial equations.
Using this formula, the calculations often require the use of imaginary numbers, even though the solutions in the end are real numbers.(3 votes)
- What's the deal with expanding from the two brackets where it goes (x+2)(x-2)=x(x-2)+2(x-2). I've never learnt this what type of property is it so that I can check it out, is it the distributive property?(1 vote)
- It is the distributive property. The (x-2) is being treated as one factors and multiplied with each term inside the first set of parentheses.(4 votes)
- Silly question, but do you ever get questions where you need to find difference of squares without perfect squares?(2 votes)
- You could at least theoretically do this x^2 - 3 = (x + sqrt(3))(x-sqrt(3)), but we often do not factor this way, but we might solve it other ways. Most of the time, it is referred to as the difference of perfect squares, not just the difference of squares.(2 votes)
- How would I solve for a question like xp^2-4x and give a number for x to make the binomial a difference of perfect squares?(1 vote)
- You aren't solving, you are factoring.
The first step you should always try when factoring is to look for a common factor. Your binomials has a common factor of X. Factor it out using the distributive property.
x (p^2 - 4)
You now have a binomial in the parentheses that is a difference of 2 squares. When you factor it, your factors become:
Hope this helps.(3 votes)