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Current time:0:00Total duration:1:42

CCSS.Math: , ,

whereas two factor the polynomial below is the product of two binomials and we have n times n minus one plus three times n minus one so I encourage you to pause this video and see if you can figure this out well the key is to realizing that both of these terms have n minus 1 as a factor let me just rewrite the whole thing so we can work on it down here so this is n times n minus 1 plus 3 times n minus 1 and notice both of them have an N minus 1 have an N minus 1 as a factor so what we could do is factor out the N minus 1 or you could you could view it as undistributing the N minus 1 and if we do that we're going to factor out the N minus 1 and what are we going to have left over well if you take out the N minus 1 here if you undistribute it out you're just going to be left with you are just going to be left with that n so you're going to have an end there and then for this second term you factor this n minus 1 out you're just going to be left with this positive 3 plus 3 and just like that we are done we have we have factored the polynomial below as a as a product of two binomials so this is the same thing as n minus 1 times n plus 3 and once again you can check this you can take this n minus 1 and distribute it n minus 1 times n is this term right over here n times n minus 1 and then n minus 1 times 3 is this term right over here n minus 1 times 3 or 3 times n minus 1